Difference between revisions of "User:Tohline/Apps/SMS"

From VistrailsWiki
Jump to navigation Jump to search
Line 119: Line 119:


===Expression for Adiabatic Exponent===
===Expression for Adiabatic Exponent===
====For any value of the ratio of specific heats====
From equation (2) of [http://adsabs.harvard.edu/abs/1941ApJ....94..124L Ledoux & Pekeris] (1941, ApJ, 94, 124) — see, for example, [[User:Tohline/SSC/Perturbations#Ledoux_and_Pekeris_.281941.29|our brief summary of this work]] — we see that when the total pressure is of the form being considered here, a general expression for the adiabatic exponent,
From equation (2) of [http://adsabs.harvard.edu/abs/1941ApJ....94..124L Ledoux & Pekeris] (1941, ApJ, 94, 124) — see, for example, [[User:Tohline/SSC/Perturbations#Ledoux_and_Pekeris_.281941.29|our brief summary of this work]] — we see that when the total pressure is of the form being considered here, a general expression for the adiabatic exponent,
<div align="center">
<div align="center">
Line 124: Line 125:
</div>
</div>
is,
is,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\Gamma_1</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\beta + \frac{(\gamma-1)(4-3\beta)^2}{\beta + 12(\gamma-1) (1 - \beta)} \, ,</math>
  </td>
</tr>
</table>
</div>
where, <math>~\gamma</math> is the ratio of specific heats associated with the ideal-gas component of the equation of state.  Notice that <math>~\beta = 1 </math> represents a situation where there is no radiation pressure.  In this limit the expression simplifies to,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\Gamma_1\biggr|_{\beta=1}</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\gamma \, ,</math>
  </td>
</tr>
</table>
</div>
which makes sense.  On the other hand, setting <math>~\beta = 0</math> represents the other extreme, where there is no ideal-gas contribution to the pressure.  In this case, we have,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\Gamma_1\biggr|_{\beta=0}</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\frac{16(\gamma-1)}{12(\gamma-1) } = \frac{4}{3} \, .</math>
  </td>
</tr>
</table>
</div>
====Used by BAC84====
On the other hand, without derivation BAC84 state (see their equation 4) that the adiabatic exponent is,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\Gamma_1</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\frac{4}{3} + \frac{4\sigma + 1}{3(\sigma+1)(8\sigma + 1)} \, .</math>
  </td>
</tr>
</table>
</div>
They also point out that, in the case where a system is dominated by radiation pressure, <math>~\sigma \gg 1</math>, and this expression becomes,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\Gamma_1\biggr|_{\sigma \gg 1}</math>
  </td>
  <td align="center">
<math>~\approx</math>
  </td>
  <td align="left">
<math>~\frac{4}{3} + \frac{1}{6\sigma} \, .</math>
  </td>
</tr>
</table>
</div>
Clearly, in the limit <math>~\sigma \rightarrow \infty</math>, this gives <math>~\Gamma_1 \rightarrow 4/3</math>, which, as it should, matches the limiting value obtained from the Ledoux &amp; Pekeris expression when <math>~\beta = 0</math>. 
BAC84 do not explicitly state what value of the ratio of specific heats they used in deriving their expression for the adiabatic exponent.  But this can be deduced by examining how their expression behaves in the limit of no radiation pressure, that is, for <math>~\sigma = 0</math>.
<!-- COMMENT OUT BRIEF SECTION
<div align="center">
<div align="center">
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
Line 181: Line 274:
</table>
</table>
</div>
</div>
END OF COMMENTED OUT SECTION -->





Revision as of 19:29, 19 December 2015

Rotating, Supermassive Stars

Whitworth's (1981) Isothermal Free-Energy Surface
|   Tiled Menu   |   Tables of Content   |  Banner Video   |  Tohline Home Page   |


Here we draw upon the work of J. R. Bond, W. D. Arnett, & B. J. Carr (1984, ApJ, 380, 825; hereafter BAC84) who were among the first to seriously address the question of the fate of very massive (stellar) objects.

Equation of State

Our discussion of the equation of state (EOS) that was used by BAC84 draws on the terminology that has already been adopted in our introductory discussion of supplemental relations and closely parallels our review of the properties of the envelope that E. A. Milne (1930, MNRAS, 91, 4) used to construct a bipolytropic sphere.

Expression for Total Pressure

Ignoring the component due to a degenerate electron gas, <math>~P_\mathrm{deg}</math>, the total gas pressure can be expressed as the sum of two separate components: a component of ideal gas pressure, and a component of radiation pressure. That is, in BAC84 the total pressure is given by the expression,

<math>~P</math>

<math>~=</math>

<math>~P_\mathrm{gas} + P_\mathrm{rad} \, ,</math>

where,

Ideal Gas Radiation

LSU Key.png

<math>~P_\mathrm{gas} = \frac{\Re}{\bar{\mu}} \rho T</math>

LSU Key.png

<math>~P_\mathrm{rad} = \frac{1}{3} a_\mathrm{rad} T^4</math>

Now, BAC84 define the rest-mass density in terms of the mean baryon mass, <math>~m_B</math>, via the expression, <math>~\rho = m_B n</math>, and write (see their equation 1),

<math>~P</math>

<math>~=</math>

<math>~Y_T n k T + \frac{1}{3}a_\mathrm{rad} T^4 \, .</math>

In converting from our notation to theirs we conclude, therefore, that,

<math>~\frac{\Re}{\bar{\mu}} (m_B n) T</math>

<math>~=</math>

<math>~Y_T n k T </math>

<math>~\Rightarrow ~~~~ Y_T </math>

<math>~=</math>

<math>~\frac{\Re}{k} \cdot \frac{m_B}{\bar{\mu}} \, .</math>

Ratio of Radiation Pressure to Gas Pressure

Following Milne (1930), we have defined the parameter, <math>~\beta</math>, as the ratio of gas pressure to total pressure. That is, in the context of BAC84, we have,

<math>\beta \equiv \frac{P_\mathrm{gas} }{P} \, ,</math>

in which case, also,

<math>\frac{P_\mathrm{rad}}{P} = 1-\beta </math>         and         <math>\frac{P_\mathrm{gas}}{P_\mathrm{rad}} = \frac{\beta}{1-\beta} \, .</math>

Using a different notation, BAC84 (see their equation 5) define <math>~\sigma</math> as the ratio of the radiation pressure to the gas pressure. Therefore, in converting from our notation to theirs we have,

<math>\sigma = \frac{1-\beta}{\beta} ~~~~\Rightarrow ~~~~ \beta = (1 + \sigma)^{-1} \, , </math>

as well as,

<math>\sigma = \frac{P_\mathrm{rad}}{P_\mathrm{gas}} = \frac{a_\mathrm{rad} T^3}{3} \cdot \frac{\bar\mu}{(\Re m_B)n} = \frac{a_\mathrm{rad} T^3}{3Y_T n k} \, ,</math>

which is precisely the definition provided in equation (5) of BAC84.

Expression for Adiabatic Exponent

For any value of the ratio of specific heats

From equation (2) of Ledoux & Pekeris (1941, ApJ, 94, 124) — see, for example, our brief summary of this work — we see that when the total pressure is of the form being considered here, a general expression for the adiabatic exponent,

<math>\Gamma_1 \equiv \frac{d\ln P}{d\ln\rho} \, ,</math>

is,

<math>~\Gamma_1</math>

<math>~=</math>

<math>~\beta + \frac{(\gamma-1)(4-3\beta)^2}{\beta + 12(\gamma-1) (1 - \beta)} \, ,</math>

where, <math>~\gamma</math> is the ratio of specific heats associated with the ideal-gas component of the equation of state. Notice that <math>~\beta = 1 </math> represents a situation where there is no radiation pressure. In this limit the expression simplifies to,

<math>~\Gamma_1\biggr|_{\beta=1}</math>

<math>~=</math>

<math>~\gamma \, ,</math>

which makes sense. On the other hand, setting <math>~\beta = 0</math> represents the other extreme, where there is no ideal-gas contribution to the pressure. In this case, we have,

<math>~\Gamma_1\biggr|_{\beta=0}</math>

<math>~=</math>

<math>~\frac{16(\gamma-1)}{12(\gamma-1) } = \frac{4}{3} \, .</math>

Used by BAC84

On the other hand, without derivation BAC84 state (see their equation 4) that the adiabatic exponent is,

<math>~\Gamma_1</math>

<math>~=</math>

<math>~\frac{4}{3} + \frac{4\sigma + 1}{3(\sigma+1)(8\sigma + 1)} \, .</math>

They also point out that, in the case where a system is dominated by radiation pressure, <math>~\sigma \gg 1</math>, and this expression becomes,

<math>~\Gamma_1\biggr|_{\sigma \gg 1}</math>

<math>~\approx</math>

<math>~\frac{4}{3} + \frac{1}{6\sigma} \, .</math>

Clearly, in the limit <math>~\sigma \rightarrow \infty</math>, this gives <math>~\Gamma_1 \rightarrow 4/3</math>, which, as it should, matches the limiting value obtained from the Ledoux & Pekeris expression when <math>~\beta = 0</math>.

BAC84 do not explicitly state what value of the ratio of specific heats they used in deriving their expression for the adiabatic exponent. But this can be deduced by examining how their expression behaves in the limit of no radiation pressure, that is, for <math>~\sigma = 0</math>.



Mass Normalization

Now, according to BAC84 (see their equation 8), when the total pressure is written in polytropic form — specifically, if we set,

<math>P = K\rho^{(1+1/n_p)} </math>

— the mass-scaling for relativistic configurations will depend on <math>~G</math>, <math>~c</math>, <math>~K</math>, and <math>~n_p</math> via the expression,

<math>~M_u = K^{n_p/2} G^{-3/2} c^{3-n_p} = \biggl( \frac{K}{G}\biggr)^{3/2} \biggl(\frac{K}{c^2}\biggr)^{(n_p-3)/2} \, .</math>


Polytropic Index Equals 3

Referencing our separate discussion of Milne's (1930) work, when <math>~n_p = 3</math>, the polytropic constant is related to the relevant set of physical parameters via the relation,

<math>~K_{3}</math>

<math>~=</math>

<math>~\biggl[ \biggl( \frac{\Re}{\bar\mu}\biggr)^4 \biggl(\frac{1-\beta}{\beta^4}\biggr) \frac{3}{a_\mathrm{rad}} \biggr]^{1/3} \, .</math>

Adopting the BAC84 terminology, this means that,

<math>~\biggl(\frac{K_{3}}{G}\biggr)^3</math>

<math>~=</math>

<math>~\biggl( \frac{\Re}{\bar\mu}\biggr)^4 \biggl[\frac{1-\beta}{\beta^4}\biggr] \frac{3}{G^3 a_\mathrm{rad}} </math>

 

<math>~=</math>

<math>~\biggl( \frac{k Y_T}{m_B}\biggr)^4 \biggl[\sigma^4(1+\sigma^{-1})^3\biggr] \frac{3}{G^3 a_\mathrm{rad}} </math>

<math>~\Rightarrow ~~~~ M_\mathrm{norm} \equiv \biggl(\frac{K_{3}}{G}\biggr)^{3/2}</math>

<math>~=</math>

<math>~(1+\sigma^{-1})^{3/2} \biggl( \frac{k Y_T}{m_B}\biggr)^2 \biggl(\frac{3}{G^3 a_\mathrm{rad}}\biggr)^{1/2} \sigma^2 </math>

 

<math>~\approx</math>

<math>~\biggl(1+\frac{3}{2\sigma} \biggr) \biggl( \frac{k Y_T}{m_B}\biggr)^2 \biggl(\frac{3}{G^3 a_\mathrm{rad}}\biggr)^{1/2} \sigma^2 \, .</math>

When radiation pressure significantly dominates over gas pressure — that is, in the limit <math>~\sigma \gg 1</math> — the leading factor is approximately unity, in which case we see that this expression for <math>~M_\mathrm{norm}</math> exactly matches the expression for <math>~M_{u,3}</math> given by equation (10) of BAC84.

Polytropic Index Slightly Less Than 3

More generally, equating the two expressions for the total pressure and drawing (twice) on the expression for <math>~\sigma</math> provided above, we have,

<math>~K\rho^{(1 + 1/n_p)}</math>

<math>~=</math>

<math>~Y_T n k T + \frac{a_\mathrm{rad}}{3} T^4 </math>

 

<math>~=</math>

<math>~\frac{a_\mathrm{rad}}{3} (1+\sigma^{-1})T^4 </math>

 

<math>~=</math>

<math>~\frac{a_\mathrm{rad}}{3} (1+\sigma^{-1})\biggl[ \frac{3Y_T n k \sigma}{a_\mathrm{rad}} \biggr]^{4/3} </math>

 

<math>~=</math>

<math>~\biggl( \frac{3}{a_\mathrm{rad}} \biggr)^{1/3}(1+\sigma^{-1})\biggl[ Y_T n k \sigma \biggr]^{4/3} \, .</math>

Now, from above we have,

<math>~1 + \frac{1}{n_p} = \Gamma</math>

<math>~\approx</math>

<math>~\frac{4}{3} + \frac{1}{6\sigma} \, ,</math>

so the lefthand-side of this last expression can be written as,

<math>~K\rho^{(1+1/n_p)}</math>

<math>~\approx</math>

<math>~K\rho^{(4/3+1/6\sigma)} = K(m_B n)^{4/3} \rho^{1/6\sigma} \, .</math>

This means that, for any <math>~\sigma \gg 1</math>,

<math>~K </math>

<math>~\approx</math>

<math>~\biggl( \frac{3}{a_\mathrm{rad}} \biggr)^{1/3} \biggl( \frac{Y_T k \sigma}{m_B} \biggr)^{4/3} (1+\sigma^{-1}) \rho^{-1/6\sigma} \, .</math>

This matches exactly expression (7) in BAC84. Again from above — and continuing to assume <math>~\sigma \gg 1</math> — we have,

<math>~1 + \frac{1}{n_p} \approx \frac{4}{3} + \frac{1}{6\sigma} </math>

      <math>~~~~\Rightarrow ~~~~</math>     

<math>~\frac{1}{n_p} \approx \frac{1}{3}\biggl(1 + \frac{1}{2\sigma}\biggr) </math>

 

      <math>~~~~\Rightarrow ~~~~</math>     

<math>~n_p \approx 3\biggl(1 + \frac{1}{2\sigma}\biggr)^{-1} \approx 3\biggl(1 - \frac{1}{2\sigma}\biggr)</math>

 

      <math>~~~~\Rightarrow ~~~~</math>     

<math>~\frac{(n_p-3)}{2} \approx - \frac{3}{4\sigma} \, .</math>

Hence, when the polytropic index is slightly less than 3, the mass normalization is,

<math>~M_u</math>

<math>~\approx</math>

<math>~\biggl( \frac{K}{G}\biggr)^{3/2} \biggl(\frac{K}{c^2}\biggr)^{-3/4\sigma}</math>

 

<math>~=</math>

<math>~\biggl[\frac{1}{G} \biggl( \frac{3}{a_\mathrm{rad}} \biggr)^{1/3} \biggl( \frac{Y_T k \sigma}{m_B} \biggr)^{4/3} (1+\sigma^{-1}) \rho^{-1/6\sigma} \biggr]^{3/2} \biggl[\frac{1}{c^2} \biggl( \frac{3}{a_\mathrm{rad}} \biggr)^{1/3} \biggl( \frac{Y_T k \sigma}{m_B} \biggr)^{4/3} (1+\sigma^{-1}) \rho^{-1/6\sigma} \biggr]^{-3/4\sigma} </math>

 

<math>~=</math>

<math>~\biggl[\biggl( \frac{3}{G^3 a_\mathrm{rad}} \biggr)^{1/2} \biggl( \frac{Y_T k }{m_B} \biggr)^{2} (1+\sigma^{-1})^{3/2} \sigma^2 \biggr] \rho^{-1/4\sigma} \biggl[\frac{1}{c^2} \biggl( \frac{3}{a_\mathrm{rad}} \biggr)^{1/3} \biggl( \frac{Y_T k \sigma}{m_B} \biggr)^{4/3} (1+\sigma^{-1}) \rho^{-1/6\sigma} \biggr]^{-3/4\sigma} </math>

 

<math>~=</math>

<math>~\biggl[M_\mathrm{norm} \biggr] \biggl\{\frac{1}{c^2} \biggl( \frac{3}{a_\mathrm{rad}} \biggr)^{1/3} \biggl( \frac{Y_T k \sigma}{m_B} \biggr)^{4/3} (m_B n)^{1/3} \biggl[(1+\sigma^{-1}) \rho^{-1/6\sigma} \biggr] \biggr\}^{-3/4\sigma} </math>

Drawing again from the definition of <math>~\sigma</math> provided above, we have,

<math>~\biggl(\frac{3}{a_\mathrm{rad}}\biggr)^{1/3}</math>

<math>~=</math>

<math>~T (\sigma Y_T n k)^{-1/3} \, ,</math>

so this last relation can be rewritten as,

<math>~M_u</math>

<math>~\approx</math>

<math>~ M_\mathrm{norm} \cdot f \biggl[\frac{m_B c^2}{T \sigma Y_T k} \biggr]^{3/4\sigma} \approx f \cdot M_{u,3} \biggl(1+\frac{3}{2\sigma} \biggr) \biggl[\frac{m_B c^2}{T \sigma Y_T k} \biggr]^{3/4\sigma} \, ,</math>

where,

<math>f \equiv \biggl[(1+\sigma^{-1})^{-1}\rho^{1/6\sigma} \biggr]^{3/4\sigma} \approx \biggl( 1 - \frac{3}{4\sigma^2}\biggr) (n m_B)^{1/8\sigma^2}\, ,</math>

which certainly is close to unity when <math>~\sigma \gg 1</math>. After setting <math>~f=1</math>, this last expression for <math>~M_u</math> exactly matches the expression presented as equation (9) in BAC84.


Whitworth's (1981) Isothermal Free-Energy Surface

© 2014 - 2021 by Joel E. Tohline
|   H_Book Home   |   YouTube   |
Appendices: | Equations | Variables | References | Ramblings | Images | myphys.lsu | ADS |
Recommended citation:   Tohline, Joel E. (2021), The Structure, Stability, & Dynamics of Self-Gravitating Fluids, a (MediaWiki-based) Vistrails.org publication, https://www.vistrails.org/index.php/User:Tohline/citation