User:Tohline/Appendix/CGH/ParallelAperturesConsolidate

CGH: Consolidate Expressions Regarding Parallel Apertures

One-dimensional Apertures

From our accompanying discussion of the Utility of FFT Techniques, we start with the most general expression for the amplitude at one point on an image screen, namely,

<math>~A(y_1)</math>

<math>~=</math>

<math>~\sum_j a_j e^{i(2\pi D_j/\lambda + \phi_j)} \, , </math>

and, assuming that <math>~|Y_j/L| \ll 1</math> for all <math>~j</math>, deduce that,

<math>~A(y_1)</math>

<math>~\approx</math>

<math>~\sum_j a_j e^{i[ 2\pi L/\lambda + \phi_j]}\biggl[ \cos\biggl(\frac{2\pi y_1 Y_j}{\lambda L} \biggr) - i \sin\biggl(\frac{2\pi y_1 Y_j}{\lambda L} \biggr) \biggr] \, , </math>

where,

<math>~L</math>

<math>~\equiv</math>

<math>~ Z \biggl[1 + \frac{y_1^2}{Z^2} \biggr]^{1 / 2} \, . </math>

Note that <math>~L</math> is formally a function of <math>~y_1</math>, but in most of what follows it will be reasonable to assume, <math>~L \approx Z</math>. Notice, as well, that this last approximate expression for the (complex) amplitude at the image screen may be rewritten in the form that will be referred to as our,

Focal-Point Expression
<math>~A(y_1)</math>	<math>~\approx</math>	<math>~ e^{i 2\pi L/\lambda } \sum_j a_j e^{i \phi_j} \cdot e^{-i \Theta_j } \, , </math>

where,

<math>~\Theta_j</math>

<math>~\equiv</math>

<math>~\biggl(\frac{2\pi y_1 Y_j}{\lambda L} \biggr) \, .</math>

Case 1

In a related accompanying derivation titled, Analytic Result, we made the substitution,

<math>~a_j </math>

<math>~\rightarrow</math>

<math>~a_0(Y) dY = a_0(\Theta) \biggl[ \frac{w}{2\beta_1} \biggr] d\Theta \, ,</math>

where,

<math>~\frac{1}{\beta_1}</math>

<math>~\equiv</math>

<math>~\frac{\lambda L}{\pi y_1w} \, ,</math>

and changed the summation to an integration, obtaining,

<math>~A(y_1)</math>

<math>~\approx</math>

<math>~ e^{i 2\pi L/\lambda }\biggl[ \frac{w}{2\beta_1} \biggr] \int a_0(\Theta) e^{i\phi(\Theta)} \cdot e^{-i \Theta } d\Theta \, . </math>

If we assume that both <math>~a_0</math> and <math>~\phi</math> are independent of position along the aperture, and that the aperture — and, hence the integration — extends from <math>~Y_2 = -w/2</math> to <math>~Y_1 = +w/2</math>, we have shown that this last expression can be evaluated analytically to give,

<math>~A(y_1)</math>	<math>~\approx</math>	<math>~ e^{i [2\pi L/\lambda + \phi] }\biggl[ \frac{a_0 w}{2\beta_1} \biggr] \int_{\Theta_2}^{\Theta_1} e^{-i \Theta } d\Theta </math>
	<math>~=</math>	<math>~ e^{i [2\pi L/\lambda + \phi] } \cdot a_0 w ~\mathrm{sinc}(\beta_1) \, . </math>

We need to explicitly demonstrate that an evaluation of our Focal-Point Expression with <math>~a_j = 1</math>, gives this last sinc-function expression, to within a multiplicative factor of, something like, <math>~j_\mathrm{max}</math>.

Case 2

In our accompanying discussion of the Fourier Series, we have shown that a square wave can be constructed from the expression,

<math>~f(x)</math>	<math>~=</math>	<math>~ \frac{c}{L} + \sum_{n=1}^{\infty} \biggl( \frac{2}{n\pi} \biggr) \sin \biggl( \frac{n\pi c}{L} \biggr) \cos \biggl(\frac{n\pi x}{L}\biggr) </math>
	<math>~=</math>	<math>~ \frac{2c}{L}\biggl\{\frac{1}{2} + \sum_{n=1}^{\infty} \mathrm{sinc} \biggl( \frac{n\pi c}{L} \biggr) \cos \biggl(\frac{n\pi x}{L}\biggr) \biggr\} \, . </math>

Can we make this look like our above, Focal-Point Expression?

Let's start by setting

<math>~Y_j</math>

<math>~=</math>

<math>~\frac{j\cdot w}{(j_\mathrm{max}-1)} - \frac{w}{2} \, ,</math>

for <math>~0 \le j \le (j_\mathrm{max}-1)</math>, in which case,

<math>~\Theta_j</math>	<math>~\equiv</math>	<math>~ \frac{2\pi y_1}{\lambda L} \biggl[ \frac{j\cdot w}{(j_\mathrm{max}-1)} - \frac{w}{2} \biggr] = \frac{2\pi y_1}{\lambda L} \biggl[ \frac{j\cdot w}{(j_\mathrm{max}-1)} \biggr] - \frac{2\pi y_1}{\lambda L} \biggl[ \frac{w}{2} \biggr] </math>
	<math>~=</math>	<math>~ j \biggl[ \frac{2\pi y_1 w}{(j_\mathrm{max}-1) \lambda L} \biggr] - \frac{\pi y_1 w }{\lambda L} = \biggl( \frac{2j}{j_\mathrm{max} - 1} - 1 \biggr) \frac{\pi y_1 w }{\lambda L} \, ,</math>
	<math>~=</math>	<math>~ j \cdot \Delta\Theta - \frac{(j_\mathrm{max} -1)}{2} \Delta\Theta \, ,</math>

where,

<math>~\Delta\Theta \equiv \frac{\pi y_1}{\mathfrak{L}} \, ,</math>     and     <math>~\mathfrak{L} \equiv \biggl[ \frac{(j_\mathrm{max}-1) \lambda L}{2w} \biggr] \, .</math>

This means that <math>~\Theta_{i} = - \Theta_{( j_\mathrm{max} - 1 - i )}</math>.

The key expression under the summation therefore becomes,

<math>~a_j e^{i \phi_j} \cdot e^{-i \Theta_j } </math>

<math>~=</math>

<math>~~a_j e^{i \phi_j} \cdot \biggl[ \cos \biggl( \frac{j\pi y_1}{\mathfrak{L}}- \Theta_0 \biggr) - i \sin \biggl( \frac{j\pi y_1}{\mathfrak{L}}- \Theta_0 \biggr) \biggr] \, ,</math>

where,

<math>~\Theta_0 \equiv \frac{(j_\mathrm{max} - 1)}{2} \cdot \pi y_1 \biggl[ \frac{2w}{(j_\mathrm{max}-1) \lambda L} \biggr] = \frac{\pi y_1 w}{\lambda L} \, .</math>

Now, what is the argument of the sinc function? By default, it needs to be something along the lines of,

<math>~\frac{j \pi c}{\mathfrak{L}}</math>

<math>~=</math>

<math>~j \pi c \biggl[ \frac{2w}{(j_\mathrm{max}-1) \lambda L} \biggr] \, .</math>

Then, as <math>~j</math> varies from <math>~0</math> to <math>~(j_\mathrm{max} - 1)</math>, the argument goes from <math>~0</math> to <math>~[2\pi w c/(\lambda L)]</math>. In an effort to make the function exhibit reflection symmetry as we move from one side of the aperture to the next, let's subtract half of this upper limit; that is, let's modify the argument of the sinc function to read,

<math>~\frac{j \pi c}{\mathfrak{L}} - \frac{\pi w c}{\lambda L}</math>

<math>~=</math>

<math>~ j \pi c \biggl[ \frac{2w}{(j_\mathrm{max}-1) \lambda L} \biggr] - \frac{\pi w c}{\lambda L} = \biggl[ \frac{2j}{j_\mathrm{max}-1} - 1\biggr]\biggl[ \frac{\pi w c}{\lambda L} \biggr] \, . </math>

This means that in our above, Focal-Point Expression we want to set,

<math>~a_j</math>

<math>~=</math>

<math>~ \mathrm{sinc} \biggl[ \biggl( \frac{2j}{j_\mathrm{max}-1} - 1 \biggr) \frac{\pi w c}{\lambda L} \biggr] \, . </math>

This therefore gives the following,

Focal-Point Expression for a Square Wave
<math>~A(y_1)</math>	<math>~\approx</math>	<math>~ e^{i 2\pi L/\lambda } \sum_{j=0}^{j_\mathrm{max}-1} e^{i \phi_j} \cdot~ \mathrm{sinc} \biggl[ \biggl( \frac{2j}{j_\mathrm{max}-1} - 1 \biggr) \frac{\pi w c}{\lambda L} \biggr] \biggl\{ \cos \biggl[ \biggl( \frac{2j}{j_\mathrm{max} - 1} - 1 \biggr) \frac{\pi y_1 w }{\lambda L} \biggr] - i \sin \biggl[ \biggl( \frac{2j}{j_\mathrm{max} - 1} - 1 \biggr) \frac{\pi y_1 w }{\lambda L} \biggr] \biggr\} \, . </math>

This exhibits a very desirable feature: Both the sinc function and the sine function — and, hence, also their product — have reflection symmetry about the summation index, <math>~j = (j_\mathrm{max}-1)/2</math>. As a result, if the overall phase factor, <math>~e^{i \phi_j}</math>, behaves in an appropriately simple way — for example, if it is zero everywhere — then under the summation the sine term will sum to zero and leave only the desired — and real — product, <math>~\mathrm{sinc} \times \cos</math>. Try this out in Excel to see if it works!

This could use a little more manipulation. Let's define the alternate summation index,

<math>~n</math>

<math>~\equiv</math>

<math>\frac{1}{2} \biggl[ j_\mathrm{max}-1 \biggr] \biggl( \frac{2j}{j_\mathrm{max}-1} - 1 \biggr) \, ,</math>

in which case we can write,

<math>~A(y_1)</math>	<math>~\approx</math>	<math>~ e^{i 2\pi L/\lambda } \sum_{n~=~-(j_\mathrm{max} - 1)/2}^{+(j_\mathrm{max} - 1)/2} e^{i \phi_j} \cdot~ \mathrm{sinc} \biggl[ \biggl( \frac{2n}{ j_\mathrm{max}-1} \biggr) \frac{\pi w c}{\lambda L} \biggr] \biggl\{ \cos \biggl[ \biggl( \frac{2n}{ j_\mathrm{max}-1} \biggr) \frac{\pi y_1 w }{\lambda L} \biggr] - i \sin \biggl[ \biggl( \frac{2n}{ j_\mathrm{max}-1} \biggr) \frac{\pi y_1 w }{\lambda L} \biggr] \biggr\} </math>
	<math>~=</math>	<math>~ e^{i 2\pi L/\lambda } e^{i \phi_{j=0} } ~+~e^{i 2\pi L/\lambda } \sum_{n~=~1}^{+(j_\mathrm{max} - 1)/2} 2e^{i \phi_j} \cdot~ \mathrm{sinc} \biggl[ \biggl( \frac{2n}{ j_\mathrm{max}-1} \biggr) \frac{\pi w c}{\lambda L} \biggr] ~ \cos \biggl[ \biggl( \frac{2n}{ j_\mathrm{max}-1} \biggr) \frac{\pi y_1 w }{\lambda L} \biggr] </math>
	<math>~=</math>	<math>~ e^{i 2\pi L/\lambda } e^{i \phi_{j=0} } ~+~e^{i 2\pi L/\lambda } \sum_{n~=~1}^{+(j_\mathrm{max} - 1)/2} 2e^{i \phi_j} \cdot~ \mathrm{sinc} \biggl(\frac{\pi n c}{\mathfrak{L} } \biggr) ~ \cos \biggl( \frac{n \pi y_1 }{\mathfrak{L} } \biggr) </math>
	<math>~=</math>	<math>~ e^{i 2\pi L/\lambda } \biggl(\frac{\mathfrak{L}}{c} \biggr) \biggl\{ e^{i \phi_{j=0} } \biggl(\frac{c}{\mathfrak{L}} \biggr) ~+~ \sum_{n~=~1}^{+(j_\mathrm{max} - 1)/2} e^{i \phi_j} \cdot~ \biggl(\frac{ 2 }{\pi n } \biggr) \sin \biggl(\frac{\pi n c}{\mathfrak{L} } \biggr) ~ \cos \biggl( \frac{n \pi y_1 }{\mathfrak{L} } \biggr) \biggr\} \, . </math>

Finally, recalling that,

<math>~L</math>

<math>~\equiv</math>

<math>~ Z \biggl[1 + \frac{y_1^2}{Z^2} \biggr]^{1 / 2} \approx Z \biggl[1 + \frac{1}{2}\frac{y_1^2}{Z^2} \biggr] = Z + \frac{y_1^2}{2Z} \, , </math>

let's set …

<math>~e^{i\phi_j}</math>	<math>~=</math>	<math>~ e^{-i2\pi Z/\lambda} </math>
<math>~\Rightarrow ~~~ e^{i2\pi L/\lambda} \cdot e^{i\phi_j}</math>	<math>~=</math>	<math>~ e^{i2\pi (L-Z)/\lambda} \approx e^{i\pi y_1^2/(\lambda Z)} = \cos\biggl( \frac{\pi y_1^2}{\lambda Z} \biggr) + i \sin \biggl( \frac{\pi y_1^2}{\lambda Z} \biggr) \, . </math>

As a result, we have,

<math>~A(y_1)</math>

<math>~\approx</math>

<math>~ \biggl[ \cos\biggl( \frac{\pi y_1^2}{\lambda Z} \biggr) + i \sin \biggl( \frac{\pi y_1^2}{\lambda Z} \biggr) \biggr] \biggl(\frac{\mathfrak{L}}{c} \biggr) \biggl\{ \biggl(\frac{c}{\mathfrak{L}} \biggr) ~+~ \sum_{n~=~1}^{+(j_\mathrm{max} - 1)/2} \biggl(\frac{ 2 }{\pi n } \biggr) \sin \biggl(\frac{\pi n c}{\mathfrak{L} } \biggr) ~ \cos \biggl( \frac{n \pi y_1 }{\mathfrak{L} } \biggr) \biggr\} \, . </math>

Therefore, a clean square wave will appear only if <math>~[\pi y_1^2/(\lambda Z)] \ll 1</math>.

See Also

• Updated Table of Contents
• Tohline, J. E., (2008) Computing in Science & Engineering, vol. 10, no. 4, pp. 84-85 — Where is My Digital Holographic Display? [ PDF ]
• Diffraction (Wikipedia)
• Various Google hits:
  • Single Slit Diffraction (University of Tennessee, Knoxville)
  • Diffraction from a Single Slit; Young's Experiment with Finite Slits (University of New South Wales, Sydney, Australia)
  • Single Slit Diffraction Pattern of Light (University of British Columbia, Canada)
  • Fraunhofer Single Slit (Georgia State University)

© 2014 - 2021 by Joel E. Tohline |   H_Book Home   |   YouTube   | Appendices: | Equations | Variables | References | Ramblings | Images | myphys.lsu | ADS | Recommended citation:   Tohline, Joel E. (2021), The Structure, Stability, & Dynamics of Self-Gravitating Fluids, a (MediaWiki-based) Vistrails.org publication, https://www.vistrails.org/index.php/User:Tohline/citation