Difference between revisions of "User:Tohline/Apps/Blaes85SlimLimit"

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(→‎Statement of the Eigenvalue Problem: Finished deriving equation 3.9 from Blaes85)
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<math>~\Rightarrow</math> &nbsp; &nbsp; &nbsp;  
<math>~\Rightarrow</math> &nbsp; &nbsp; &nbsp;  
<math>~dy = 2\eta d\eta</math> &nbsp; &nbsp; &nbsp;
<math>~dy = 2\eta d\eta</math> &nbsp; &nbsp; &nbsp;
<math>~\Rightarrow</math> &nbsp; &nbsp; &nbsp;
<math> ~~ </math>&nbsp; &nbsp; &nbsp; and &nbsp; &nbsp; &nbsp;
<math>\frac{d^2}{d\eta^2} ~\rightarrow~ 2y^{1/2}\frac{d}{dy}</math>
</div>
</div>
in which case,
in which case,
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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~4y^{1/2}\frac{d}{dy} + 4y^{3/2}\frac{d^2}{dy^2}</math>
<math>~2\frac{d}{dy} + 4y\frac{d^2}{dy^2} \, .</math>
   </td>
   </td>
</tr>
</tr>
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   <td align="left">
   <td align="left">
<math>~
<math>~
(1-y)y \biggl[ 4y^{1/2}\frac{d\Upsilon}{dy} + 4y^{3/2}\frac{d^2\Upsilon}{dy^2}\biggr] + 2(2|k|+1)(1-y)y \frac{d\Upsilon}{dy}  
(1-y) y \frac{d^2\Upsilon}{d\eta^2} + (2|k|+1)(1-y)y^{1/2} \frac{d\Upsilon}{d\eta}  
- \biggl[ 4 n y^{2}  \frac{d\Upsilon}{dy} \biggr]
- 2 n y^{3/2} \frac{d\Upsilon}{d\eta}
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
4(1-y)y^2 \frac{d^2\Upsilon}{dy^2} + 2(1-y) y \frac{d\Upsilon}{dy} + 2(2|k|+1)(1-y)y \frac{d\Upsilon}{dy}  
- 4 n y^{2}  \frac{d\Upsilon}{dy}
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~\Rightarrow~~~~
- \frac{n}{2}\biggl[\biggl( \frac{\sigma}{\Omega_0} + m  \biggr)^2 -|k|\biggr]  \Upsilon
</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
(1-y)y \frac{d^2\Upsilon}{dy^2} + \frac{1}{2}(1-y) \frac{d\Upsilon}{dy} + \frac{1}{2}(2|k|+1)(1-y)\frac{d\Upsilon}{dy}
- n y \frac{d\Upsilon}{dy}
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
(1-y)y \frac{d^2\Upsilon}{dy^2} + (|k|+1)(1-y)\frac{d\Upsilon}{dy}
- n y \frac{d\Upsilon}{dy}  
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
(1-y)y \frac{d^2\Upsilon}{dy^2} + (|k|+1)\frac{d\Upsilon}{dy} -y (|k|+1+n)\frac{d\Upsilon}{dy} \, .
</math>
</math>
   </td>
   </td>
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</table>
</table>
</div>
</div>
This matches equation (3.9) of Blaes85.


=See Also=
=See Also=

Revision as of 01:51, 4 May 2016


Stability of PP Tori in the Slim Torus Limit

Whitworth's (1981) Isothermal Free-Energy Surface
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Statement of the Eigenvalue Problem

Here, we build on our discussion in an accompanying chapter in which five published analyses of nonaxisymmetric instabilities in Papaloizou-Pringle tori were reviewed: The discovery paper, PP84, and papers by four separate groups that were published within a couple of years of the discovery paper — Papaloizou & Pringle (1985), Blaes (1985), Kojima (1986), and Goldreich, Goodman & Narayan (1986). Following the lead of Blaes (1985; hereafter Blaes85), in particular, we have shown that the relevant eigenvalue problem is defined by the following 2nd-order PDE,

<math>~0</math>

<math>~=</math>

<math>~ \eta^2 (1-\eta^2)\cdot \frac{\partial^2(\delta W)^{(0)}}{\partial \eta^2} + (1-\eta^2) \cdot \frac{\partial^2(\delta W)^{(0)}}{\partial\theta^2} + \biggl[ \eta (1-\eta^2) -2 n \eta^3 \biggr] \cdot \frac{\partial (\delta W)^{(0)}}{\partial \eta} + 2n\eta^2 \biggl( \frac{\sigma}{\Omega_0} + m \biggr)^2 (\delta W)^{(0)} \, , </math>

where, <math>~\delta W^{(0)}</math> is the dimensionless enthalpy perturbation. Making the substitution,

<math>~\delta W^{(0)} ~\rightarrow~ V(\eta) \exp (ik\theta) \, ,</math>

this governing equation — now, a one-dimensional, 2nd-order ODE — becomes,

<math>~0</math>

<math>~=</math>

<math>~ \eta^2 (1-\eta^2)\cdot \frac{d^2V}{d \eta^2} - k^2(1-\eta^2) V + \biggl[ \eta (1-\eta^2) -2 n \eta^3 \biggr] \cdot \frac{d V}{d \eta} + 2n\eta^2 \biggl( \frac{\sigma}{\Omega_0} + m \biggr)^2 V \, . </math>

Making the additional substitution,

<math>~V ~\rightarrow~ \eta^{|k|} \Upsilon(\eta) \, ,</math>

and appreciating that,

<math>~\frac{dV}{d\eta}</math>

<math>~=</math>

<math>~|k|\eta^{|k|-1} \Upsilon + \eta^{|k|} \frac{d\Upsilon}{d\eta} \, ,</math>

<math>~\frac{d^2V}{d\eta^2}</math>

<math>~=</math>

<math>~ |k|[|k|-1] \eta^{|k|-2}\Upsilon + 2|k|\eta^{|k|-1} \frac{d\Upsilon}{d\eta} + \eta^{|k|} \frac{d^2\Upsilon}{d\eta^2}\, ,</math>

the governing ODE becomes,

<math>~ \biggl\{k^2(1-\eta^2) - 2n\eta^2 \biggl( \frac{\sigma}{\Omega_0} + m \biggr)^2\biggr\} \eta^{|k|}\Upsilon </math>

<math>~=</math>

<math>~ \eta^2 (1-\eta^2)\cdot \biggl[ |k|[|k|-1] \eta^{|k|-2}\Upsilon + 2|k|\eta^{|k|-1} \frac{d\Upsilon}{d\eta} + \eta^{|k|} \frac{d^2\Upsilon}{d\eta^2}

\biggr]

+ \biggl[ \eta (1-\eta^2) -2 n \eta^3 \biggr] \cdot \biggl[ |k|\eta^{|k|-1} \Upsilon + \eta^{|k|} \frac{d\Upsilon}{d\eta} \biggr] </math>

 

<math>~=</math>

<math>~(1-\eta^2) \biggl[ |k|[|k|-1] \eta^{|k|}\Upsilon + 2|k|\eta^{|k|+1} \frac{d\Upsilon}{d\eta} + \eta^{|k|+2} \frac{d^2\Upsilon}{d\eta^2}\biggr] + \biggl[ (1-\eta^2) -2 n \eta^2 \biggr] \cdot \biggl[ |k|\eta^{|k|} \Upsilon + \eta^{|k|+1} \frac{d\Upsilon}{d\eta} \biggr] </math>

 

<math>~=</math>

<math>~\eta^{|k|}(1-\eta^2) \biggl[ k^2 \Upsilon + (2|k|+1)\eta \frac{d\Upsilon}{d\eta} + \eta^{2} \frac{d^2\Upsilon}{d\eta^2} \biggr] - \eta^{|k|}\biggl[ 2 n \eta^2 \biggr] \cdot \biggl[ |k| \Upsilon + \eta \frac{d\Upsilon}{d\eta} \biggr] </math>

<math>~\Rightarrow~~~ - 2n\eta^2 \biggl[\biggl( \frac{\sigma}{\Omega_0} + m \biggr)^2 -|k|\biggr] \Upsilon </math>

<math>~=</math>

<math>~(1-\eta^2) \biggl[ \eta^{2} \frac{d^2\Upsilon}{d\eta^2} + (2|k|+1)\eta \frac{d\Upsilon}{d\eta} \biggr] - \biggl[ 2 n \eta^3 \frac{d\Upsilon}{d\eta} \biggr] \, . </math>


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Finally, then, making the independent variable substitution,

<math>~\eta^2 ~\rightarrow ~ y</math>       <math>~\Rightarrow</math>       <math>~dy = 2\eta d\eta</math>      

in which case,

<math>~\frac{d}{d\eta}</math>

<math>~\rightarrow</math>

<math>~2y^{1/2}\frac{d}{dy}</math>

<math>~\frac{d^2}{d\eta^2}</math>

<math>~\rightarrow</math>

<math>~2\frac{d}{dy} + 4y\frac{d^2}{dy^2} \, .</math>

and,

<math>~ - 2ny \biggl[\biggl( \frac{\sigma}{\Omega_0} + m \biggr)^2 -|k|\biggr] \Upsilon </math>

<math>~=</math>

<math>~ (1-y) y \frac{d^2\Upsilon}{d\eta^2} + (2|k|+1)(1-y)y^{1/2} \frac{d\Upsilon}{d\eta} - 2 n y^{3/2} \frac{d\Upsilon}{d\eta} </math>

 

<math>~=</math>

<math>~ 4(1-y)y^2 \frac{d^2\Upsilon}{dy^2} + 2(1-y) y \frac{d\Upsilon}{dy} + 2(2|k|+1)(1-y)y \frac{d\Upsilon}{dy} - 4 n y^{2} \frac{d\Upsilon}{dy} </math>

<math>~\Rightarrow~~~~ - \frac{n}{2}\biggl[\biggl( \frac{\sigma}{\Omega_0} + m \biggr)^2 -|k|\biggr] \Upsilon </math>

<math>~=</math>

<math>~ (1-y)y \frac{d^2\Upsilon}{dy^2} + \frac{1}{2}(1-y) \frac{d\Upsilon}{dy} + \frac{1}{2}(2|k|+1)(1-y)\frac{d\Upsilon}{dy} - n y \frac{d\Upsilon}{dy} </math>

 

<math>~=</math>

<math>~ (1-y)y \frac{d^2\Upsilon}{dy^2} + (|k|+1)(1-y)\frac{d\Upsilon}{dy} - n y \frac{d\Upsilon}{dy} </math>

 

<math>~=</math>

<math>~ (1-y)y \frac{d^2\Upsilon}{dy^2} + (|k|+1)\frac{d\Upsilon}{dy} -y (|k|+1+n)\frac{d\Upsilon}{dy} \, . </math>

This matches equation (3.9) of Blaes85.

See Also

Whitworth's (1981) Isothermal Free-Energy Surface

© 2014 - 2021 by Joel E. Tohline
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