Difference between revisions of "User:Tohline/Appendix/Ramblings/Bordeaux"

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=Universit&eacute; de Bordeaux=
=Universit&eacute; de Bordeaux (Part 1)=


{{LSU_HBook_header}}
{{LSU_HBook_header}}
==Spheroid-Ring Systems==
Through a research collaboration at the [https://www.u-bordeaux.com Universit&eacute; de Bordeaux], [https://ui.adsabs.harvard.edu/abs/2019MNRAS.487.4504B/abstract B. Basillais &amp; J. -M. Hur&eacute; (2019), MNRAS, 487, 4504-4509] have published a paper titled, ''Rigidly Rotating, Incompressible Spheroid-Ring Systems:  New Bifurcations, Critical Rotations, and Degenerate States.''
We discuss this topic in a [[User:Tohline/Appendix/Ramblings/BordeauxSequences#Spheroid-Ring_Systems|separate, accompanying chapter]].


==Exterior Gravitational Potential of Toroids==
==Exterior Gravitational Potential of Toroids==
Line 4,750: Line 4,755:
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~2^4e^4(1 - 4x + 10 x^2 - 20x^3 + 35x^4 - 56x^5 + \cdots) \, .</math>
<math>~2^4e^4(1 - 4e + 10 e^2 - 20e^3 + 35e^4 - 56e^5 + \cdots) \, .</math>
   </td>
   </td>
</tr>
</tr>
Line 5,069: Line 5,074:
   </td>
   </td>
</tr>
</tr>
<tr><td align="center" colspan="3"><font color="red">'''TEMPORARY BREAK'''</font></td></tr>


<tr>
<tr>
Line 5,081: Line 5,084:
   <td align="left">
   <td align="left">
<math>~
<math>~
2^{-9}\biggl[
2^{-9} \biggl[  
(- 192+ 128 - 448)e^2   
(- 192+ 128 - 448)e^2  + 2048 e^2
+ (- 192 + 448) e^3
+ (1285 + 78- 51)e^4
+ (1285 + 78- 51)e^4
+ (192+ 448) e^4 
+ 128e^4
+ \mathcal{O}(e^{5})  
+ \mathcal{O}(e^{5})  
\biggr]
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 2^{-9} e \biggl[
1024e + (192- 448)e^2 
+ (192+ 448) e^3 
+ \mathcal{O}(e^{4})
\biggr]
+ 2^{-9} e^2 \biggl[
1024 + 128e^2
+ \mathcal{O}(e^{3})
\biggr]
\biggr]
</math>
</math>
Line 5,122: Line 5,104:
   <td align="left">
   <td align="left">
<math>~
<math>~
2^{-3}\biggl\{ (1-e) \biggl[ - 8 - 8e - 3e^2 - 3e^3
2^{-9} \biggl[
1536e^2 
+ 2080e^4
+ \mathcal{O}(e^{5})  
\biggr]
\biggr]
+ (1+e^2) \biggl[ 16 ~+~2e^2
\biggr]
+ (1+e) \biggl[ - 8 + 8e - 7e^2 + 7e^3
\biggr] \biggr\}
+ \mathcal{O}(e^{4})
</math>
</math>
   </td>
   </td>
Line 5,142: Line 5,122:
   <td align="left">
   <td align="left">
<math>~
<math>~
2^{-3}\biggl\{
3e^2
\biggl[ - 8 - 8e - 3e^2 - 3e^3 \biggr]
+ \biggl[ \frac{5\cdot 13}{2^4}\biggr] e^4
+ \biggl[ 8e + 8e^2 + 3e^3\biggr]
+ \mathcal{O}(e^{5})  
+
\biggl[ 16 ~+~2e^2 \biggr]
+\biggl[ 16e^2 \biggr]
+
\biggl[ - 8 + 8e - 7e^2 + 7e^3 \biggr]  
+
\biggl[ - 8e + 8e^2 - 7e^3 \biggr]
\biggr\}
+ \mathcal{O}(e^{4})  
</math>
</math>
   </td>
   </td>
Line 5,160: Line 5,131:
<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~\Rightarrow ~~~ \frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
Line 5,167: Line 5,138:
   <td align="left">
   <td align="left">
<math>~
<math>~
3e^2+ \mathcal{O}(e^{4})  
\biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} \, .
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>


Hence,
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\Rightarrow ~~~ \frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
Line 5,181: Line 5,155:
   <td align="left">
   <td align="left">
<math>~
<math>~
[1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2} \, .
[1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2}
\biggl\{
\frac{\boldsymbol{K}(k) }{ r_1 }  \biggr\}\Delta_0  \, ,
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
</table>
 
or, more precisely,
Hence,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
Line 5,198: Line 5,173:
   <td align="left">
   <td align="left">
<math>~
<math>~
[1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2}
\biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2}
\biggl\{
\biggl\{
\frac{\boldsymbol{K}(k) }{ r_1 }  \biggr\}\Delta_0  \, .
\frac{\boldsymbol{K}(k) }{ r_1 }  \biggr\}\Delta_0  \, .
Line 5,799: Line 5,774:




Let's subtract <math>~K([k_H]_0)</math> from the potential expression.  But first, let's adopt the shorthand notation,
Let's subtract <math>~K([k_H]_0)</math> from the potential expression.  But first, let's adopt the shorthand notation &hellip;
 
<table border="1" width="80%" align="center" cellpadding="8"><tr><td align="left">
Given that,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\{ 1 + e^2 \cdot \mathcal{A} \}</math>
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\leftrightarrow</math>
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~\biggl\{ 1 + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr] \biggr\}[1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2} \, .</math>
<math>~
\biggl\{
\boldsymbol{K}(k) \biggr\} \frac{\Delta_0}{r_1}~\biggl( \frac{2^2}{3\pi^2} \biggr) \Upsilon_{W0}(\eta_0)
</math>
   </td>
   </td>
</tr>
</tr>
</table>
We can therefore write,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] - K([k_H]_0)</math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~- K([k_H]_0) +
<math>~\biggl\{ \boldsymbol{K}(k) \biggr\} \biggl[\frac{r_1^2 }{ \Delta_0^2 } \biggr]^{-1 / 2}
\biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\}
\biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2}
\{ 1 + e^2 \cdot \mathcal{A} \}
</math>
</math>
   </td>
   </td>
Line 5,839: Line 5,813:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~- K([k_H]_0)  
<math>~\biggl\{ \boldsymbol{K}(k) \biggr\} \biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \mathcal{O}(e^4)\biggr\}
+
\biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot \biggl[ 1 - \frac{1}{2}e^2  - \mathcal{O}(e^{4}) \biggr]
K(k_H)
\{ 1 + e^2 \cdot \mathcal{A} \}
+
\frac{\pi}{2} \cdot \delta_K \, ,
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
</table>
where we should keep in mind that <math>~\delta_k</math> is <math>~\mathcal{O}(e^1)</math>.  So, let's examine the piece,
 
let's define the variable, <math>~\mathcal{A}</math>, such that,
 
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]</math>
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
Line 5,864: Line 5,835:
   <td align="left">
   <td align="left">
<math>~
<math>~
\biggl\{1 + \frac{k_H^2}{4}
\biggl\{\boldsymbol{K}(k)\biggr\} \{1 + e^2\mathcal{A}\}
+ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4
+ \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6
+ \cdots
\biggr\} -
\biggl\{1 + \frac{k_H^2}{4}
+ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4
+ \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6
+ \cdots
\biggr\}_{e\rightarrow 0}
</math>
</math>
   </td>
   </td>
Line 5,880: Line 5,842:
<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~\Rightarrow ~~~ \{ 1 + e^2 \cdot \mathcal{A} \}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~\biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \mathcal{O}(e^4)\biggr\}
\frac{k_H^2}{4} - \biggl[ \frac{k_H^2}{4} \biggr]_{e\rightarrow 0}
\biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot \biggl[ 1 - \frac{1}{2}e^2  - \mathcal{O}(e^{4}) \biggr]</math>
</math>
   </td>
   </td>
</tr>
</tr>
Line 5,897: Line 5,858:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~\biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] \biggr\}
\biggl[ \frac{\varpi_W R_c (1 + e\cos\theta_H)}{[\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2} \biggr]
\biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 \biggr] \biggl[ 1 - \frac{1}{2}e^2   \biggr]</math>
-
   </td>
\biggl[ \frac{\varpi_W R_c (1 + e\cos\theta_H)}{[\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2} \biggr]_{e\rightarrow 0}
</math>
   </td>
</tr>
</tr>


Line 5,913: Line 5,871:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~\varpi_W R_c (1 + e\cos\theta_H)
<math>~\biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 - \frac{1}{2}e^2 \biggr\}</math>
\biggl\{ [\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2 \biggr\}^{-1}  
-
\biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
</math>
   </td>
   </td>
</tr>
</tr>
Line 5,926: Line 5,880:
<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~\Rightarrow ~~~ 2\mathcal{A}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~\varpi_W R_c (1 + e\cos\theta_H)
<math>~\biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \biggl( \frac{41}{2^3\cdot 3}\biggr) \, . </math>
\biggl\{
\varpi_W^2 + 2\varpi_W R_c(1 + e\cos\theta_H) + R_c^2(1 + 2e\cos\theta_H + e^2\cos^2\theta_H) + z_W^2 -2z_W R_c e\sin\theta_H + R_c^2 e^2\sin^2\theta_H
\biggr\}^{-1}
</math>
   </td>
   </td>
</tr>
</tr>
</table>
</td></tr></table>
We can therefore write,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] - K([k_H]_0)</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~- K([k_H]_0) +
-
\biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\}
\biggl\frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
\{ 1 + e^2 \cdot \mathcal{A} \}
</math>
</math>
   </td>
   </td>
Line 5,960: Line 5,918:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~- K([k_H]_0)  
-\biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
+
+ \biggl[ \frac{ \varpi_W R_c (1 + e\cos\theta_H)}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
K(k_H)  
\biggl\{1  
\{ 1 + e^2 \cdot \mathcal{A} \}
+ \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{(\varpi_W + R_c)^2 + z_W^2}
+
+ \frac{e^2 [R_c^2\cos^2\theta_H  + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2}
\frac{\pi}{2} \cdot \delta_K \, ,
\biggr\}^{-1}
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
where we should keep in mind that <math>~\delta_k</math> is <math>~\mathcal{O}(e^1)</math>.  So, let's examine the piece,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~\frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
-\biggl\frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
\biggl\{1 + \frac{k_H^2}{4}
+\biggl[ \frac{ \varpi_W R_c (1 + e\cos\theta_H)}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
+ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4
\biggl\{1  
+ \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6
- \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{(\varpi_W + R_c)^2 + z_W^2}
+ \cdots
\biggr\} -
\biggl\{1 + \frac{k_H^2}{4}
+ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4
+ \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6
+ \cdots
\biggr\}_{e\rightarrow 0}
</math>
</math>
   </td>
   </td>
Line 5,996: Line 5,962:
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
- \frac{e^2 [R_c^2\cos^2\theta_H  + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2}
\frac{k_H^2}{4} - \biggl[ \frac{k_H^2}{4} \biggr]_{e\rightarrow 0}
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ [(\varpi_W + R_c)^2 + z_W^2]^2}
\biggr\}
</math>
</math>
   </td>
   </td>
Line 6,012: Line 5,976:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
\biggl[ \frac{ \varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
\biggl[ \frac{\varpi_W R_c (1 + e\cos\theta_H)}{[\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2} \biggr]
\biggl\{
-
- \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{(\varpi_W + R_c)^2 + z_W^2}
\biggl\frac{\varpi_W R_c (1 + e\cos\theta_H)}{[\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2} \biggr]_{e\rightarrow 0}
</math>
</math>
   </td>
   </td>
Line 6,028: Line 5,992:
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~\varpi_W R_c (1 + e\cos\theta_H)
- \frac{e^2 [R_c^2\cos^2\theta_H + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2}
\biggl\{ [\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2 \biggr\}^{-1}
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ [(\varpi_W + R_c)^2 + z_W^2]^2}
-
\biggr\}
\biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
</math>
</math>
   </td>
   </td>
Line 6,044: Line 6,008:
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~\varpi_W R_c (1 + e\cos\theta_H)
+\biggl[ \frac{ \varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
\biggl\{
\biggl\{ \frac{e\cos\theta_H [(\varpi_W + R_c)^2 + z_W^2] -e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{(\varpi_W + R_c)^2 + z_W^2}
\varpi_W^2 + 2\varpi_W R_c(1 + e\cos\theta_H) + R_c^2(1 + 2e\cos\theta_H + e^2\cos^2\theta_H) + z_W^2 -2z_W R_c e\sin\theta_H + R_c^2 e^2\sin^2\theta_H
\biggr\}
\biggr\}^{-1}
</math>
</math>
   </td>
   </td>
Line 6,060: Line 6,024:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
\biggl[ \frac{ \varpi_W R_c}{ \Delta_0^2 } \biggr]
-
\biggl\{
\biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
e\cos\theta_H
- \frac{ eR_c\cos\theta_H [2\varpi_W + 2 R_c - 2z_W  \tan\theta_H]  }{ \Delta_0^2}
- \frac{e^2 R_c^2 }{ \Delta_0^2}
</math>
</math>
   </td>
   </td>
Line 6,078: Line 6,039:
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
- \frac{e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{ \Delta_0^2}
-\biggl[  \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ \Delta_0^4}
+ \biggl[ \frac{ \varpi_W R_c (1 + e\cos\theta_H)}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
\biggr\} \, .
\biggl\{1
+ \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{(\varpi_W + R_c)^2 + z_W^2}
+ \frac{e^2 [R_c^2\cos^2\theta_H + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2}
\biggr\}^{-1}
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
Now we have,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] - K([k_H]_0)</math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
Line 6,102: Line 6,061:
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~- K([k_H]_0)
<math>~
+
-\biggl[  \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr]
K(k_H)
+\biggl[ \frac{ \varpi_W R_c (1 + e\cos\theta_H)}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
\{ 1 + e^2 \cdot \mathcal{A} \}
\biggl\{1
+
- \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{(\varpi_W + R_c)^2 + z_W^2}
\frac{\pi}{2} \cdot \delta_K
</math>
</math>
   </td>
   </td>
Line 6,114: Line 6,072:
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\Rightarrow ~~~ - \Delta_0 \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
\frac{2}{\pi} K([k_H]_0)
- \frac{e^2 [R_c^2\cos^2\theta_H  + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2}
+ \frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ [(\varpi_W + R_c)^2 + z_W^2]^2}
+
\biggr\}
\delta_K
+
\frac{2}{\pi} K(k_H) e^2 \cdot \mathcal{A} \, .
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
But, as we have just demonstrated,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]+ \delta_K
&nbsp;
</math>
  </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~\approx</math>
Line 6,144: Line 6,095:
   <td align="left">
   <td align="left">
<math>~
<math>~
\biggl[ \frac{ \varpi_W R_c}{ \Delta_0^2 } \biggr]
\biggl[ \frac{ \varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
\biggl\{  
\biggl\{  
e\cos\theta_H
- \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{(\varpi_W + R_c)^2 + z_W^2}
- \frac{ eR_c\cos\theta_H [2\varpi_W  + 2 R_c - 2z_W \tan\theta_H]  }{ \Delta_0^2}
- \frac{e^2 R_c^2 }{ \Delta_0^2}
</math>
</math>
   </td>
   </td>
Line 6,162: Line 6,111:
   <td align="left">
   <td align="left">
<math>~
<math>~
- \frac{e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{ \Delta_0^2}
- \frac{e^2 [R_c^2\cos^2\theta_H + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2}
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ \Delta_0^4}
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ [(\varpi_W + R_c)^2 + z_W^2]^2}
\biggr\}  
\biggr\}
</math>
</math>
   </td>
   </td>
Line 6,178: Line 6,127:
   <td align="left">
   <td align="left">
<math>~
<math>~
-~\frac{ e\cdot \varpi_W R_c }{ \Delta_0^2 }  
+\biggl[ \frac{ \varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr]
\biggl[ \cos\theta_H   - \frac{2R_c (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)}{\Delta_0^2} \biggr]
\biggl\{ \frac{e\cos\theta_H [(\varpi_W + R_c)^2 + z_W^2] -e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H}{(\varpi_W + R_c)^2 + z_W^2}
\biggr\}
</math>
</math>
   </td>
   </td>
Line 6,188: Line 6,138:
&nbsp;
&nbsp;
   </td>
   </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+~\frac{ e^2 \cdot \varpi_W R_c}{2 \Delta_0^4 }
\biggl\{ 2 (\varpi_W R_c + R_c^2 )  - [ (\varpi_W^2 + R_c)^2 + z_W^2 ] 
- 2R_c^2   
- 4R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)
\biggr\} \, .
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
   <td align="center">
   <td align="center">
<math>~\approx</math>
<math>~\approx</math>
Line 6,210: Line 6,143:
   <td align="left">
   <td align="left">
<math>~
<math>~
\biggl[ \frac{e^2 \cdot  \varpi_W R_c}{ \Delta_0^4 } \biggr]
\biggl[ \frac{ \varpi_W R_c}{ \Delta_0^2 } \biggr]
\biggl\{  
\biggl\{  
- R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]
e\cos\theta_H
- \frac{ eR_c\cos\theta_H [2\varpi_W + 2 R_c - 2z_W  \tan\theta_H]  }{ \Delta_0^2}
- \frac{e^2 R_c^2 }{ \Delta_0^2}
</math>
</math>
   </td>
   </td>
Line 6,226: Line 6,161:
   <td align="left">
   <td align="left">
<math>~
<math>~
+~(\varpi_W R_c + R_c^2 - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2
- \frac{e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{ \Delta_0^2}
- R_c^2  
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ \Delta_0^4}
- 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)
\biggr\} \, .
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
Now we have,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] - K([k_H]_0)</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~- K([k_H]_0)
+ \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ \Delta_0^2}
+
\biggr\}
K(k_H)
\{ 1 + e^2 \cdot \mathcal{A} \}
+
\frac{\pi}{2} \cdot \delta_K
</math>
</math>
   </td>
   </td>
</tr>
</tr>
<tr><td align="center" colspan="3"><font color="red">TEMPORARY BREAK HERE</font></td></tr>
</table>
Hence,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~ - \frac{\pi  \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
<math>~\Rightarrow ~~~ - \Delta_0 \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
Line 6,263: Line 6,200:
   <td align="left">
   <td align="left">
<math>~
<math>~
K([k_H]_0)
\frac{2}{\pi} K([k_H]_0)
+ \frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]
+
\delta_K
+
+
K(k_H) e^2 \cdot \mathcal{A}  
\frac{2}{\pi} K(k_H) e^2 \cdot \mathcal{A} \, .
+~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot \varpi_W R_c}{ \Delta_0^4 } \biggr]
\biggl\{
- R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
But, as we have just demonstrated,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~\frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]+ \delta_K
  </td>
</math>
   <td align="center">
   <td align="center">
&nbsp;
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
+~(\varpi_W R_c + R_c^2 )  - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ]
\biggl[ \frac{ \varpi_W R_c}{ \Delta_0^2 } \biggr]
- R_c^2   
\biggl\{
- 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)
e\cos\theta_H
- \frac{ eR_c\cos\theta_H [2\varpi_W + 2 R_c - 2z_W \tan\theta_H]  }{ \Delta_0^2}
- \frac{e^2 R_c^2 }{ \Delta_0^2}
</math>
</math>
   </td>
   </td>
Line 6,298: Line 6,241:
   <td align="left">
   <td align="left">
<math>~
<math>~
+ \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{  \Delta_0^2}
- \frac{e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]  }{ \Delta_0^2}
+ \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{  \Delta_0^4}
\biggr\}  
\biggr\}  
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
<table border="1" cellpadding="8" align="center" width="90%">
<tr>
  <td align="center" bgcolor="black"><font color="white">'''Floating Comparison Summary'''</font></td>
</tr>
<tr><td align="left">
As [[#Step01|shown above]], the first three terms of the [https://ui.adsabs.harvard.edu/abs/2020MNRAS.494.5825H/abstract Hur&eacute;, et al. (2020)] series expression may be written as,
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{ \Psi_0 + \Psi_1 + \Psi_2 }{GM} \biggr] </math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
\boldsymbol{K}([k_H]_0)
-~\frac{ e\cdot \varpi_W R_c }{ \Delta_0^2 }  
-  
\biggl[ \cos\theta_H  - \frac{2R_c (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)}{\Delta_0^2} \biggr]  
\frac{e^2}{2^4} \cdot \boldsymbol{K}(k_H)
\frac{e^2}{2^4} \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \boldsymbol{E}(k_H) \, .
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>


Let's see how it compares to the first term of Wong's (1973) expression which, as [[#Step02|shown separately above]], can be written in the form,
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
\Delta_0 \biggl( \frac{2^{2} }{3\pi^2} \biggr)
+~\frac{ e^2 \cdot \varpi_W R_c}{2 \Delta_0^4 }
\Upsilon_{W0}(\eta_0) \biggl\{
\biggl\{ 2 (\varpi_W R_c + R_c^2 )  - [ (\varpi_W^2 + R_c)^2 + z_W^2 ] 
\frac{\boldsymbol{K}(k) }{ r_1 }  \biggr\}\, .
- 2R_c^2   
- 4R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)  
\biggr\} \, .
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>


----
First, as [[#Step03|shown above]],
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>
&nbsp;
  </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>~\approx</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
[1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2} \, .
\biggl[ \frac{e^2 \cdot  \varpi_W R_c}{ \Delta_0^4 } \biggr]
\biggl\{
- R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]
</math>
</math>
   </td>
   </td>
</tr>
</tr>
</table>
Note that, in order to determine the functional form of the <math>~\mathcal{O}(e^{2})</math> term in this expression, we will have to include <math>~k_0^8</math> terms in the various expressions for products of elliptic integrals.  Second, [[#Step04|we have shown that]],


<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{ r_1^2}{\Delta_0^2} </math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~1
<math>~
-e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{\Delta_0^2}\biggr]
+~(\varpi_W R_c + R_c^2 - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2
- \frac{\varpi_W R_c}{\Delta_0^2} \biggl[\frac{1}{2^2} e^4 + \frac{1}{2^3}e^6 + \frac{5}{2^6} e^8 + \mathcal{O}(e^{10}) \biggr] </math>
- R_c^2   
- 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)
</math>
   </td>
   </td>
</tr>
</tr>
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\Rightarrow ~~~ \frac{\Delta_0}{r_1} </math>
&nbsp;
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
1 + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr]
+ \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ \Delta_0^2}
\, ,</math> &nbsp; &nbsp; &nbsp; and we are defining <math>~\delta_K</math> such that,
\biggr\}
</math>
   </td>
   </td>
</tr>
</tr>


<tr>
<tr><td align="center" colspan="3"><font color="red">TEMPORARY BREAK HERE</font></td></tr>
  <td align="right">
<math>~K(k)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~K(k_H) + \frac{\pi}{2} \cdot \delta_K \, .</math>
  </td>
</tr>
</table>
</table>
----


Hence,
Hence,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
<math>~ - \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
Line 6,424: Line 6,342:
   <td align="left">
   <td align="left">
<math>~
<math>~
\biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\}
K([k_H]_0)
\biggl\{ 1  + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr] \biggr\}[1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2}
+
</math>
K(k_H) e^2 \cdot \mathcal{A}
+~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot  \varpi_W R_c}{ \Delta_0^4 } \biggr]
\biggl\{  
- R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]
</math>
   </td>
   </td>
</tr>
</tr>
Line 6,435: Line 6,357:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\approx</math>
&nbsp;
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
\boldsymbol{K}([k_H]_0)
+~(\varpi_W R_c + R_c^2 )  - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ]
+
- R_c^2  
\boldsymbol{K}(k_H) e^2 \cdot \mathcal{A}
- 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)
+~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot  \varpi_W R_c}{ \Delta_0^4 } \biggr]
\biggl\{
- R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]
</math>
</math>
   </td>
   </td>
Line 6,458: Line 6,377:
   <td align="left">
   <td align="left">
<math>~
<math>~
+~(\varpi_W R_c + R_c^2 ) - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ] 
+ \frac{  [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{  \Delta_0^2}
- R_c^2   
\biggr\}
- 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)  
</math>
  </td>
</tr>
</table>
 
===Include Second Wong Term===
 
<table border="0" cellpadding="5" align="center">
 
<tr>
  <td align="right">
<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\varpi,z)\biggr|_\mathrm{exterior}</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- \biggl( \frac{2^{3} }{3\pi^3} \biggr)
\Upsilon_{W1}(\eta_0) \times \cos\theta
\biggl\{ \frac{a}{r_2} \cdot
\boldsymbol{E}(k) \biggr\}
</math>
</math>
   </td>
   </td>
Line 6,467: Line 6,407:
<tr>
<tr>
   <td align="right">
   <td align="right">
&nbsp;
<math>~\Rightarrow ~~~ - \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W1}}{GM} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
&nbsp;
<math>~=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>~
+ \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{ \Delta_0^2}
\biggl( \frac{2^{2} }{3\pi^2} \biggr)
\biggr\}  
\Upsilon_{W1}(\eta_0) \times \cos\theta
\biggl\{ \frac{\Delta_0}{r_2} \cdot
\boldsymbol{E}(k) \biggr\} \, ;
</math>
</math>
   </td>
   </td>
Line 6,481: Line 6,423:
</table>
</table>


</td></tr>
====Leading (Upsilon) Coefficient====
</table>


==Spheroid-Ring Systems==
<table border="0" cellpadding="5" align="center">
Through a research collaboration at the [https://www.u-bordeaux.com Universit&eacute; de Bordeaux], [https://ui.adsabs.harvard.edu/abs/2019MNRAS.487.4504B/abstract B. Basillais &amp; J. -M. Hur&eacute; (2019), MNRAS, 487, 4504-4509] have published a paper titled, ''Rigidly Rotating, Incompressible Spheroid-Ring Systems:  New Bifurcations, Critical Rotations, and Degenerate States.''


'''TO BE DISCUSSED''' &hellip;
<tr>
  <td align="right">
<math>~\Upsilon_{W1}(\eta_0)</math>
  </td>
  <td align="center">
<math>~\equiv</math>
  </td>
  <td align="left" colspan="2">
<math>~\biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] 
\biggl\{
K(k_0)\cdot K(k_0) [\cosh\eta_0(1 - \cosh\eta_0)]
+~2K(k_0)\cdot E(k_0) [(3\cosh^2\eta_0 - 1)]
-~5 E(k_0)\cdot E(k_0) [\cosh\eta_0(1+\cosh\eta_0)]
\biggr\}
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~\Rightarrow~~~ \biggl[ \frac{e^2}{ (1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left" colspan="2">
<math>~ 
- (1-e)K(k_0)\cdot K(k_0)
+~2(3-e^2)K(k_0)\cdot E(k_0) 
-~5(1+e) E(k_0)\cdot E(k_0)  \, .
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~\Rightarrow ~~~ \frac{2^2}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- (1-e) \biggl[ 1 + \frac{1}{2} k_0^2
+ \frac{11}{2^5} ~k_0^4
+ \frac{17}{2^6} ~ k_0^6
+ \frac{1787}{2^{13}} ~k_0^8
+ \mathcal{O}(k_0^{10})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 2 (3-e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~k_0^4
~+~\frac{1}{2^5} ~ k_0^6
~+~ \frac{231}{2^{13}}~k_0^8
+ \mathcal{O}(k_0^{10})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
- 5(1+e) \biggl[ 1
- ~\frac{1}{2} ~k_0^2 ~
-~ \frac{1}{2^5} ~ k_0^4 ~
~-~\frac{1}{2^6} ~ k_0^6
~-~\frac{77}{2^{13}}~k_0^8
+ \mathcal{O}(k_0^{10})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- (1-e) \biggl[ 1 + \frac{1}{2} \cdot 2e(  1 - e +e^2 - e^3 )
+ \frac{11}{2^5} ~\cdot 4e^2(  1 - 2e + 3e^2 )
+ \frac{17}{2^6} ~ \cdot 2^3e^3(  1 - 3e  )
+ \frac{1787}{2^{13}} ~\cdot 2^4e^4
+ \mathcal{O}(e^{5})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 2 (3-e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~\cdot 4e^2(  1 - 2e + 3e^2 )
~+~\frac{1}{2^5} ~ \cdot 2^3e^3(  1 - 3e  )
~+~ \frac{231}{2^{13}}~\cdot 2^4e^4
+ \mathcal{O}(e^{5})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
- 5(1+e) \biggl[ 1
- ~\frac{1}{2} ~\cdot 2e(  1 - e +e^2 - e^3 ) ~
-~ \frac{1}{2^5} ~ \cdot 4e^2(  1 - 2e + 3e^2 )
~-~\frac{1}{2^6} ~ \cdot 2^3e^3(  1 - 3e  )
~-~\frac{77}{2^{13}}~\cdot 2^4e^4
+ \mathcal{O}(e^{5})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- 2^{-9}(1-e) \biggl[ 2^9 + 2^9e(  1 - e +e^2 - e^3 )
+ 2^6 \cdot 11 ~\cdot e^2(  1 - 2e + 3e^2 )
+ 2^6\cdot 17 ~ \cdot e^3(  1 - 3e  )
+ 1787 ~\cdot e^4
+ \mathcal{O}(e^{5})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 2^{-9} (6- 2e^2) \biggl[ 2^9 ~+~2^6~\cdot e^2(  1 - 2e + 3e^2 )
~+~2^7 \cdot e^3(  1 - 3e  )
~+~ 231~\cdot e^4
+ \mathcal{O}(e^{5})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
- 2^{-9}(5+ 5e) \biggl[ 2^9
- ~2^9 \cdot e(  1 - e +e^2 - e^3 ) ~
-~ 2^6 \cdot e^2(  1 - 2e + 3e^2 )
~-~2^6 \cdot e^3(  1 - 3e  )
~-~77~\cdot e^4
+ \mathcal{O}(e^{5})
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~\Rightarrow ~~~\frac{2^{11}}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- 2^9 - 2^9e(  1 - e +e^2 - e^3 )
- 2^6 \cdot 11 ~\cdot e^2(  1 - 2e + 3e^2 )
- 2^6\cdot 17 ~ \cdot e^3(  1 - 3e  )
- 1787 ~\cdot e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 2^9e + 2^9e^2(  1 - e +e^2 )
+ 2^6 \cdot 11 ~\cdot e^3(  1 - 2e )
+ 2^6\cdot 17 ~ \cdot e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 6\biggl[ 2^9 ~+~2^6~\cdot e^2(  1 - 2e + 3e^2 )
~+~2^7 \cdot e^3(  1 - 3e  )
~+~ 231~\cdot e^4
\biggr]
-2^{10}e^2 ~-~2^7~\cdot e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 5 \biggl[ -2^9
+ ~2^9 \cdot e(  1 - e +e^2 - e^3 ) ~
+~ 2^6 \cdot e^2(  1 - 2e + 3e^2 )
~+~2^6 \cdot e^3(  1 - 3e  )
~+~77~\cdot e^4
\biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+~5 \biggl[ -2^9e
+ ~2^9 \cdot e^2(  1 - e +e^2 ) ~
+~ 2^6 \cdot e^3(  1 - 2e )
~+~2^6 \cdot e^4
\biggr]
+ \mathcal{O}(e^{5})
</math>
  </td>
</tr>
 
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
2^9( e^2 - e^3 + e^4 )
- 2^6 \cdot 11 ~(  e^2 - 2e^3 + 3e^4 )
- 2^6\cdot 17 ~(  e^3 - 3e^4  )
- 1787 ~e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+2^9 (  e^2 - e^3 +e^4 )
+ 2^6 \cdot 11 (  e^3 - 2e^4 )
+ 2^6\cdot 17 ~ e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+~ 3\cdot 2^7~(  e^2 - 2e^3 + 3e^4 )
~+~3\cdot 2^8 (  e^3 - 3e^4  )
~+~ 2\cdot 3^2 \cdot 7\cdot 11~\cdot e^4
-2^{10}e^2 ~-~2^7~\cdot e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ 5\cdot 2^9 (  - e^2 +e^3 - e^4 ) ~
+~ 5\cdot 2^6 (  e^2 - 2e^3 + 3e^4 )
~+~5\cdot 2^6 (  e^3 - 3e^4  )
~+~5\cdot 77~e^4
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+5\cdot 2^9 (  e^2 - e^3 +e^4 ) ~
+~ 5\cdot 2^6 (  e^3 - 2e^4 )
~+~5\cdot 2^6 e^4
+ \mathcal{O}(e^{5})
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
e^2 [ 2^9 - 2^6\cdot 11 + 2^9 + 3\cdot 2^7 -2^{10} -5\cdot 2^9 + 5\cdot 2^6 + 5\cdot 2^9 ]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ e^3 [ -2^9 - 2^7\cdot 11 - 2^6\cdot 17 - 2^9 +2^6\cdot 11 - 3\cdot 2^8+3\cdot 2^8  + 5\cdot 2^9-5\cdot 2^7 +5\cdot 2^6 -5\cdot 2^9 + 5\cdot 2^6]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ e^4 [ 2^9 - 3\cdot 11\cdot 2^6+3\cdot 17\cdot 2^6 - 1787 + 2^9 - 11\cdot 2^7 + 17\cdot 2^6 + 3^2\cdot 2^7 - 3^2\cdot 2^8+ 2\cdot 3^2\cdot 7\cdot 11 - 2^7
- 5\cdot 2^9 + 3\cdot 5\cdot 2^6 - 3\cdot 5\cdot 2^6 + 5\cdot 7\cdot 11  + 5\cdot 2^9 - 5\cdot 2^7 +5\cdot 2^6]
+ \mathcal{O}(e^{5})
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
e^2 [ - 2^6\cdot 11  + 3\cdot 2^7  + 5\cdot 2^6  ]
+ e^3 [ -2^{10} - 2^7\cdot 11 - 2^6\cdot 17 +2^6\cdot 11  ]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ e^4 [ 2^{10}~-~ 1787~+~ 2\cdot 3^2\cdot 7\cdot 11~+~ 5\cdot 7\cdot 11 ~+~ 2^6\cdot (3\cdot 17 - 3\cdot 11 - 22 + 17 + 18 - 36 - 2 - 10 + 5)  ]
+ \mathcal{O}(e^{5})
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
2^6 e^2 [ 0  ] ~- 2^8 \cdot 11 e^3 + e^4 [ 2^{10}~-~ 1787~+~ 7\cdot 11\cdot 23 ~-~ 2^8\cdot 3  ]
+ \mathcal{O}(e^{5})
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- 2^8 \cdot 11 e^3 + 2^4\cdot 3\cdot 5e^4
+ \mathcal{O}(e^{5})
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~\Rightarrow ~~~\frac{2^{2}}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
- \frac{11}{2} e^3 + \frac{3\cdot 5}{2^5} e^4
+ \mathcal{O}(e^{5}) \, .
</math>
  </td>
</tr>
 
</table>
 
<table border="1" cellpadding="8" align="center" width="90%">
<tr>
  <td align="center" bgcolor="black"><font color="white">'''Floating Comparison Summary'''</font></td>
</tr>
<tr><td align="left">
As [[#Step01|shown above]], the first three terms of the [https://ui.adsabs.harvard.edu/abs/2020MNRAS.494.5825H/abstract Hur&eacute;, et al. (2020)] series expression may be written as,
<table border="0" cellpadding="5" align="center">
 
<tr>
  <td align="right">
<math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{ \Psi_0 + \Psi_1 + \Psi_2 }{GM} \biggr] </math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
\boldsymbol{K}([k_H]_0)
-
\frac{e^2}{2^4} \cdot \boldsymbol{K}(k_H)
+  \frac{e^2}{2^4} \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr]  \boldsymbol{E}(k_H) \, .
</math>
  </td>
</tr>
</table>
 
Let's see how it compares to the first term of Wong's (1973) expression which, as [[#Step02|shown separately above]], can be written in the form,
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
\Delta_0 \biggl( \frac{2^{2} }{3\pi^2} \biggr)
\Upsilon_{W0}(\eta_0) \biggl\{
\frac{\boldsymbol{K}(k) }{ r_1 }  \biggr\}\, .
</math>
  </td>
</tr>
</table>
 
----
First, as [[#Step03|shown above]],
 
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
\biggl[1 + \biggl(\frac{5\cdot 13}{2^4\cdot 3} \biggr)e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} \, .
</math>
  </td>
</tr>
</table>
Note that, in order to determine the functional form of the <math>~\mathcal{O}(e^{2})</math> term in this expression, we will have to include <math>~k_0^8</math> terms in the various expressions for products of elliptic integrals.  Second, [[#Step04|we have shown that]],
 
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\frac{ r_1^2}{\Delta_0^2} </math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~1
-e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{\Delta_0^2}\biggr]
- \frac{\varpi_W R_c}{\Delta_0^2} \biggl[\frac{1}{2^2} e^4 + \frac{1}{2^3}e^6 + \frac{5}{2^6} e^8 + \mathcal{O}(e^{10})  \biggr] </math>
  </td>
</tr>
<tr>
  <td align="right">
<math>~\Rightarrow ~~~ \frac{\Delta_0}{r_1} </math>
  </td>
  <td align="center">
<math>~\approx</math>
  </td>
  <td align="left">
<math>~
1  + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr]
\, ,</math> &nbsp; &nbsp; &nbsp; and we are defining <math>~\delta_K</math> such that,
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~K(k)</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~K(k_H) + \frac{\pi}{2} \cdot \delta_K \, .</math>
  </td>
</tr>
</table>
 
----
 
Hence,
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>
  </td>
  <td align="center">
<math>~\approx</math>
  </td>
  <td align="left">
<math>~
\biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\}
\biggl\{ 1  + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr] \biggr\}\biggl[1 + \biggl(\frac{5\cdot 13}{2^4\cdot 3} \biggr)e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2}
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~\approx</math>
  </td>
  <td align="left">
<math>~
\boldsymbol{K}([k_H]_0)
+
\boldsymbol{K}(k_H) e^2 \cdot \mathcal{A}
+~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot  \varpi_W R_c}{ \Delta_0^4 } \biggr]
\biggl\{
- R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+~(\varpi_W R_c + R_c^2 )  - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ] 
- R_c^2   
- 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W  \cos\theta_H - z_W \sin\theta_H)
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>~
+ \frac{  [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2  }{  \Delta_0^2}
\biggr\} \, ,
</math>
  </td>
</tr>
</table>
and,
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\mathcal{A}</math>
  </td>
  <td align="center">
<math>~\approx</math>
  </td>
  <td align="left">
<math>~\biggl[ \frac{R_c(R_c + \varpi_W)}{2\Delta_0^2}\biggr] + \biggl( \frac{41}{2^4\cdot 3}\biggr) \, . </math>
  </td>
</tr>
</table>
 
----
 
Second,
<table border="0" cellpadding="5" align="center">
 
<tr>
  <td align="right">
<math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W1}}{GM} \biggr] </math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
\boldsymbol{E}(k)
\biggl\{ \frac{\Delta_0 \cdot \cos\theta}{r_2} \biggr\}
\biggl[ \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W1}(\eta_0) \biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
\biggl\{ \boldsymbol{E}(k_H) + \frac{\pi}{2}\cdot \delta_E \biggr\}
\biggl\{ \frac{\Delta_0 \cdot \cos\theta}{r_2} \biggr\}
\biggl[- \biggl(\frac{11}{2\cdot 3} \biggr) e + \biggl(\frac{5}{2^5}\biggr) e^2 + \mathcal{O}(e^{5}) \biggr]\cdot (1 - e^2)^{1 / 2} \, .
</math>
  </td>
</tr>
</table>
 
</td></tr>
</table>
 
====Geometric Factor====
 
By definition,
 
<table border="0" cellpadding="5" align="center">
 
<tr>
  <td align="right">
<math>~\Delta_0^2</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~
(\varpi_W + R_c)^2 + z_W^2 \, ,
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~r_1^2</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\biggl[ \varpi_W + R_c (1 - e^2 )^{1 / 2}\biggr]^2 + z_W^2  \, ,</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~r_2^2</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\biggl[ \varpi_W - R_c (1 - e^2 )^{1 / 2}\biggr]^2 + z_W^2  \, ,</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>~\cos^2\theta</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\biggl[ \frac{r_1^2 + r_2^2 - 4R_c^2(1-e^2)}{2r_1 r_2} \biggr]^2  \, .</math>
  </td>
</tr>
</table>
Hence,
<table border="0" cellpadding="5" align="center">
 
<tr>
  <td align="right">
<math>~r_2^2 - \Delta_0^2 \cdot \cos^2\theta</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~</math>
  </td>
</tr>
</table>




{{LSU_HBook_footer}}
{{LSU_HBook_footer}}

Revision as of 03:56, 24 July 2020

Université de Bordeaux (Part 1)

Whitworth's (1981) Isothermal Free-Energy Surface
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Spheroid-Ring Systems

Through a research collaboration at the Université de Bordeaux, B. Basillais & J. -M. Huré (2019), MNRAS, 487, 4504-4509 have published a paper titled, Rigidly Rotating, Incompressible Spheroid-Ring Systems: New Bifurcations, Critical Rotations, and Degenerate States.

We discuss this topic in a separate, accompanying chapter.

Exterior Gravitational Potential of Toroids

J. -M. Huré, B. Basillais, V. Karas, A. Trova, & O. Semerák (2020), MNRAS, 494, 5825-5838 have published a paper titled, The Exterior Gravitational Potential of Toroids. Here we examine how their work relates to the published work by C.-Y. Wong (1973, Annals of Physics, 77, 279), which we have separately discussed in detail.

Our Presentation of Wong's (1973) Result

Summary:  First three terms in Wong's (1973) expression for the gravitational potential at any point, P(ϖ, z), outside of a uniform-density torus.
Wong diagram

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W0}(\varpi,z)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \biggl( \frac{2^{3} }{3\pi^3} \biggr) \Upsilon_{W0}(\eta_0) \biggl\{ \frac{a}{ r_1 } \cdot \boldsymbol{K}(k) \biggr\}\, , </math>

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\varpi,z)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \biggl( \frac{2^{3} }{3\pi^3} \biggr) \Upsilon_{W1}(\eta_0) \times \cos\theta \biggl\{ \frac{a}{r_2} \cdot \boldsymbol{E}(k) \biggr\} \, , </math>

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W2}(\varpi, z)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \biggl( \frac{2^{3} }{3\pi^3} \biggr)\Upsilon_{W2}(\eta_0) \times \cos(2\theta) \biggl\{ \biggl[ \frac{r_1^2 + r_2^2}{2r_1 r_2} \biggr] \frac{a}{r_2} \cdot \boldsymbol{E}(k) - \frac{a}{r_1} \cdot \boldsymbol{K}(k) \biggr\} \, , </math>

where, once the major ( R ) and minor ( d ) radii of the torus — as well as the vertical location of its equatorial plane (Z0) — have been specified, we have,

<math>~a^2 </math>

<math>~\equiv</math>

<math>~ R^2 - d^2</math>       and,       <math>~\cosh\eta_0 \equiv \frac{R}{d} ~~~~\Rightarrow ~~~\sinh\eta_0 = \frac{a}{d} \, , </math>

<math>~r_1^2</math>

<math>~\equiv</math>

<math>~(\varpi + a)^2 + (z - Z_0)^2 \, ,</math>

<math>~r_2^2</math>

<math>~\equiv</math>

<math>~(\varpi - a)^2 + (z - Z_0)^2 \, ,</math>

<math>~\cos\theta</math>

<math>~\equiv</math>

<math>~\biggl[\frac{ r_1^2 + r_2^2 - 4a^2}{2r_1 r_2} \biggr] \, ,</math>

<math>~k</math>

<math>~\equiv</math>

<math>~ \biggl[ \frac{r_1^2 - r_2^2}{r_1^2} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{r_1^2} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{(\varpi + a)^2 + (z - Z_0)^2} \biggr]^{1 / 2} \, . </math>


  Leading Coefficient Expressions … … evaluated for:    <math>~\frac{R}{d} = \cosh\eta_0 = 3</math>

<math>~\Upsilon_{W0}(\eta_0)</math>

<math>~\equiv</math>

<math>~ \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \biggl\{ K(k_0)\cdot K(k_0) [ \cosh\eta_0(1 - \cosh\eta_0) ] + 2K(k_0)\cdot E(k_0) [ \cosh^2\eta_0 + 1 ] - E(k_0)\cdot E(k_0) [ \cosh\eta_0(1 + \cosh\eta_0) ] \biggr\} \, , </math>

7.134677

<math>~\Upsilon_{W1}(\eta_0)</math>

<math>~\equiv</math>

<math>~\biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \biggl\{ K(k_0)\cdot K(k_0) [\cosh\eta_0(1 - \cosh\eta_0)] +~2K(k_0)\cdot E(k_0) [(3\cosh^2\eta_0 - 1)] -~5 E(k_0)\cdot E(k_0) [\cosh\eta_0(1+\cosh\eta_0)] \biggr\} \, , </math>

0.130324

<math>~\Upsilon_{W2}(\eta_0)</math>

<math>~\equiv</math>

<math>~ \frac{2^{3 / 2}}{3^2} \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \biggl\{ K ( k_0 ) \cdot K(k_0) \cdot \cosh\eta_0(1 - \cosh\eta_0) [ 16\cosh^2\eta_0 - 13] + 2 K ( k_0 ) \cdot E(k_0) [ 16\cosh^4\eta_0 -13\cosh^2\eta_0 + 3 ] </math>

 

 

 

<math>~ -~E(k_0) \cdot E(k_0) \cdot \cosh\eta_0 (1 + \cosh\eta_0) [ 3 +16\cosh^2\eta_0 ] \biggr\} \, , </math>

0.003153
where,

<math>~k_0</math>

<math>~\equiv</math>

<math>~ \biggl[ \frac{2}{\cosh\eta_0 + 1} \biggr]^{1 / 2} \, . </math>

0.707106781

NOTE: In evaluating these "leading coefficient expressions" for the case, <math>~R/d = 3</math>, we have used the complete elliptic integral evaluations, K(k0) = 1.854074677 and E(k0) = 1.350643881.

Setup

From our accompanying discussion of Wong's (1973) derivation, the exterior potential is given by the expression,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W}(\eta,\theta)</math>

<math>~=</math>

<math>~ -D_0 (\cosh\eta - \cos\theta)^{1 / 2} ~\sum_{n=0}^{\mathrm{nmax}} \epsilon_n \cos(n\theta) C_n(\cosh\eta_0)P_{n-\frac{1}{2}}(\cosh\eta) \, , </math>

Wong (1973), §II.D, p. 294, Eqs. (2.59) & (2.61)

where,

<math>~D_0 </math>

<math>~\equiv</math>

<math>~ \frac{2^{3/2} }{3\pi^2} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] = \frac{2^{3/2} }{3\pi^2} \biggl[\frac{(R^2 - d^2)^{3 / 2}}{d^2 R} \biggr] \, ,</math>

<math>~C_n(\cosh\eta_0)</math>

<math>~\equiv</math>

<math>~(n+\tfrac{1}{2})Q_{n+\frac{1}{2}}(\cosh \eta_0) Q_{n - \frac{1}{2}}^2(\cosh \eta_0) - (n - \tfrac{3}{2}) Q_{n - \frac{1}{2}}(\cosh \eta_0)~Q^2_{n + \frac{1}{2}}(\cosh \eta_0) \, </math>

Wong (1973), §II.D, p. 294, Eq. (2.63)

and where, in terms of the major ( R ) and minor ( d ) radii of the torus — or their ratio, ε ≡ d/R,

<math>~\cosh\eta_0</math>

<math>~=</math>

<math>~\frac{R}{d} = \frac{1}{\epsilon} \, ,</math>

<math>~\sinh\eta_0</math>

<math>~=</math>

<math>~\frac{a}{d} = \frac{1}{d}\biggl[ R^2 - d^2 \biggr]^{1 / 2} = \frac{1}{\epsilon} \biggl[1 - \epsilon^2 \biggr]^{1 / 2} \, .</math>

These expressions incorporate a number of basic elements of a toroidal coordinate system. In what follows, we will also make use of the following relations:

Once the primary scale factor, <math>~a</math>, has been specified, the illustration shown at the bottom of this inset box — see also our accompanying set of similar figures used by other researchers — helps in explaining how transformations can be made between any two of the referenced coordinate pairs: <math>~(\varpi, z)</math>, <math>~(\eta, \theta)</math>, <math>~(r_1, r_2)</math>.

<math>~\varpi</math>

<math>~=</math>

<math>~\frac{a\sinh\eta}{(\cosh\eta - \cos\theta)}</math>

     <math>~\Rightarrow ~</math>     

<math>~\cos\theta</math>

<math>~=</math>

<math>~\cosh\eta - \frac{a\sinh\eta}{\varpi}</math>

<math>~z - Z_0</math>

<math>~=</math>

<math>~\frac{a\sin\theta}{(\cosh\eta - \cos\theta)}</math>

     <math>~\Rightarrow ~</math>     

<math>~\sin\theta</math>

<math>~=</math>

<math>~\frac{(z - Z_0)}{\varpi} \cdot \sinh\eta </math>

Given that (sin2θ + cos2θ) = 1, we have,

<math>~1</math>

<math>~=</math>

<math>~ \biggl[ \frac{(z - Z_0)}{\varpi} \cdot \sinh\eta \biggr]^2 + \biggl[\cosh\eta - \frac{a\sinh\eta}{\varpi}\biggr]^2 </math>

<math>~\Rightarrow ~~~ \coth\eta</math>

<math>~=</math>

<math>~ \frac{1}{2a\varpi}\biggl[\varpi^2 + a^2 + (z - Z_0)^2 \biggr] \, . </math>

We deduce as well that,

<math>~\frac{2}{\coth\eta + 1}</math>

<math>~=</math>

<math>~ \frac{4a\varpi}{(\varpi + a)^2 + (z - Z_0)^2} \, , </math>        and,

<math>~\sinh\eta + \cosh\eta</math>

<math>~=</math>

<math>~ \frac{\varpi^2 + a^2 + (z - Z_0)^2}{(\varpi + a)^2 + (z - Z_0)^2} \, . </math>


Given the definitions,

<math>~r_1^2</math>

<math>~=</math>

<math>~(\varpi + a)^2 + (z - Z_0)^2 \, ,</math>

<math>~r_2^2</math>

<math>~=</math>

<math>~(\varpi - a)^2 + (z - Z_0)^2 \, ,</math>

we can use the transformations,

<math>~\varpi</math>

<math>~=</math>

<math>~\frac{(r_1^2 - r_2^2)}{4a}</math>     and,

<math>~(z - Z_0)^2</math>

<math>~=</math>

<math>~r_2^2 - \frac{1}{16a^2}\biggl[ r_1^2 - r_2^2 - 4a^2 \biggr]^2 \, ,</math>     or,

<math>~(z - Z_0)^2</math>

<math>~=</math>

<math>~r_1^2 - \frac{1}{16a^2}\biggl[ r_1^2 - r_2^2 + 4a^2 \biggr]^2 \, .</math>

Or we can use the transformations,

<math>~\eta</math>

<math>~=</math>

<math>~\ln \biggl(\frac{r_1}{r_2}\biggr) \, ,</math>

<math>~\cos\theta</math>

<math>~=</math>

<math>~\frac{r_1^2 + r_2^2 - 4a^2}{2r_1 r_2} \, .</math>


Additional potentially useful relations can be found in an accompanying chapter wherein we present a variety of basic elements of a toroidal coordinate system.

Wong diagram

Leading (n = 0) Term

Wong's Expression

Now, from our separate derivation we have,

<math>~P_{-1 / 2}(\cosh\eta)</math>

<math>~=</math>

<math>~ \frac{\sqrt{2}}{\pi}~ (\sinh\eta)^{-1 / 2} Q_{-1 / 2}(\coth\eta) \, . </math>

And if we make the function-argument substitution, <math>~z \rightarrow \coth\eta</math>, in the "Key Equation,"

LSU Key.png

<math>~Q_{-\frac{1}{2}}(z)</math>

<math>~=</math>

<math>~ \sqrt{ \frac{2}{z+1} } ~K\biggl( \sqrt{ \frac{2}{z+1}} \biggr) </math>

Abramowitz & Stegun (1995), p. 337, eq. (8.13.3)

we can write,

<math>~P_{-1 / 2}(\cosh\eta)</math>

<math>~=</math>

<math>~ \frac{\sqrt{2}}{\pi}~ (\sinh\eta)^{-1 / 2} ~k \boldsymbol{K}(k) \, , </math>

where, from above, we recognize that,

<math>~ k \equiv \biggl[ \frac{2}{\coth\eta + 1} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{(\varpi + a)^2 + (z - Z_0)^2} \biggr]^{1 / 2} \, . </math>

So, the leading (n = 0) term gives,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W0}(\eta,\theta)</math>

<math>~=</math>

<math>~ -D_0 (\cosh\eta - \cos\theta)^{1 / 2} ~C_0(\cosh\eta_0)P_{-\frac{1}{2}}(\cosh\eta) </math>

 

<math>~=</math>

<math>~ -D_0~C_0(\cosh\eta_0) \biggl[ \frac{a \sinh\eta}{\varpi} \biggr]^{1 / 2} ~\frac{\sqrt{2}}{\pi}~ (\sinh\eta)^{-1 / 2} ~k \boldsymbol{K}(k) </math>

 

<math>~=</math>

<math>~ -\frac{D_0~C_0(\cosh\eta_0)}{\pi} \biggl[ \frac{2a }{\varpi} \biggr]^{1 / 2} ~ k \boldsymbol{K}(k) </math>

 

<math>~=</math>

<math>~ - C_0(\cosh\eta_0) \cdot \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] \frac{a}{ [ (\varpi + a)^2 + (z - Z_0)^2 ]^{1 / 2} } \cdot \boldsymbol{K}(k) \, . </math>

Thin-Ring Evaluation of C0

In an accompanying discussion of the thin-ring approximation, we showed that as <math>~\cosh\eta_0 \rightarrow \infty</math>

<math>~C_0(x)\biggr|_{x\rightarrow \infty}</math>

<math>~=</math>

<math>~\biggl( \frac{3 \pi^2}{2^2} \biggr) \frac{1}{\cosh^2\eta_0} \, . </math>

Hence, in this limit we can write,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W0}(\eta,\theta)\biggr|_\mathrm{thin-ring}</math>

<math>~=</math>

<math>~ - \frac{2 }{\pi} \cancelto{1}{\biggl[\frac{\sinh\eta_0}{\cosh\eta_0}\biggr]^3 } \frac{a}{ [ (\varpi + a)^2 + (z - Z_0)^2 ]^{1 / 2} } \cdot \boldsymbol{K}(k) \, . </math>

More General Evaluation of C0

NOTE of CAUTION: In our above evaluation of the toroidal function, <math>~Q_{-\frac{1}{2}}(z)</math>, we appropriately associated the function argument, <math>~z</math>, with the hyperbolic-cotangent of <math>~\eta</math>; that is, we made the substitution, <math>~z \rightarrow \coth\eta</math>. Here, as we assess the behavior of, and evaluate, the leading coefficient, <math>~C_0</math>, an alternate substitution is appropriate, namely, <math>~z_0 \rightarrow \cosh\eta_0</math>; we affix the subscript zero to this function argument in an effort to minimize possible confusion with the argument, <math>~z</math>.

Drawing from our accompanying tabulation of Toroidal Function Evaluations, we have more generally,

<math>~2C_0(\cosh\eta_0)</math>

<math>~=</math>

<math>~ \biggl[ Q_{+\frac{1}{2}}(\cosh \eta_0) \biggr] \biggl[ Q_{ - \frac{1}{2}}^2(\cosh \eta_0) \biggr] + 3 \biggl[ Q_{ - \frac{1}{2}}(\cosh \eta_0) \biggr] \biggl[ Q^2_{ + \frac{1}{2}}(\cosh \eta_0) \biggr] </math>

 

<math>~=</math>

<math>~ \biggl[ \cosh\eta_0 ~k_0~K(k_0) ~-~ [2(\cosh\eta_0+1)]^{1 / 2} E(k_0) \biggr] \times \biggl\{ \frac{ 4 \cosh\eta_0 ~E(k_0) - (\cosh\eta_0-1) K(k_0) }{ [2^{3} (\cosh\eta_0+1) (\cosh\eta_0-1)^{2} ]^{1 / 2}} \biggr\} </math>

 

 

<math>~ - \frac{3}{2^2} \biggl[ k_0 ~K ( k_0) \biggr] \times \biggl\{ \cosh\eta_0~ k_0~K ( k_0 ) ~-~(\cosh^2\eta_0+3) \biggl[ \frac{2}{(\cosh\eta_0 - 1)(\cosh^2\eta_0 -1)} \biggr]^{1 / 2} E(k_0)

\biggr\} \, ,

</math>

where,

<math>~k_0</math>

<math>~\equiv</math>

<math>~\biggl[ \frac{2}{\cosh\eta_0+1}\biggr]^{1 / 2} ~~~\Rightarrow ~~~ (\cosh\eta_0 + 1) = \frac{2}{k_0^2} \, .</math>

Looking back at our previous numerical evaluation of <math>~C_0(\cosh\eta_0)</math> when <math>~z_0 = \cosh\eta_0 = 3 ~~\Rightarrow ~~~ k_0 = 2^{-1 / 2}</math>, we see that,

Appendix Expression: <math>~Q_{-\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~k_0 K(k_0)</math>

Hence MF53 value, <math>~Q_{-\tfrac{1}{2}}(3)</math>

<math>~=</math>

<math>~1.311028777 ~~~\Rightarrow ~~~ K(k_0) = 1.854074677</math>

Appendix Expression: <math>~Q_{+\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0)</math>

Hence MF53 value, <math>~Q_{+\tfrac{1}{2}}(3)</math>

<math>~=</math>

<math>~0.1128885424 ~~~\Rightarrow~~~ E(k_0) = 1.350643881</math>

Appendix Expression: <math>~Q^2_{-\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~[2^3(z-1)(z^2-1)]^{-1 / 2} [4zE(k_0) - (z-1)K(k_0)]</math>

Hence, <math>~Q^2_{-\tfrac{1}{2}}(3)</math>

<math>~=</math>

<math>~1.104816977</math>, which matches MF53 value

Additional derivation: <math>~Q^2_{+\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~ -~\frac{1}{2^2}\biggl\{ z k_0~K ( k_0 ) ~-~(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} E(k_0)\biggr\} </math>

Hence, <math>~Q^2_{+\tfrac{1}{2}}(3)</math>

<math>~=</math>

<math>~0.449302588</math>


<math>~\Rightarrow ~~~ C_0(3)</math>

<math>~=</math>

<math>~ \frac{1}{2}~Q_{+\frac{1}{2}}(3) \cdot Q_{- \frac{1}{2}}^2(3) + \frac{3}{2}~ Q_{- \frac{1}{2}}(3)\cdot Q^2_{+ \frac{1}{2}}(3) = 0.945933522 \, . </math>


Attempting to simplify this expression, we have,

<math>~2C_0(\cosh\eta_0)</math>

<math>~=</math>

<math>~ \biggl\{ \cosh\eta_0 ~k_0~K(k_0) ~-~ \biggl(\frac{2}{k_0}\biggr) E(k_0) \biggr\} \times \biggl\{ \frac{ 4 \cosh\eta_0 ~E(k_0) - (\cosh\eta_0-1) K(k_0) }{ [2^{2} k_0^{-1} (\cosh\eta_0-1) ]} \biggr\} </math>

 

 

<math>~ - \frac{3}{2^2} \biggl[ k_0 ~K ( k_0) \biggr] \times \biggl\{ \cosh\eta_0~ k_0~K ( k_0 ) ~-~(\cosh^2\eta_0+3) \biggl[ \frac{k_0^2}{(\cosh\eta_0 - 1)^2} \biggr]^{1 / 2} E(k_0)

\biggr\} 

</math>

<math>~\Rightarrow ~~~ 2^3(\cosh\eta_0 - 1)C_0(\cosh\eta_0)</math>

<math>~=</math>

<math>~ \biggl\{ \cosh\eta_0 ~k_0^2~K(k_0) ~-~ 2 E(k_0) \biggr\} \times \biggl\{ 4 \cosh\eta_0 ~E(k_0) - (\cosh\eta_0-1) K(k_0) \biggr\} </math>

 

 

<math>~ - 3 k_0 ~K ( k_0) \times \biggl\{ \cosh\eta_0(\cosh\eta_0 - 1)~ k_0~K ( k_0 ) ~-~(\cosh^2\eta_0+3) k_0 E(k_0)

\biggr\} 

</math>

 

<math>~=</math>

<math>~ -~K(k_0)\cdot K(k_0) \biggl[ (\cosh\eta_0-1) \cdot \cosh\eta_0 ~k_0^2 + 3\cosh\eta_0~ (\cosh\eta_0~-1)k_0^2\biggr] </math>

 

 

<math>~ + K(k_0)\cdot E(k_0) \biggl[ 2^2 \cosh^2\eta_0 ~k_0^2 + 2(\cosh\eta_0 ~-1) + 3k_0^2 (\cosh^2\eta_0 ~ + 3)\biggr] - E(k_0)\cdot E(k_0) \biggl[2^3\cosh\eta_0 \biggr] </math>

<math>~\Rightarrow ~~~ \biggl[ \frac{ 2^3(\cosh\eta_0 - 1)}{k_0^2} \biggr] C_0(\cosh\eta_0)</math>

<math>~=</math>

<math>~ -~K(k_0)\cdot K(k_0) \biggl[ (\cosh\eta_0-1) \cdot \cosh\eta_0 + 3\cosh\eta_0~ (\cosh\eta_0~-1) \biggr] </math>

 

 

<math>~ + K(k_0)\cdot E(k_0) \biggl[ 2^2 \cosh^2\eta_0 + \frac{2}{k_0^2}(\cosh\eta_0 ~-1) + 3 (\cosh^2\eta_0 ~ + 3)\biggr] - E(k_0)\cdot E(k_0) \biggl[\frac{2^3\cosh\eta_0}{k_0^2} \biggr] </math>

<math>~\Rightarrow ~~~ (\cosh^2\eta_0 - 1) C_0(\cosh\eta_0)</math>

<math>~=</math>

<math>~ K(k_0)\cdot K(k_0) \biggl[ \cosh\eta_0(1 - \cosh\eta_0) \biggr] + 2K(k_0)\cdot E(k_0) \biggl[ \cosh^2\eta_0 + 1\biggr] - E(k_0)\cdot E(k_0) \biggl[ \cosh\eta_0(1 + \cosh\eta_0) \biggr] </math>

This last, simplifed expression gives, as above, <math>~C_0(3) = 0.945933523</math>. TERRIFIC!

Finally then, for any choice of <math>~\eta_0</math>,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W0}(\eta,\theta)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \frac{a}{ [ (\varpi + a)^2 + (z - Z_0)^2 ]^{1 / 2} } \cdot \boldsymbol{K}(k) </math>

 

 

<math>~ \times \biggl\{ K(k_0)\cdot K(k_0) [ \cosh\eta_0(1 - \cosh\eta_0) ] + 2K(k_0)\cdot E(k_0) [ \cosh^2\eta_0 + 1 ] - E(k_0)\cdot E(k_0) [ \cosh\eta_0(1 + \cosh\eta_0) ] \biggr\} \, . </math>

Second (n = 1) Term

The second (n = 1) term in Wong's (1973) expression for the exterior potential is,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\eta,\theta)</math>

<math>~=</math>

<math>~ -D_0 (\cosh\eta - \cos\theta)^{1 / 2} \cdot 2 \cos\theta \cdot C_1(\cosh\eta_0)P_{+\frac{1}{2}}(\cosh\eta) \, , </math>

where, <math>~D_0</math> is the same as above, and,

<math>~C_1(\cosh\eta_0)</math>

<math>~\equiv</math>

<math>~\tfrac{3}{2} Q_{+\frac{3}{2}}(\cosh \eta_0) Q_{+\frac{1}{2}}^2(\cosh \eta_0) + \tfrac{1}{2} Q_{+\frac{1}{2}}(\cosh \eta_0)~Q^2_{+ \frac{3}{2}}(\cosh \eta_0) \, . </math>

Now, from our accompanying table of "Toroidal Function Evaluations", it appears as though,

<math>~P_{+\frac{1}{2}}(\cosh\eta)</math>

<math>~=</math>

<math>~\frac{\sqrt{2}}{\pi} (\sinh\eta)^{+1 / 2} k^{-1} E(k) \, ,</math>

where, as above,

<math>~k</math>

<math>~\equiv</math>

<math>~\biggl[ \frac{2}{\coth\eta+1} \biggr]^{1 / 2} \, .</math>

Hence, we have,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\eta,\theta)</math>

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \biggl[ \cos\theta \cdot (\cosh\eta - \cos\theta)^{1 / 2} (\sinh\eta)^{+1 / 2} \biggr] k^{-1} E(k) </math>

 

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \cdot \cos\theta \biggl\{ \frac{a\sinh^2\eta}{\varpi} \cdot \frac{\coth\eta + 1}{2} \biggr\}^{1 / 2} E(k) </math>

 

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \cdot \cos\theta \biggl\{ \biggl( \frac{a}{2\varpi} \biggr) \biggl[ \frac{r_1^2 - r_2^2}{2r_1 r_2} \biggr]^2 \cdot \biggl[ \frac{2r_1^2}{r_1^2 - r_2^2} \biggr] \biggr\}^{1 / 2} E(k) </math>

 

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \cdot \cos\theta \biggl\{ \biggl( \frac{a}{2} \biggr)\biggl[ \frac{4a}{r_1^2 - r_2^2} \biggr] \biggl[ \frac{r_1^2 - r_2^2}{2r_1 r_2} \biggr]^2 \cdot \biggl[ \frac{2r_1^2}{r_1^2 - r_2^2} \biggr] \biggr\}^{1 / 2} E(k) </math>

 

<math>~=</math>

<math>~ - \frac{2^{3} a}{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \biggl[ \frac{\cos\theta}{r_2} \biggr] E(k) = - \frac{2^{3} a}{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \biggl[ \frac{\cos\theta}{\sqrt{ (\varpi - a)^2 + (z-Z_0)^2 }} \biggr] E(k) </math>

 

<math>~=</math>

<math>~ - \frac{2^{3} a}{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \biggl[\frac{ r_1^2 + r_2^2 - 4a^2}{2r_1 r_2^2} \biggr] \boldsymbol{E}(k) \, . </math>

 

From the above function tabulations & evaluations — for example, <math>~ K(k_0) = 1.854074677</math> and <math>~ E(k_0) = 1.350643881</math> — and a separate listing of Example Recurrence Relations, we have,

Appendix Expression: <math>~Q_{-\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~k_0 K(k_0)</math>

Appendix Expression: <math>~Q_{+\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0)</math>

<math>~Q^0_{m-\tfrac{1}{2}}</math> recurrence with m = 2: <math>~Q_{+\tfrac{3}{2}}(z_0)</math>

<math>~=</math>

<math>~\frac{4}{3} z~Q_{+\tfrac{1}{2}}(z_0) - \frac{1}{3} Q_{-\tfrac{1}{2}}(z_0)</math>

 

<math>~=</math>

<math>~\frac{4}{3} z \{z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0)\} - \frac{1}{3}k_0 K(k_0)</math>

 

<math>~=</math>

<math>~\frac{1}{3} \biggl[ (4z^2 - 1 )k_0 K(k_0) - 4 z[2(z+1)]^{1 / 2} E(k_0) \biggr] </math>

Hence, <math>~Q_{+\tfrac{3}{2}}(3)</math>

<math>~=</math>

<math>~0.014544576 \, .</math>


Appendix Expression: <math>~Q^2_{-\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~[2^3(z-1)(z^2-1)]^{-1 / 2} [4zE(k_0) - (z-1)K(k_0)]</math>

Additional derivation: <math>~Q^2_{+\tfrac{1}{2}}(z_0)</math>

<math>~=</math>

<math>~ -~\frac{1}{2^2} \biggl\{ z k_0~K ( k_0 ) ~-~(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} E(k_0)\biggr\} </math>

Then, letting <math>~\mu \rightarrow 2</math> and, for all m ≥ 2, letting <math>~\nu \rightarrow (m - \tfrac{1}{2})</math> in the "Key Equation,"

LSU Key.png

<math>~(\nu - \mu + 1)P^\mu_{\nu + 1} (z)</math>

<math>~=</math>

<math>~ (2\nu + 1)z P_\nu^\mu(z) - (\nu + \mu)P^\mu_{\nu-1}(z) </math>

Abramowitz & Stegun (1995), p. 334, eq. (8.5.3)

NOTE: <math>~Q_\nu^\mu</math>, as well as <math>~P_\nu^\mu</math>, satisfies this same recurrence relation.

we have,

<math>~(m - \tfrac{3}{2})Q^{2}_{m+\tfrac{1}{2}} (z)</math>

<math>~=</math>

<math>~ (2m)z Q_{m-\tfrac{1}{2}}^{2}(z) - (m + \tfrac{3}{2})Q^{2}_{m - \tfrac{3}{2}}(z) \, . </math>

Therefore, specifically for m = 1, we obtain the recurrence relation,

<math>~Q^{2}_{+\tfrac{3}{2}} (z_0)</math>

<math>~=</math>

<math>~ 5 Q^{2}_{- \tfrac{1}{2}}(z_0)-4z Q_{+\tfrac{1}{2}}^{2}(z_0) </math>

 

<math>~=</math>

<math>~ 5 \biggl\{ [2^3(z-1)(z^2-1)]^{-1 / 2} [4zE(k_0) - (z-1)K(k_0)] \biggr\} + z \biggl\{ z k_0~K ( k_0 ) ~-~(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} E(k_0)\biggr\} </math>

 

<math>~=</math>

<math>~ 2^{1 / 2}[ (z-1)(z^2-1) ]^{- 1 / 2} \biggl\{ [5 z] ~-~z (z^2+3) \biggr\} E(k_0) + \biggl\{ z^2 k_0~ - [(z-1)(z^2-1)]^{-1 / 2} [ 2^{-3 / 2} \cdot 5 (z-1)] \biggr\}K(k_0) </math>

 

<math>~=</math>

<math>~ 2^{-3 / 2}(z+1)^{-1 / 2} [4 z^2 - 5 ]K(k_0) -~2^{1 / 2}[ (z-1)(z^2-1) ]^{- 1 / 2} (z^2 - 2)z E(k_0) </math>

Hence, <math>~Q^{2}_{+\tfrac{3}{2}} (3)</math>

<math>~=</math>

<math>~ 0.132453829 \, . </math>


<math>~\Rightarrow ~~~ C_1(3)</math>

<math>~=</math>

<math>~ \frac{3}{2}~Q_{+\frac{3}{2}}(3) \cdot Q_{+ \frac{1}{2}}^2(3) + \frac{1}{2}~ Q_{+ \frac{1}{2}}(3)\cdot Q^2_{+ \frac{3}{2}}(3) = 0.017278633 \, . </math>


While keeping in mind that,

<math>~z_0</math>

<math>~=</math>

<math>~\cosh\eta_0 \, ,</math>

      and,      

<math>~k_0^2</math>

<math>~=</math>

<math>~\frac{2}{\cosh\eta_0 + 1} = \frac{2}{z_0 + 1} \, ,</math>

let's attempt to express this leading coefficient, <math>~C_1(\cosh\eta_0)</math>, entirely in terms of the pair of complete elliptic integral functions.

<math>~2C_1(z_0)</math>

<math>~=</math>

<math>~3 \biggl[ Q_{+\frac{3}{2}}(z_0) \biggr]\times \biggl[ Q_{+\frac{1}{2}}^2(z_0) \biggr] + \biggl[ Q_{+\frac{1}{2}}(z_0) \biggr]\times \biggl[ 5 Q^{2}_{- \tfrac{1}{2}}(z_0)-4z Q_{+\tfrac{1}{2}}^{2}(z_0) \biggr] </math>

 

<math>~=</math>

<math>~\biggl[3 Q_{+\frac{3}{2}}(z_0) -4z Q_{+\frac{1}{2}}(z_0) \biggr]\times \biggl[ Q_{+\frac{1}{2}}^2(z_0) \biggr] + \biggl[ 5Q_{+\frac{1}{2}}(z_0) \biggr]\times \biggl[ Q^{2}_{- \tfrac{1}{2}}(z_0) \biggr] </math>

 

<math>~=</math>

<math>~-~\frac{1}{2^2}\biggl\{ (4z^2 - 1 )k_0 K(k_0) - 4 z[2(z+1)]^{1 / 2} E(k_0) -4z \biggl[ z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0) \biggr] \biggr\} \times \biggl\{ z k_0~K ( k_0 ) ~-~(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} E(k_0) \biggr\} </math>

 

 

<math>~ + 5\biggl[ ~z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0) \biggr] \times \biggl\{ [2^3(z-1)(z^2-1)]^{-1 / 2} [4zE(k_0) - (z-1)K(k_0)] \biggr\} </math>

 

<math>~=</math>

<math>~\frac{1}{2^2} \cdot k_0 K(k_0) \times \biggl\{ z k_0~K ( k_0 ) ~-~(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} E(k_0) \biggr\} </math>

 

 

<math>~ + 5[2^3(z-1)(z^2-1)]^{-1 / 2} \biggl[ ~z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0) \biggr] \times \biggl\{ 4zE(k_0) - (z-1)K(k_0) \biggr\} </math>

 

<math>~=</math>

<math>~ K(k_0)\cdot K(k_0) \biggl\{ \frac{z k_0^2}{2^2} - 5[2^3(z-1)(z^2-1)]^{-1 / 2} \cdot zk_0(z-1)\biggr\} + E(k_0)\cdot E(k_0) \biggl\{ -5[2^3(z-1)(z^2-1)]^{-1 / 2}\cdot [2(z+1)]^{1 / 2} \cdot 4z \biggr\} </math>

 

 

<math>~ +~K(k_0)\cdot E(k_0) \biggl\{ -~\frac{1}{2^2} \cdot k_0(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} + 5[2^3(z-1)(z^2-1)]^{-1 / 2} \cdot 4z^2k_0 + 5[2^3(z-1)(z^2-1)]^{-1 / 2}\cdot [2(z+1)]^{1 / 2} \cdot (z-1) \biggr\} \, . </math>

Hence,

<math>~2[(z-1)(z^2-1)]^{1 / 2} C_1(z_0)</math>

<math>~=</math>

<math>~ z k_0 \cdot K(k_0)\cdot K(k_0) \biggl\{ \frac{k_0}{2^2} \biggl[(z-1)(z^2-1) \biggr]^{1 / 2} - \frac{5(z-1)}{2^{3/2}} \biggr\} -~10 z(z+1)^{1 / 2} \cdot E(k_0)\cdot E(k_0) </math>

 

 

<math>~ +~2^{-3/2} K(k_0)\cdot E(k_0) \biggl\{ k_0[19z^2 - 3 ] + 5(z-1) [2(z+1)]^{1 / 2} \biggr\} </math>

<math>~\Rightarrow ~~~2^{3/2}\biggl[ \frac{(z-1)}{k_0} \biggr] C_1(z_0)</math>

<math>~=</math>

<math>~ z k_0 \cdot K(k_0)\cdot K(k_0) \biggl\{ \frac{k_0}{2^2} \biggl[\frac{2^{1 / 2}(z-1)}{k_0} \biggr] - \frac{5(z-1)}{2^{3/2}} \biggr\} -~\biggl[ \frac{2^{3 / 2} \cdot 5z}{k_0} \biggr] E(k_0)\cdot E(k_0) </math>

 

 

<math>~ +~2^{-3/2} K(k_0)\cdot E(k_0) \biggl\{ k_0[19z^2 - 3 ] + \frac{10 (z-1)}{k_0} \biggr\} </math>

<math>~\Rightarrow ~~~C_1(z_0)</math>

<math>~=</math>

<math>~ \biggl[ \frac{2(3z^2 - 1)}{(z^2-1)} \biggr]K(k_0)\cdot E(k_0) -~\biggl[ \frac{z}{(z+1)} \biggr] K(k_0)\cdot K(k_0) -~\biggl[ \frac{ 5z}{(z-1)} \biggr] E(k_0)\cdot E(k_0) </math>

<math>~\Rightarrow ~~~(z_0^2-1)C_1(z_0)</math>

<math>~=</math>

<math>~ 2(3z^2 - 1) K(k_0)\cdot E(k_0) -~z_0(z_0-1) K(k_0)\cdot K(k_0) -~5z_0(z_0+1) E(k_0)\cdot E(k_0) \, . </math>

Hence, we have,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\eta,\theta)</math>

<math>~=</math>

<math>~ - \frac{2^{3} a}{3\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_1(\cosh\eta_0) \biggl[\frac{ r_1^2 + r_2^2 - 4a^2}{2r_1 r_2^2} \biggr] \boldsymbol{E}(k) \, . </math>

Third (n = 2) Term

Part A

The third (n = 2) term in Wong's (1973) expression for the exterior potential is,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W2}(\eta,\theta)</math>

<math>~=</math>

<math>~ -D_0 (\cosh\eta - \cos\theta)^{1 / 2} \cdot 2 \cos(2\theta) \cdot C_2(\cosh\eta_0)P_{+\frac{3}{2}}(\cosh\eta) \, , </math>

where, <math>~D_0</math> is the same as above, and,

<math>~C_2(\cosh\eta_0)</math>

<math>~\equiv</math>

<math>~\tfrac{5}{2}Q_{+\frac{5}{2}}(\cosh \eta_0) Q_{+\frac{3}{2}}^2(\cosh \eta_0) - \tfrac{1}{2} Q_{+\frac{3}{2}}(\cosh \eta_0)~Q^2_{+ \frac{5}{2}}(\cosh \eta_0) \, . </math>

In order to evaluate <math>~C_2(z)</math>, we will need the following pair of expressions in addition to the ones already used:

<math>~Q^0_{m-\tfrac{1}{2}}</math> recurrence with m = 3, gives:     <math>~Q_{+\tfrac{5}{2}}(z_0)</math>

<math>~=</math>

<math>~\frac{8}{5} z~Q_{+\tfrac{3}{2}}(z_0) - \frac{3}{5} Q_{+\tfrac{1}{2}}(z_0)</math>

<math>~\Rightarrow~~~15Q_{+\tfrac{5}{2}}(z_0)</math>

<math>~=</math>

<math>~8 z~\biggl[ (4z^2 - 1 )k_0 K(k_0) - 4 z[2(z+1)]^{1 / 2} E(k_0) \biggr] - 9 \biggl[ z~k_0 K(k_0) - [2(z+1)]^{1 / 2} E(k_0) \biggr]</math>

 

<math>~=</math>

<math>~ z~k_0 K(k_0) \biggl[ 8(4z^2 - 1 ) - 9 \biggr] + [2(z+1)]^{1 / 2} E(k_0) \biggl[-32z^2 + 9 \biggr] </math>

 

<math>~=</math>

<math>~ z~k_0 K(k_0) [ 32z^2 - 17 ] + [2(z+1)]^{1 / 2} E(k_0) [9 -32z^2 ] \, . </math>

Hence,     <math>~Q_{+\frac{5}{2}}(3)</math>

<math>~=</math>

<math>~0.002080867 \, .</math>

And, setting m = 2 in the above recurrence relation for <math>~Q^2_{m+\frac{1}{2}}(z)</math> gives,

<math>~\biggl[ (m - \tfrac{3}{2})Q^{2}_{m+\tfrac{1}{2}} (z) \biggr]_{m=2}</math>

<math>~=</math>

<math>~ \biggl[ (2m)z Q_{m-\tfrac{1}{2}}^{2}(z) - (m + \tfrac{3}{2})Q^{2}_{m - \tfrac{3}{2}}(z) \biggr]_{m=2} </math>

<math>~\Rightarrow ~~~ Q^{2}_{+\tfrac{5}{2}} (z) </math>

<math>~=</math>

<math>~ 8z Q_{+\tfrac{3}{2}}^{2}(z) - 7 Q^{2}_{+ \tfrac{1}{2}}(z) </math>

 

<math>~=</math>

<math>~ 8z \biggl[ 5 Q^{2}_{- \tfrac{1}{2}}(z_0)-4z Q_{+\tfrac{1}{2}}^{2}(z_0) \biggr] - 7 Q^{2}_{+ \tfrac{1}{2}}(z) </math>

 

<math>~=</math>

<math>~ 40z Q^{2}_{- \tfrac{1}{2}}(z_0) - [32z^2 +7]Q_{+\tfrac{1}{2}}^{2}(z_0) </math>

 

<math>~=</math>

<math>~ 40z \biggl\{ [2^3(z-1)(z^2-1)]^{-1 / 2} [4zE(k_0) - (z-1)K(k_0)] \biggr\} </math>

 

 

<math>~ + \frac{[32z^2 +7]}{4} \biggl\{

z k_0~K ( k_0 )  

~-~(z^2+3) \biggl[ \frac{2}{(z-1)(z^2-1)} \biggr]^{1 / 2} E(k_0) \biggr\} </math>

<math>~\Rightarrow ~~~ 4Q^{2}_{+\tfrac{5}{2}} (z) </math>

<math>~=</math>

<math>~ 2^5\cdot 5z \biggl\{ 2^{1 / 2} [(z-1)(z^2-1)]^{-1 / 2} [zE(k_0) ] - 2^{-3 / 2}[(z-1)(z^2-1)]^{-1 / 2} [(z-1)K(k_0)] \biggr\} </math>

 

 

<math>~ + [32z^2 +7] \biggl\{

z k_0~K ( k_0 )  

~-~2^{1 / 2}(z^2+3) [ (z-1)(z^2-1) ]^{-1 / 2} E(k_0) \biggr\} </math>

 

<math>~=</math>

<math>~ \biggl\{ 2^{11 / 2}\cdot 5 [z^2 ] - 2^{1 / 2} [32z^2 +7] (z^2+3) \biggr\}[(z-1)(z^2-1)]^{-1 / 2} E(k_0) </math>

 

 

<math>~ -~2^{7 / 2}\cdot 5 \biggl\{ [(z-1)(z^2-1)]^{-1 / 2} (z-1) \biggr\} z K(k_0) + [32z^2 +7] \biggl\{ 2^{1 / 2}[z + 1]^{-1 / 2} \biggr\} z K ( k_0 ) </math>

 

<math>~=</math>

<math>~ 2^{1 / 2}\biggl\{ 32z^2 - 33 \biggr\} z [z + 1]^{-1 / 2} K ( k_0 ) -~2^{1 / 2} \biggl\{ 32z^4 - 57 z^2 + 21 \biggr\}[(z-1)(z^2-1)]^{-1 / 2} E(k_0) </math>

 

<math>~=</math>

<math>~ 2^{1 / 2}[z + 1]^{-1 / 2} [z-1]^{-1 }\biggl[ (32z^2 - 33) z (z-1) K ( k_0 ) -~(32z^4 - 57 z^2 + 21)E(k_0) \biggr] \, . </math>

Hence,     <math>~Q^2_{+\frac{5}{2}}(3)</math>

<math>~=</math>

<math>~0.03377378 \, .</math>

Part B

Let's evaluate <math>~C_2(z)</math> specifically for the case where <math>~z = \cosh\eta_0 = 3</math>, using the already separately evaluated values of the four relevant toroidal functions. We find,

<math>~2C_2(3)</math>

<math>~=</math>

<math>~5Q_{+\frac{5}{2}}(3) Q_{+\frac{3}{2}}^2(3) - Q_{+\frac{3}{2}}(3)~Q^2_{+ \frac{5}{2}}(3) </math>

 

<math>~=</math>

<math>~ 5\cdot ( 0.002080867 ) \times ( 0.132453829 ) - ( 0.014544576 ) \times (0.03377378 ) </math>

 

<math>~=</math>

<math>~ 8.868687\times 10^{-4} \, . </math>

Next, let's develop a consolidated expression for <math>~C_2(z_0)</math> that replaces all the toroidal functions with complete elliptic integrals of the first and second kind.

<math>~2C_2(z_0)</math>

<math>~=</math>

<math>~5Q_{+\frac{5}{2}}(z_0) Q_{+\frac{3}{2}}^2(z_0) - Q_{+\frac{3}{2}}(z_0)~Q^2_{+ \frac{5}{2}}(z_0) </math>

 

<math>~=</math>

<math>~ \frac{1}{3}\biggl\{ z~k_0 K(k_0) [ 32z^2 - 17 ] + [2(z+1)]^{1 / 2} E(k_0) [9 -32z^2 ] \biggr\} \times \biggl\{ 2^{-3 / 2}(z+1)^{-1 / 2} [4 z^2 - 5 ]K(k_0) -~2^{1 / 2}[ (z-1)(z^2-1) ]^{- 1 / 2} (z^2 - 2)z E(k_0) \biggr\} </math>

 

 

<math>~ - \frac{1}{2^2\cdot 3} \biggl\{ (4z^2 - 1 )k_0 K(k_0) - 4 z[2(z+1)]^{1 / 2} E(k_0) \biggr\} \times \biggl\{ 2^{1 / 2}[z + 1]^{-1 / 2} [z-1]^{-1 }\biggl[ (32z^2 - 33) z (z-1) K ( k_0 ) -~(32z^4 - 57 z^2 + 21)E(k_0) \biggr] \biggr\} </math>

<math>~\Rightarrow ~~~ 2^{2} \cdot 3 (z^2-1) C_2(z_0)</math>

<math>~=</math>

<math>~ \biggl\{ K(k_0) z[ 32z^2 - 17 ] + (z+1) E(k_0) [9 -32z^2 ] \biggr\} \times \biggl\{ (z-1) [4 z^2 - 5 ]K(k_0) -~4 (z^2 - 2)z E(k_0) \biggr\} </math>

 

 

<math>~ - ~ \biggl\{ (4z^2 - 1 ) K(k_0) - 4 z(z+1) E(k_0) \biggr\} \times \biggl\{ (32z^2 - 33) z (z-1) K ( k_0 ) -~(32z^4 - 57 z^2 + 21)E(k_0) \biggr\} </math>

 

<math>~=</math>

<math>~ \biggl\{ (z-1)[ 32z^2 - 17 ] [4 z^2 - 5 ]z K(k_0) \cdot K(k_0) -~4 (z^2 - 2)z^2 [ 32z^2 - 17 ] K(k_0) \cdot E(k_0) \biggr\} </math>

 

 

<math>~ + \biggl\{ (z-1) (z+1) [9 -32z^2 ] [4 z^2 - 5 ]K(k_0) \cdot E(k_0) -~4 (z^2 - 2)z (z+1) [9 -32z^2 ] E(k_0) \cdot E(k_0) \biggr\} </math>

 

 

<math>~ + ~ \biggl\{ (32z^4 - 57 z^2 + 21)(4z^2 - 1 ) K(k_0) \cdot E(k_0) -~(32z^2 - 33) z (z-1)(4z^2 - 1 ) K ( k_0 ) \cdot K(k_0) \biggr\} </math>

 

 

<math>~ + ~ \biggl\{ 4 z(z+1)(32z^2 - 33) z (z-1) K ( k_0 ) \cdot E(k_0) -~4 z(z+1)(32z^4 - 57 z^2 + 21)E(k_0) \cdot E(k_0) \biggr\} </math>

 

<math>~=</math>

<math>~(z-1)\biggl\{ \biggl[ ( 32z^2 - 17 ) (4 z^2 - 5 )z \biggr] -~\biggl[ (32z^2 - 33) z (4z^2 - 1 ) \biggr] \biggr\} K ( k_0 ) \cdot K(k_0) </math>

 

 

<math>~ + \biggl\{ \biggl[ (z-1) (z+1) (9 -32z^2 ) (4 z^2 - 5 )\biggr] -~\biggl[ 4 (z^2 - 2)z^2 ( 32z^2 - 17 ) \biggr] </math>

 

 

<math>~ + ~ \biggl[ (32z^4 - 57 z^2 + 21)(4z^2 - 1 ) \biggr] + ~ \biggl[ 4 z(z+1)(32z^2 - 33) z (z-1)\biggr]\biggr\} K ( k_0 ) \cdot E(k_0) </math>

 

 

<math>~ -~2z(z+1) \biggl\{ \biggl[ 2 (32z^4 - 57 z^2 + 21) \biggr] +~2\biggl[ (z^2 - 2) (9 -32z^2 )\biggr] \biggr\} E(k_0) \cdot E(k_0) </math>

 

<math>~=</math>

<math>~ z(z-1)\biggl\{[ 52 - 64z^2 ] \biggr\} K ( k_0 ) \cdot K(k_0) -~4z(z+1) \biggl\{ [ 3 +16z^2 ]\biggr\} E(k_0) \cdot E(k_0) </math>

 

 

<math>~ + \biggl\{ \biggl[ 5(32z^4 - 41z^2 + 9 ) \biggr] - \biggl[ (32z^4 - 57 z^2 + 21)\biggr] </math>

 

 

<math>~ + ~ 4z^2\biggl[ (32z^4 - 57 z^2 + 21) + (32z^4 - 65z^2 + 33) + (-32z^4 + 41z^2 -9 ) +~( -32z^4 + 81z^2 - 34 )

\biggr]\biggr\}  K ( k_0 ) \cdot E(k_0)

</math>

 

<math>~=</math>

<math>~ 4z(z-1)\biggl\{ 13 - 16z^2 \biggr\} K ( k_0 ) \cdot K(k_0) -~4z(z+1) \biggl\{ [ 3 +16z^2 ]\biggr\} E(k_0) \cdot E(k_0) + 8\biggl\{ 16z^4 -13z^2 + 3 \biggr\} K ( k_0 ) \cdot E(k_0) \, . </math>

Finally, let's evaluate this consolidated expression for the specific case of <math>~z_0 = \cosh\eta_0 = 3</math>, remembering that in this specific case <math>~k_0 = 2^{-1 / 2}</math>, <math>~K(k_0) = 1.854074677</math>, and <math>~E(k_0) = 1.350643881</math>. We find,

<math>~2C_2(z_0)</math>

<math>~=</math>

<math>~ [2 \cdot 3 (z^2-1) ]^{-1} \biggl\{ 4z(z-1) [ 13 - 16z^2 ] K ( k_0 ) \cdot K(k_0) -~4z(z+1) [ 3 +16z^2 ] E(k_0) \cdot E(k_0) + 8[ 16z^4 -13z^2 + 3 ] K ( k_0 ) \cdot E(k_0) \biggr\} </math>

 

<math>~=</math>

<math>~ [48 ]^{-1} \biggl\{ -24[ 131 ] K ( k_0 ) \cdot K(k_0) -~48 [ 147] E(k_0) \cdot E(k_0) + 8[ 1182 ] K ( k_0 ) \cdot E(k_0) \biggr\} </math>

 

<math>~=</math>

<math>~ 8.8708 \times 10^{-4} \, . </math>

This matches the numerically evaluated expression, from above (6/30/2020). There is a tremendous amount of cancellation between the three key terms in this expression, so the match is only to three significant digits.

Part C

Next …

Useful Relations from Above

<math>~\cosh\eta</math>

<math>~=</math>

<math>~\frac{r_1^2 + r_2^2}{2r_1 r_2} \, ;</math>

<math>~\sinh\eta</math>

<math>~=</math>

<math>~\frac{r_1^2 - r_2^2}{2r_1 r_2} \, ;</math>

<math>~\varpi</math>

<math>~=</math>

<math>~\frac{r_1^2 - r_2^2}{2a} \, ;</math>

<math>~\cosh\eta - \cos\theta</math>

<math>~=</math>

<math>~\frac{2a^2}{r_1 r_2} \, ;</math>

<math>~ \cos\theta</math>

<math>~=</math>

<math>~\frac{r_1^2 + r_2^2-4a^2}{2r_1 r_2} \, ;</math>

<math>~\frac{2}{\coth\eta + 1}</math>

<math>~=</math>

<math>~\frac{4a\varpi}{r_1^2} \, .</math>


Now, from our tabulation of example recurrence relations, we see that,

<math>~ P_{+\frac{3}{2}}(\cosh\eta)</math>

<math>~=</math>

<math>~\frac{4}{3} \cdot \cosh\eta ~P_{+\frac{1}{2}}(\cosh\eta) - \frac{1}{3} ~ P_{-\frac{1}{2}}(\cosh\eta) </math>

 

<math>~=</math>

<math>~\frac{4}{3} \cdot \cosh\eta \biggl[ \frac{\sqrt{2}}{\pi} (\sinh\eta)^{+1 / 2} k^{-1} \boldsymbol{E}(k) \biggr] - \frac{1}{3} ~ \biggl[ \frac{\sqrt{2}}{\pi}~ (\sinh\eta)^{-1 / 2} ~k \boldsymbol{K}(k)\biggr]</math>

 

<math>~=</math>

<math>~\frac{2^{1 / 2}}{3\pi} \biggl[ 4 \cosh\eta (\sinh\eta)^{+1 / 2} k^{-1} \boldsymbol{E}(k) - (\sinh\eta)^{-1 / 2} ~k \boldsymbol{K}(k)\biggr] \, ,</math>

where, as above,

<math>~ k \equiv \biggl[ \frac{2}{\coth\eta + 1} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{(\varpi + a)^2 + (z - Z_0)^2} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{r_1^2} \biggr]^{1 / 2} \, . </math>

So we have,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W2}(\eta,\theta)</math>

<math>~=</math>

<math>~ -\frac{2^{5/2} }{3\pi^2} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_2(\cosh\eta_0)\cos(2\theta) \biggl\{ (\cosh\eta - \cos\theta)^{1 / 2}P_{+\frac{3}{2}}(\cosh\eta) \biggr\} </math>

 

<math>~=</math>

<math>~ -\frac{2^{3} }{3^2\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_2(\cosh\eta_0)\cos(2\theta)\biggl( \frac{2a^2}{r_1 r_2}\biggr)^{1 / 2} \biggl\{ 4 \cosh\eta (\sinh\eta)^{+1 / 2} k^{-1} \boldsymbol{E}(k) - (\sinh\eta)^{-1 / 2} ~k \boldsymbol{K}(k) \biggr\} </math>

 

<math>~=</math>

<math>~ -\frac{2^{3} }{3^2\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_2(\cosh\eta_0)\cos(2\theta)\biggl( \frac{2a^2}{r_1 r_2}\biggr)^{1 / 2} </math>

 

 

<math>~ \times \biggl\{ 4 \biggl[ \frac{r_1^2 + r_2^2}{2r_1 r_2} \biggr] \biggl[\frac{r_1^2 - r_2^2}{2r_1 r_2} \biggr]^{+1 / 2} \biggl[ \frac{4a}{r_1^2} \biggl( \frac{r_1^2 - r_2^2}{2a} \biggr)\biggr]^{-1 / 2} \boldsymbol{E}(k) - \biggl[ \frac{r_1^2 - r_2^2}{2r_1 r_2} \biggr]^{-1 / 2} ~\biggl[ \frac{4a}{r_1^2}\biggl( \frac{r_1^2 - r_2^2}{2a} \biggr) \biggr]^{1 / 2} \boldsymbol{K}(k) \biggr\} </math>

 

<math>~=</math>

<math>~ -\frac{2^{9/2} }{3^2\pi^3} \biggl[ \frac{\sinh^3\eta_0}{\cosh\eta_0}\biggr] C_2(\cosh\eta_0)\cos(2\theta) \times \biggl\{ \biggl[ \frac{r_1^2 + r_2^2}{2r_1 r_2} \biggr] \frac{a}{r_2} \cdot \boldsymbol{E}(k) - \frac{a}{r_1} \cdot \boldsymbol{K}(k) \biggr\} \, . </math>

Finally, inserting the expression for <math>~\sinh^2\eta_0~ C_2(\cosh\eta_0) = (z_0^2-1)C_2(z_0)</math> that we have derived, above, gives,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W2}(\eta,\theta)</math>

<math>~=</math>

<math>~ -\frac{2^{9/2} }{3^3\pi^3} \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \times \cos(2\theta) \biggl\{ \biggl[ \frac{r_1^2 + r_2^2}{2r_1 r_2} \biggr] \frac{a}{r_2} \cdot \boldsymbol{E}(k) - \frac{a}{r_1} \cdot \boldsymbol{K}(k) \biggr\} </math>

 

 

<math>~ \times \biggl\{ z(z-1) [ 13 - 16z^2 ] K ( k_0 ) \cdot K(k_0) -~z(z+1) [ 3 +16z^2 ] E(k_0) \cdot E(k_0) + 2 [ 16z^4 -13z^2 + 3 ] K ( k_0 ) \cdot E(k_0) \biggr\} \, . </math>

Summary

Once the major ( R ) and minor ( d ) radii of the torus have been specified, two key model parameters can be immediately determined, namely,

<math>~a^2 \equiv R^2 - d^2\, ,</math>       and,       <math>~\cosh\eta_0 \equiv \frac{R}{d} \, ,</math>

in which case also, <math>~\sinh\eta_0 = a/d \, .</math> Once the mass-density ( ρ0 ) of the torus has been specified, the torus mass is given by the expression,

<math>~M = 2\pi^2 \rho_0 d^2 R \, .</math>

In addition to the principal pair of meridional-plane coordinates, <math>~(\varpi, z)</math>, it is useful to define the pair of distances,

<math>~r_1^2</math>

<math>~\equiv</math>

<math>~(\varpi + a)^2 + (z - Z_0)^2 \, ,</math>

<math>~r_2^2</math>

<math>~\equiv</math>

<math>~(\varpi - a)^2 + (z - Z_0)^2 \, ,</math>

where, the equatorial plane of the torus is located at <math>~z = Z_0</math>. As we have shown above, the leading (n = 0) term in Wong's (1973) series-expression for the gravitational potential anywhere outside the torus is,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W0}(\varpi,z)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \frac{a}{ r_1 } \cdot \boldsymbol{K}(k) </math>

 

 

<math>~ \times \biggl\{ K(k_0)\cdot K(k_0) [ \cosh\eta_0(1 - \cosh\eta_0) ] + 2K(k_0)\cdot E(k_0) [ \cosh^2\eta_0 + 1 ] - E(k_0)\cdot E(k_0) [ \cosh\eta_0(1 + \cosh\eta_0) ] \biggr\} \, . </math>

where, the two distinctly different arguments — one with, and one without a zero subscript — of the complete elliptic-integral functions are,

<math>~k</math>

<math>~\equiv</math>

<math>~ \biggl[ \frac{2}{\coth\eta + 1} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{(\varpi + a)^2 + (z - Z_0)^2} \biggr]^{1 / 2} = \biggl[ \frac{4a\varpi}{r_1^2} \biggr]^{1 / 2} = \biggl[ \frac{r_1^2 - r_2^2}{r_1^2} \biggr]^{1 / 2} \, , </math>

<math>~k_0</math>

<math>~\equiv</math>

<math>~ \biggl[ \frac{2}{\cosh\eta_0 + 1} \biggr]^{1 / 2} \, . </math>

As we also have shown above, the second (n = 1) term in Wong's (1973) series-expression for the exterior gravitational potential is,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\varpi,z)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \biggl[\frac{ r_1^2 + r_2^2 - 4a^2}{2r_1 r_2} \biggr] \frac{a}{r_2} \cdot \boldsymbol{E}(k) </math>

 

 

<math>~\times \biggl\{ K(k_0)\cdot K(k_0) [\cosh\eta_0(1 - \cosh\eta_0)] +~2K(k_0)\cdot E(k_0) [(3\cosh^2\eta_0 - 1)] -~5 E(k_0)\cdot E(k_0) [\cosh\eta_0(1+\cosh\eta_0)] \biggr\} \, . </math>

Note that a transformation from the <math>~(r_1, r_2)</math> coordinate pair to the toroidal-coordinate pair <math>~(\eta, \theta)</math> includes the expression,

<math>~\cos\theta</math>

<math>~=</math>

<math>~ \frac{r_1^2 + r_2^2 - 4a^2}{2r_1 r_2} \, . </math>

So this (n = 1) term's explicit dependence on "cos(nθ)" is clear. Finally, the third (n = 2) term in Wong's (1973) series-expression for the exterior gravitational potential is,

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W2}(\eta,\theta)</math>

<math>~=</math>

<math>~ -\frac{2^{3} }{3\pi^3} \biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \times \cos(2\theta) \biggl\{ \biggl[ \frac{r_1^2 + r_2^2}{2r_1 r_2} \biggr] \frac{a}{r_2} \cdot \boldsymbol{E}(k) - \frac{a}{r_1} \cdot \boldsymbol{K}(k) \biggr\} </math>

 

 

<math>~ \times \frac{2^{3 / 2}}{3^2}\biggl\{ K ( k_0 ) \cdot K(k_0) \cdot \cosh\eta_0(1 - \cosh\eta_0) [ 16\cosh^2\eta_0 - 13] + 2 K ( k_0 ) \cdot E(k_0) [ 16\cosh^4\eta_0 -13\cosh^2\eta_0 + 3 ] </math>

 

 

<math>~ -~E(k_0) \cdot E(k_0) \cdot \cosh\eta_0 (1 + \cosh\eta_0) [ 3 +16\cosh^2\eta_0 ] \biggr\} \, . </math>

The Huré, et al (2020) Presentation


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Notation

In Huré, et al. (2020), the major and minor radii of the torus surface ("shell") are labeled, respectively, Rc and b, and their ratio is denoted,

<math>~e \equiv \frac{b}{R_c} \, .</math>

Huré, et al. (2020), §2, p. 5826, Eq. (1)

The authors work in cylindrical coordinates, <math>~(R, Z)</math>, whereas we refer to this same coordinate-pair as, <math>~(\varpi_W, z_W)</math>. The quantity,

<math>~\Delta^2</math>

<math>~\equiv</math>

<math>~ [R + (R_c + b\cos\theta_H)]^2 + [Z - b\sin\theta_H]^2 \, . </math>

Huré, et al. (2020), §2, p. 5826, Eqs. (5) & (7)

We have affixed the subscript "H" to their meridional-plane angle, θ, to clarify that it has a different coordinate-base definition from the meridional-plane angle, θ, that appears in our above discussion of Wong's (1973) work. In their paper, the subscript "0" is used in the case of an infinitesimally thin hoop <math>~(b \rightarrow 0)</math>, that is to say,

<math>~\Delta_0^2</math>

<math>~=</math>

<math>~ [R + R_c]^2 + Z^2 \, . </math>

Huré, et al. (2020), §3, p. 5827, Eq. (13)

Generally, the argument (modulus) of the complete elliptic integral functions is,

<math>~k_H</math>

<math>~=</math>

<math>~ \frac{2}{\Delta}\biggl[ R (R_c + b\cos\theta_H) \biggr]^{1 / 2} \, , </math>

Huré, et al. (2020), §2, p. 5826, Eq. (4)

and, as stated in the first sentence of their §3, reference may also be made to the complementary modulus,

<math>~k'_H</math>

<math>~\equiv</math>

<math>~[1 - k_H^2]^{1 / 2} \, .</math>

(Again, we have affixed the subscript "H" in order to differentiate from the modulus employed by Wong (1973).) And in the case of an infinitesimally thin hoop <math>~(b\rightarrow 0)</math>,

<math>~[k^2_H]_0</math>

<math>~=</math>

<math>~ \frac{4R R_c}{\Delta_0^2} \, . </math>

Huré, et al. (2020), §3, p. 5827, Eq. (12)

Key Finding

On an initial reading, it appears as though the most relevant section of the Huré, et al. (2020) paper is §8 titled, The Solid Torus. They write the gravitational potential in terms of the series expansion,

<math>~\Psi_\mathrm{grav}(\vec{r})</math>

<math>~\approx</math>

<math>~ \Psi_0 + \sum\limits_{n=1}^N \Psi_n \, , </math>

Huré, et al. (2020), §7, p. 5831, Eq. (42)

where, after setting <math>~M_\mathrm{tot} = 2\pi^2\rho_0 b^2 R_c </math> and acknowledging that <math>~V_{0,0} = 1 \, ,</math> we can write,

<math>~\Psi_0 </math>

<math>~=</math>

<math>~ - \frac{GM_\mathrm{tot}}{r} \biggl[ \frac{r}{\Delta_0} \cdot \frac{2}{\pi} \boldsymbol{K}([k_H]_0) \biggr] </math>

Huré, et al. (2020), §8, p. 5832, Eqs. (52) & (53)

and,

<math>~\frac{1}{e^2} \biggl[ \Psi_1 + \Psi_2 \biggr]</math>

<math>~=</math>

<math>~ - \frac{G\pi \rho_0 R_c b^2}{4 (k'_H)^2 \Delta_0^3} \biggl\{ [\Delta_0^2 - 2R_c(R_c + R)]\boldsymbol{E}(k_H) - (k'_H)^2 \Delta_0^2 \boldsymbol{K}(k_H) \biggr\} \, . </math>

Huré, et al. (2020), §8, p. 5832, Eq. (54)

Rewriting this last expression in a form that can more readily be compared with Wong's work, we obtain,

<math>~\frac{2^3\pi}{e^2} \biggl[ \frac{ \Psi_1 + \Psi_2 }{GM} \biggr]</math>

<math>~=</math>

<math>~ - \frac{ 1 }{(k'_H)^2 \Delta_0^3}\biggl\{ [\Delta_0^2 - 2R_c(R_c + R)]\boldsymbol{E}(k_H) - (k'_H)^2 \Delta_0^2 \boldsymbol{K}(k_H) \biggr\} </math>

 

<math>~=</math>

<math>~ - \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \frac{\boldsymbol{E}(k_H)}{\Delta_0} + \frac{\boldsymbol{K}(k_H)}{\Delta_0} \, . </math>

Hence, also,

<math>~ \frac{ \Psi_0 }{GM} + \biggl[ \frac{ \Psi_1 + \Psi_2 }{GM} \biggr]</math>

<math>~=</math>

<math>~- \frac{2}{\pi}\biggl\{ \frac{\boldsymbol{K}([k_H]_0)}{\Delta_0} \biggr\} + \frac{e^2}{2^3\pi}\biggl\{ \frac{\boldsymbol{K}(k_H)}{\Delta_0} - \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \frac{\boldsymbol{E}(k_H)}{\Delta_0} \biggr\} </math>

 

<math>~=</math>

<math>~- \frac{2}{\pi \Delta_0}\biggl\{ \boldsymbol{K}([k_H]_0) - \frac{e^2}{2^4} \cdot \boldsymbol{K}(k_H) \biggr\} - \frac{2}{\pi\Delta_0} \cdot \frac{e^2}{2^4}\biggl\{\biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \biggr\} \boldsymbol{E}(k_H) </math>

<math>~\Rightarrow ~~~- \frac{\pi \Delta_0}{2} \biggl[ \frac{ \Psi_0 + \Psi_1 + \Psi_2 }{GM} \biggr] </math>

<math>~=</math>

<math>~ \boldsymbol{K}([k_H]_0) - \frac{e^2}{2^4} \cdot \boldsymbol{K}(k_H) + \frac{e^2}{2^4} \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \boldsymbol{E}(k_H) \, . </math>

Compare First Terms

Rewriting the first term in the Huré, et al. (2020) series expression for the potential, we have,

<math>~\frac{\Psi_0}{GM} </math>

<math>~=</math>

<math>~ - \frac{2}{\pi} \biggl\{ \frac{\boldsymbol{K}([k_H]_0) }{[ (\varpi_W + R_c)^2 + z_W^2]^{1 / 2}} \biggr\} \, , </math>

where,

<math>~[k_H]_0</math>

<math>~=</math>

<math>~ \biggl[ \frac{4\varpi_W R_c}{\Delta_0^2} \biggr]^{1 / 2} = \biggl\{ \frac{4\varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2} \biggr\}^{1 / 2} \, . </math>

For comparison, the first term in Wong's expression is,

<math>~\frac{\Phi_\mathrm{W0}}{GM} </math>

<math>~=</math>

<math>~ - \biggl( \frac{2^{3} }{3\pi^3} \biggr) \Upsilon_{W0}(\eta_0) \biggl\{ \frac{\boldsymbol{K}(k) }{ r_1 } \biggr\}\, , </math>

where,

<math>~a^2 </math>

<math>~\equiv</math>

<math>~ R^2 - d^2 ~~~\Rightarrow ~~~ a = R_c(1 - e^2)^{1 / 2} \, , </math>

<math>~r_1^2</math>

<math>~\equiv</math>

<math>~\biggl[ \varpi + R_c (1 - e^2 )^{1 / 2}\biggr]^2 + \biggl[z - Z_0 \biggr]^2 \, ,</math>

<math>~k</math>

<math>~\equiv</math>

<math>~ \biggl\{ \frac{4\varpi R_c(1-e^2)^{1 / 2}}{[\varpi + R_c(1-e^2)^{1 / 2}]^2 + [z - Z_0]^2} \biggr\}^{1 / 2} \, , </math>

<math>~\Upsilon_{W0}(\eta_0)</math>

<math>~=</math>

<math>~ \frac{\sinh\eta_0}{\cosh\eta_0}\biggl\{ K(k_0)\cdot K(k_0) [ \cosh\eta_0(1 - \cosh\eta_0) ] + 2K(k_0)\cdot E(k_0) [ \cosh^2\eta_0 + 1 ] - E(k_0)\cdot E(k_0) [ \cosh\eta_0(1 + \cosh\eta_0) ] \biggr\} \, , </math>

 

<math>~=</math>

<math>~ \frac{(1-e^2)^{1 / 2}}{e^2} \biggl\{ - K(k_0)\cdot K(k_0) (1-e) + 2K(k_0)\cdot E(k_0) (1+e^2) - E(k_0)\cdot E(k_0) (1+e) \biggr\} \, , </math>

<math>~k_0</math>

<math>~=</math>

<math>~ \biggl[ \frac{2}{1+1/e} \biggr]^{1 / 2} = \biggl[ \frac{2e}{1+e} \biggr]^{1 / 2} \, . </math>

This expression is correct for any value of the aspect ratio, <math>~e</math>. But let's set <math>~Z_0 = 0</math> — as Huré, et al. (2020) have done — then see how the expression simplifies for an infinitesimally thin hoop, that is, if we let <math>~e \rightarrow 0</math>. First we note that,

<math>~k\biggr|_{e\rightarrow 0}</math>

<math>~=</math>

<math>~ \biggl\{ \frac{4\varpi R_c}{[\varpi + R_c]^2 + z^2} \biggr\}^{1 / 2} \, , </math>

so in this limit the modulus of the complete elliptic integral of the first kind becomes identical to the modulus used by Huré, et al. (2020), <math>~[k_H]_0</math>. Next, we note that,

<math>~r_1\biggr|_{e\rightarrow 0}</math>

<math>~=</math>

<math>~[( \varpi + R_c )^2 + z^2]^{1 / 2} \, .</math>

As a result, we can write,

<math>~\frac{\Phi_\mathrm{W0}}{GM} \biggr|_{e\rightarrow 0}</math>

<math>~=</math>

<math>~ \frac{\Psi_0}{GM} \cdot \biggl[ \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W0}(\eta_0) \biggr]_{e\rightarrow 0} \, . </math>

Now let's evaluate the coefficient, <math>~\Upsilon_{W0}</math>, in the limit of <math>~e \rightarrow 0</math>.


<math>~\Upsilon_{W0}</math>, in the limit of <math>~e \rightarrow 0</math>.

First, drawing from our separate examination of the behavior of complete elliptic integral functions, we appreciate that,

<math>~\frac{2^2}{\pi^2} \biggl[K(k_0) \cdot E(k_0) \biggr]</math>

<math>~=</math>

<math>~ 1 ~+~\frac{1}{2^5} ~k_0^4 ~+~\frac{1}{2^5} ~ k_0^6 + \mathcal{O}(k_0^{8}) \, , </math>

<math>~\frac{2^2}{\pi^2} \biggl[K(k_0) \cdot K(k_0) \biggr]</math>

<math>~=</math>

<math>~ 1 + \frac{1}{2} k_0^2 + \frac{11}{2^5} ~k_0^4 + \frac{17}{2^6} ~ k_0^6 + \mathcal{O}(k_0^{8}) \, , </math>

<math>~\frac{2^2}{\pi^2} \biggl[E(k_0) \cdot E(k_0) \biggr]</math>

<math>~=</math>

<math>~ 1 - \frac{1}{2} ~k_0^2 ~-~ \frac{1}{2^5} ~ k_0^4 ~-~\frac{1}{2^6} ~ k_0^6 + \mathcal{O}(k_0^{8}) \, . </math>

Next, employing the binomial expansion, we find that,

<math>~k_0^2</math>

<math>~=</math>

<math>~2e(1+e)^{-1}</math>

 

<math>~=</math>

<math>~2e( 1 - e +e^2 - e^3 + e^4 - e^5 + \cdots ) \, ;</math>

and,

<math>~k_0^4</math>

<math>~=</math>

<math>~4e^2(1+e)^{-2}</math>

 

<math>~=</math>

<math>~4e^2( 1 - 2e + 3e^2 - 4e^3 + 5e^4 - 6e^5 + \cdots ) \, .</math>

Hence, we have,

<math>~\frac{2^2}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W0}(\eta_0)</math>

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + \frac{1}{2} k_0^2 + \frac{11}{2^5} ~k_0^4 + \mathcal{O}(k_0^{6})

\biggr]

</math>

 

 

<math>~ + 2 (1+e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~k_0^4 + \mathcal{O}(k_0^{6})

\biggr]

</math>

 

 

<math>~ - (1+e) \biggl[ 1 - \frac{1}{2} ~k_0^2 ~-~ \frac{1}{2^5} ~ k_0^4 ~ + \mathcal{O}(k_0^{6}) \biggr] </math>

 

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + e ( 1 - e +e^2 - e^3 + e^4 - e^5 + \cdots ) + \frac{11}{2^3} \cdot ~e^2( 1 - 2e + 3e^2 - 4e^3 + 5e^4 - 6e^5 + \cdots ) + \mathcal{O}(e^{3})

\biggr]

</math>

 

 

<math>~ + 2 (1+e^2) \biggl[ 1 ~+~\frac{1}{2^3} \cdot~e^2( 1 - 2e + 3e^2 - 4e^3 + 5e^4 - 6e^5 + \cdots ) + \mathcal{O}(e^{3})

\biggr]

</math>

 

 

<math>~ - (1+e) \biggl[ 1 - e ~( 1 - e +e^2 - e^3 + e^4 - e^5 + \cdots ) ~ -~ \frac{1}{2^3} \cdot~ e^2( 1 - 2e + 3e^2 - 4e^3 + 5e^4 - 6e^5 + \cdots ) ~ + \mathcal{O}(e^{3}) \biggr] </math>

 

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + e ( 1 - e ) + \frac{11}{2^3} \cdot ~e^2

\biggr]

+ 2 (1+e^2) \biggl[ 1 ~+~\frac{1}{2^3} \cdot~e^2

\biggr]

- (1+e) \biggl[ 1 - e ~( 1 - e ) ~ -~ \frac{1}{2^3} \cdot~ e^2 ~ \biggr] + \mathcal{O}(e^{3}) </math>

 

<math>~=</math>

<math>~ - \biggl[ 1 + e ( 1 - e ) + \frac{11}{2^3} \cdot ~e^2

\biggr]

+e \biggl[ 1 + e \biggr] + 2 \biggl[ 1 ~+~\frac{1}{2^3} \cdot~e^2

\biggr]

+ 2 e^2 - \biggl[ 1 - e ~( 1 - e ) ~ -~ \frac{1}{2^3} \cdot~ e^2 ~ \biggr] - e \biggl[ 1 - e \biggr] + \mathcal{O}(e^{3}) </math>

 

<math>~=</math>

<math>~ -1 - e + e^2 - \frac{11}{2^3} \cdot ~e^2 + e + e^2 + 2 ~+~\frac{1}{2^2} \cdot~e^2 + 2 e^2 -1 + e - e^2 ~ +~ \frac{1}{2^3} \cdot~ e^2 ~ - e +e^2 + \mathcal{O}(e^{3}) </math>

 

<math>~=</math>

<math>~\frac{e^2}{2^3} \biggl[ 2^5 - 11~ ~+~3 \biggr]~ + \mathcal{O}(e^{3}) </math>

 

<math>~=</math>

<math>~ 3e^2 + \mathcal{O}(e^{3}) </math>

<math>~\Rightarrow ~~~ \frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>

<math>~=</math>

<math>~ [1 + \mathcal{O}(e^{1})]\cdot (1 - e^2)^{1 / 2} </math>

<math>~\Rightarrow ~~~ \biggl[ \frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0) \biggr]_{e\rightarrow 0}</math>

<math>~=</math>

<math>~ 1 \, .</math>

Given that,

<math>~ \biggl[ \frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0) \biggr]_{e\rightarrow 0}</math>

<math>~=</math>

<math>~ 1 \, ,</math>

we conclude that,

<math>~\frac{\Phi_\mathrm{W0}}{GM} \biggr|_{e\rightarrow 0}</math>

<math>~=</math>

<math>~ \frac{\Psi_0}{GM} \, , </math>

that is, we conclude that <math>~\Psi_0</math> matches <math>~\Phi_{W0}</math> in the limit of, <math>~e\rightarrow 0</math>.

Go to Higher Order

Let's keep higher order terms in Wong's n = 0 component, and let's examine contributions to the same order that come from Wong's n = 1 and (if necessary) n = 2 components.

First, note that,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \Delta_0 \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W0}(\eta_0) \biggl\{ \frac{\boldsymbol{K}(k) }{ r_1 } \biggr\}\, . </math>


Keeping Higher Order in Wong's First Component

<math>~\frac{2^2}{\pi^2} \biggl[K(k_0) \cdot E(k_0) \biggr]</math>

<math>~=</math>

<math>~ 1 ~+~\frac{1}{2^5} ~k_0^4 ~+~\frac{1}{2^5} ~ k_0^6 ~+~\frac{231}{2^{13}} ~ k_0^8 + \mathcal{O}(k_0^{10}) \, , </math>

<math>~\frac{2^2}{\pi^2} \biggl[K(k_0) \cdot K(k_0) \biggr]</math>

<math>~=</math>

<math>~ 1 + \frac{1}{2} k_0^2 + \frac{11}{2^5} ~k_0^4 + \frac{17}{2^6} ~ k_0^6 + \frac{1787}{2^{13}} ~k^8 + \mathcal{O}(k_0^{10}) \, , </math>

<math>~\frac{2^2}{\pi^2} \biggl[E(k_0) \cdot E(k_0) \biggr]</math>

<math>~=</math>

<math>~ 1 - \frac{1}{2} ~k_0^2 ~-~ \frac{1}{2^5} ~ k_0^4 ~-~\frac{1}{2^6} ~ k_0^6 ~-~\frac{77}{2^{13}} ~ k_0^8 + \mathcal{O}(k_0^{10}) \, . </math>

Add One Additional Term

<math>~\frac{2^2}{\pi^2} \biggl[K(k) \cdot E(k) \biggr]</math>

<math>~=</math>

<math>~ \biggl\{ 1 + \biggl( \frac{1}{2} \biggr)^2k^2 + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k^6 + \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 k^8 + \cdots + \biggl[ \frac{(2n-1)!!}{2^n n!} \biggr]^2 k^{2n} + \cdots \biggr\} </math>

 

 

<math>~ \times~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{1^2\cdot 3}{2^2\cdot 4^2}~ k^4 - \biggl(\frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2~\frac{ k^6 }{5} - \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 \frac{k^8}{7} ~-~ \cdots

\biggl[ \frac{(2n-1)!!}{2^n n!} \biggr]^2 \frac{k^{2n}}{2n-1}

~-~ \cdots \biggr\} </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{1^2\cdot 3}{2^2\cdot 4^2}~ k^4 - \biggl(\frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2~\frac{ k^6 }{5} - \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 \frac{k^8}{7} \biggr\} ~+~ \biggl\{ \biggl( \frac{1}{2} \biggr)^2k^2 \biggr\} \times~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{1^2\cdot 3}{2^2\cdot 4^2}~ k^4 - \biggl(\frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2~\frac{ k^6 }{5} \biggr\} </math>

 

 

<math>~+~ \biggl\{ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k^4 \biggr\} \times~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{1^2\cdot 3}{2^2\cdot 4^2}~ k^4 \biggr\} ~+~ \biggl\{ \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k^6 \biggr\}\times \biggl\{1 - \frac{1}{2^2} ~k^2 \biggr\} + \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 k^8 + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 - \biggl(\frac{5}{2^8}\biggr)~k^6 - \biggl( \frac{5^2 \cdot 7}{2^{14}}\biggr)~k^8 \biggr\} ~+~ \biggl\{ \biggl( \frac{1}{2^2} \biggr)k^2 - \frac{1}{2^4} ~k^4 - \frac{3}{2^8}~ k^6 -\frac{5}{2^{10}} ~k^8 \biggr\} </math>

 

 

<math>~ ~+~ \biggl( \frac{3^2}{2^6}\biggr) k^4 ~-~ \biggl( \frac{3^2}{2^8}\biggr) k^6 ~-~ \biggl(\frac{3^3}{2^{12}}\biggr) ~k^8 ~+~ \biggl( \frac{5^2}{2^8}\biggr) k^6 ~-~\biggl(\frac{5^2}{2^{10}}\biggr) ~k^8 ~+~\biggl(\frac{5^2\cdot 7^2}{2^{14}}\biggr) ~k^8 + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ 1 ~+~\biggl[ \frac{1}{2^2} - \frac{1}{2^2} \biggr] ~k^2 ~+~\biggl[ \frac{3^2}{2^6} - \frac{3}{2^6} - \frac{1}{2^4} \biggr]~k^4 ~+~\biggl[ \frac{5^2}{2^8} - \frac{5}{2^8} - \frac{3}{2^8} ~-~\frac{3^2}{2^8} \biggr]~ k^6 + \biggl[ \biggl(\frac{5^2\cdot 7^2}{2^{14}}\biggr) - \biggl(\frac{5^2}{2^{10}}\biggr) - \biggl(\frac{3^3}{2^{12}}\biggr) - \frac{5}{2^{10}} - \biggl( \frac{5^2 \cdot 7}{2^{14}}\biggr) \biggr]~k^8 + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ 1 ~+~\frac{1}{2^5} ~k^4 ~+~\frac{1}{2^5} ~ k^6 ~+~\frac{231}{2^{13}} ~ k^8 + \mathcal{O}(k^{10}) </math>

<math>~\frac{2^2}{\pi^2} \biggl[K(k) \cdot K(k) \biggr]</math>

<math>~=</math>

<math>~ \biggl\{ 1 + \biggl( \frac{1}{2} \biggr)^2k^2 + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k^6 + \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 k^8 + \cdots + \biggl[ \frac{(2n-1)!!}{2^n n!} \biggr]^2 k^{2n} + \cdots \biggr\} </math>

 

 

<math>~ \times~ \biggl\{ 1 + \biggl( \frac{1}{2} \biggr)^2k^2 + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k^6 + \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 k^8 + \cdots + \biggl[ \frac{(2n-1)!!}{2^n n!} \biggr]^2 k^{2n} + \cdots \biggr\} </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 + \frac{1}{2^2} k^2 + \frac{3^2}{2^6} k^4 + \frac{5^2}{2^8} k^6 + \frac{5^2 \cdot 7^2}{2^{14}} k^8 \biggr\} \times~ \biggl\{ 1 + \frac{1}{2^2} k^2 + \frac{3^2}{2^6} k^4 + \frac{5^2}{2^8} k^6 + \frac{5^2 \cdot 7^2}{2^{14}} k^8 \biggr\} + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 + \frac{1}{2^2} k^2 + \frac{3^2}{2^6} k^4 + \frac{5^2}{2^8} k^6 + \frac{5^2 \cdot 7^2}{2^{14}} k^8 \biggr\} ~+~\frac{1}{2^2} k^2 \biggl\{ 1 + \frac{1}{2^2} k^2 + \frac{3^2}{2^6} k^4 + \frac{5^2}{2^8} k^6 \biggr\} ~+~\frac{3^2}{2^6} k^4 \biggl\{ 1 + \frac{1}{2^2} k^2 + \frac{3^2}{2^6} k^4 \biggr\} ~+~ \biggl\{ \frac{5^2}{2^8} k^6 \biggr\} \biggl\{ 1 + \frac{1}{2^2} k^2 \biggr\} ~+~ \biggl\{ \frac{5^2 \cdot 7^2}{2^{14}} k^8 \biggr\} + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 + \frac{1}{2^2} k^2 + \frac{3^2}{2^6} k^4 + \frac{5^2}{2^8} k^6 + \frac{5^2 \cdot 7^2}{2^{14}} k^8 \biggr\} ~+~ \biggl\{ \frac{1}{2^2} k^2 + \frac{1}{2^4} k^4 + \frac{3^2}{2^8} k^6 + \frac{5^2}{2^{10}} k^8 \biggr\} ~+~ \biggl\{ \frac{3^2}{2^6} k^4 ~+~\frac{3^2}{2^8} k^6 ~+~\frac{3^4}{2^{12}} k^8 \biggr\} ~+~ \biggl\{ \frac{5^2}{2^8} k^6 ~+~\frac{5^2}{2^{10}} k^8 \biggr\} ~+~ \biggl\{ \frac{5^2 \cdot 7^2}{2^{14}} k^8 \biggr\} + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ 1 + \biggl[ \frac{1}{2^2} ~+~ \frac{1}{2^2} \biggr] ~k^2 + \biggl[ \frac{3^2}{2^6} + \frac{1}{2^4} ~+~\frac{3^2}{2^6} \biggr]~k^4 + \biggl[ \frac{5^2}{2^8} + \frac{3^2}{2^8} ~+~\frac{3^2}{2^8} ~+~\frac{5^2}{2^8} \biggr]~ k^6 ~+~\biggl[ \frac{5^2 \cdot 7^2}{2^{14}}+ \frac{5^2}{2^{10}} ~+~\frac{3^4}{2^{12}} ~+~\frac{5^2}{2^{10}} ~+~\frac{5^2 \cdot 7^2}{2^{14}} \biggr]k^8 + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ 1 + \frac{1}{2} k^2 + \frac{11}{2^5} ~k^4 + \frac{17}{2^6} ~ k^6 + \frac{1787}{2^{13}} ~k^{8} + \mathcal{O}(k^{10}) </math>


<math>~\frac{2^2}{\pi^2} \biggl[E(k) \cdot E(k) \biggr]</math>

<math>~=</math>

<math>~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{1^2\cdot 3}{2^2\cdot 4^2}~ k^4 - \biggl(\frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2~\frac{ k^6 }{5} - \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 \frac{k^8}{7} ~-~ \cdots

\biggl[ \frac{(2n-1)!!}{2^n n!} \biggr]^2 \frac{k^{2n}}{2n-1}

~-~ \cdots \biggr\} </math>

 

 

<math>~ \times~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{1^2\cdot 3}{2^2\cdot 4^2}~ k^4 - \biggl(\frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2~\frac{ k^6 }{5} - \biggl( \frac{1\cdot 3\cdot 5 \cdot 7}{2^7 \cdot 3}\biggr)^2 \frac{k^8}{7} ~-~ \cdots

\biggl[ \frac{(2n-1)!!}{2^n n!} \biggr]^2 \frac{k^{2n}}{2n-1}

~-~ \cdots \biggr\} </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 - \frac{5}{2^8}~ k^6 - \frac{5^2\cdot 7}{2^{14}} ~k^8 \biggr\} \times \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 - \frac{5}{2^8}~ k^6 - \frac{5^2\cdot 7}{2^{14}} ~k^8 \biggr\} + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 - \frac{5}{2^8}~ k^6 - \frac{5^2\cdot 7}{2^{14}} ~k^8 \biggr\} ~+~ \biggl\{- \frac{1}{2^2} ~k^2 \biggr\} \times \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 - \frac{5}{2^8}~ k^6 \biggr\} </math>

 

 

<math>~ ~+~ \biggl\{ - \frac{3}{2^6}~ k^4 \biggr\} \times \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 \biggr\} ~+~ \biggl\{ - \frac{5}{2^8}~ k^6 \biggr\} \times \biggl\{ 1 - \frac{1}{2^2} ~k^2 \biggr\} ~+~ \biggl\{ - \frac{5^2\cdot 7}{2^{14}}k^8 \biggr\} + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ \biggl\{ 1 - \frac{1}{2^2} ~k^2 - \frac{3}{2^6}~ k^4 - \frac{5}{2^8}~ k^6 - \frac{5^2\cdot 7}{2^{14}} ~k^8 \biggr\} ~+~ \biggl\{ - \frac{1}{2^2} ~k^2 + \frac{1}{2^4} ~k^4 + \frac{3}{2^8}~ k^6 + \frac{5}{2^{10}}~k^8 \biggr\} </math>

 

 

<math>~ ~+~ \biggl\{ ~-~ \frac{3}{2^6}~ k^4 ~+~ \frac{3}{2^8}~ k^6 + \frac{3^2}{2^{12}}~k^8 \biggr\} ~+~ \biggl\{ ~-~\frac{5}{2^8}~ k^6 + \frac{5}{2^{10}}~k^8 \biggr\} ~+~ \biggl\{ ~-~ \frac{5^2\cdot 7}{2^{14}}k^8 \biggr\} + \mathcal{O}(k^{10}) </math>

<math>~</math>

<math>~=</math>

<math>~ 1 + \biggl[ - \frac{1}{2^2}- \frac{1}{2^2} \biggr]k^2 + \biggl[ - \frac{3}{2^6}+ \frac{1}{2^4}~-~ \frac{3}{2^6} \biggr] k^4 + \biggl[ - \frac{5}{2^8}+ \frac{3}{2^8}~+~ \frac{3}{2^8}~-~\frac{5}{2^8} \biggr] k^6 + \biggl[ - \frac{5^2\cdot 7}{2^{14}} + \frac{5}{2^{10}}+ \frac{3^2}{2^{12}}+ \frac{5}{2^{10}}~-~ \frac{5^2\cdot 7}{2^{14}} \biggr] k^8 + \mathcal{O}(k^{10}) </math>

<math>~</math>

<math>~=</math>

<math>~ 1 + \biggl[ - \frac{2}{2^2} \biggr]k^2 + \biggl[ - \frac{3}{2^5}+ \frac{2}{2^5} \biggr] k^4 + \biggl[ - \frac{5}{2^7}+ \frac{3}{2^7} \biggr] k^6 + \biggl[ - \frac{5^2\cdot 7}{2^{13}} + \frac{5\cdot 2^4}{2^{13}}+ \frac{2 \cdot 3^2}{2^{13}}\biggr] k^8 + \mathcal{O}(k^{10}) </math>

 

<math>~=</math>

<math>~ 1 - \frac{1}{2} ~k^2 ~-~ \frac{1}{2^5} ~ k^4 ~-~\frac{1}{2^6} ~ k^6 ~-~\frac{77}{2^{13}} ~ k^8 + \mathcal{O}(k^{10}) </math>


Next, employing the binomial expansion, we find that,

<math>~k_0^2</math>

<math>~=</math>

<math>~2e(1+e)^{-1}</math>

 

<math>~=</math>

<math>~2e( 1 - e +e^2 - e^3 + e^4 - e^5 + \cdots ) \, ;</math>

<math>~k_0^4</math>

<math>~=</math>

<math>~4e^2(1+e)^{-2}</math>

 

<math>~=</math>

<math>~4e^2( 1 - 2e + 3e^2 - 4e^3 + 5e^4 - 6e^5 + \cdots ) \, ;</math>

<math>~k_0^6</math>

<math>~=</math>

<math>~2^3e^3(1+e)^{-3}</math>

 

<math>~=</math>

<math>~2^3e^3( 1 - 3e + 6e^2 - 10e^3 + 15e^4 - 21e^5 + \cdots ) \, ;</math>

<math>~k_0^8</math>

<math>~=</math>

<math>~2^4e^4(1+e)^{-4}</math>

 

<math>~=</math>

<math>~2^4e^4(1 - 4e + 10 e^2 - 20e^3 + 35e^4 - 56e^5 + \cdots) \, .</math>

Hence, we have,

<math>~\frac{2^2}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W0}(\eta_0)</math>

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + \frac{1}{2} k_0^2 + \frac{11}{2^5} ~k_0^4 + \frac{17}{2^6} ~ k_0^6 + \frac{1787}{2^{13}} ~k_0^8 + \mathcal{O}(k_0^{10})

\biggr]

</math>

 

 

<math>~ + 2 (1+e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~k_0^4 ~+~\frac{1}{2^5} ~ k_0^6 ~+~ \frac{231}{2^{13}}~k_0^8 + \mathcal{O}(k_0^{10})

\biggr]

</math>

 

 

<math>~ - (1+e) \biggl[ 1 - \frac{1}{2} ~k_0^2 ~-~ \frac{1}{2^5} ~ k_0^4 ~ ~-~\frac{1}{2^6} ~ k_0^6 ~-~\frac{77}{2^{13}}~k_0^8 + \mathcal{O}(k_0^{10}) \biggr] </math>

 

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + e ( 1 - e +e^2 -e^3 ) + \frac{11}{2^3} \cdot ~e^2( 1 - 2e + 3e^2) + \frac{17}{2^6} ~\cdot 2^3 e^3 ( 1 - 3e) + \frac{1787}{2^{13}} \cdot 2^4e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ + 2 (1+e^2) \biggl[ 1 ~+~\frac{1}{2^5} \cdot~4e^2( 1 - 2e + 3e^2) ~+~\frac{1}{2^5} ~ 2^3e^3 (1-3e) ~+~\frac{231}{2^{13}} \cdot 2^4e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ - (1+e) \biggl[ 1 - e ~( 1 - e +e^2 -e^3) ~ -~ \frac{1}{2^5} \cdot~ 4e^2( 1 - 2e +3e^2) ~ ~-~\frac{1}{2^6} ~ 2^3e^3(1 - 3e) ~-~\frac{77}{2^{13}}~2^4e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ - 2^{-9}(1-e) \biggl[ 512 (1+ e - e^2 +e^3 -e^4 ) + 704 \cdot ~( e^2 - 2e^3 + 3e^4) + 1088 ~\cdot ( e^3 - 3e^4) + 1787 \cdot e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ + (1+e^2) 2^{-9}\biggl[ 1024 ~+~128 \cdot~( e^2 - 2e^3 + 3e^4) ~+~256 ~ (e^3-3e^4) ~+~462 \cdot e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ - 2^{-9}(1+e) \biggl[ 512 ~(1 -e + e^2 -e^3 + e^4) ~ -~ 64 \cdot~ ( e^2 - 2e^3 +3e^4) ~ ~-~64 ~ (e^3 - 3e^4) ~-~77~e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ - 2^{-9}(1-e) \biggl[ 512 + 512e + 192e^2 + e^3(512 - 1408 + 1088) + e^4(704-512 - 3264 + 1787) + \mathcal{O}(e^{5}) \biggr] </math>

 

 

<math>~ + 2^{-9}(1+e^2) \biggl[ 1024 + 128e^2 + e^3(-256 + 256 ) + e^4(384 -768 + 462) + \mathcal{O}(e^{5}) \biggr] </math>

 

 

<math>~ - 2^{-9}(1+e) \biggl[ 512 - 512e + e^2(512 - 64 ) + e^3(-512 +128 -64 ) + e^4(512 - 192 - 192 - 77) + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ - 2^{-9}(1-e) \biggl[ 512 + 512e + 192e^2 + 192e^3 - 1285 e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

 

<math>~ + 2^{-9}(1+e^2) \biggl[ 1024 + 128e^2 + 78e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

 

<math>~ - 2^{-9}(1+e) \biggl[ 512 - 512e + 448e^2 - 448 e^3 + 51e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ 2^{-9}\biggl[ (- 192+ 128 - 448)e^2 + (- 192 + 448) e^3 + (1285 + 78- 51)e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

 

<math>~ + 2^{-9} e \biggl[ 1024e + (192- 448)e^2 + (192+ 448) e^3 + \mathcal{O}(e^{4}) \biggr] + 2^{-9} e^2 \biggl[ 1024 + 128e^2 + \mathcal{O}(e^{3}) \biggr] </math>

 

<math>~=</math>

<math>~ 2^{-9} \biggl[ (- 192+ 128 - 448)e^2 + 2048 e^2 + (1285 + 78- 51)e^4 + (192+ 448) e^4 + 128e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ 2^{-9} \biggl[ 1536e^2 + 2080e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ 3e^2 + \biggl[ \frac{5\cdot 13}{2^4}\biggr] e^4 + \mathcal{O}(e^{5}) </math>

<math>~\Rightarrow ~~~ \frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>

<math>~=</math>

<math>~ \biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} \, . </math>

Hence,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~=</math>

<math>~ [1 + \mathcal{O}(e^{2})]\cdot (1 - e^2)^{1 / 2} \biggl\{ \frac{\boldsymbol{K}(k) }{ r_1 } \biggr\}\Delta_0 \, , </math>

or, more precisely,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} \biggl\{ \frac{\boldsymbol{K}(k) }{ r_1 } \biggr\}\Delta_0 \, . </math>

Next Factors

Now,

<math>~\Delta_0^2</math>

<math>~=</math>

<math>~ (\varpi_W + R_c)^2 + z_W^2 \, , </math>

<math>~r_1^2</math>

<math>~=</math>

<math>~\biggl[ \varpi_W + R_c (1 - e^2 )^{1 / 2}\biggr]^2 + z_W^2 \, ,</math>

<math>~\Rightarrow ~~~ r_1^2 - \Delta_0^2</math>

<math>~=</math>

<math>~\biggl[ \varpi_W + R_c (1 - e^2 )^{1 / 2}\biggr]^2 + z_W^2 - \biggl[ (\varpi_W + R_c)^2 + z_W^2 \biggr]</math>

 

<math>~=</math>

<math>~\varpi_W^2 + 2\varpi_W R_c (1 - e^2 )^{1 / 2} + R_c^2 (1 - e^2 ) + z_W^2 - [\varpi_W^2 + 2\varpi_W R_c + R_c^2 + z_W^2 ]</math>

 

<math>~=</math>

<math>~2\varpi_W R_c [(1 - e^2 )^{1 / 2} - 1] -e^2 R_c^2 \, . </math>


Again, drawing from the binomial theorem, we have,

<math>~(1 -e^2)^{1 / 2}</math>

<math>~=</math>

<math>~ 1 - \frac{1}{2}e^2 + \biggl[\frac{ \tfrac{1}{2}(-\tfrac{1}{2}) }{ 2 } \biggr]e^4 - \biggl[ \frac{ \tfrac{1}{2}(-\tfrac{1}{2} )(-\tfrac{3}{2} ) }{ 3! } \biggr]e^6 + \biggl[ \frac{ \tfrac{1}{2} (-\tfrac{1}{2})(-\tfrac{3}{2})(-\tfrac{5}{2}) }{ 4! } \biggr]e^8 + \cdots </math>

 

<math>~=</math>

<math>~ 1 - \frac{1}{2}e^2 - \frac{1}{2^3} e^4 - \frac{1}{2^4}e^6 - \frac{5}{2^7} e^8 - \mathcal{O}(e^{10}) \, . </math>


<math>~\Rightarrow ~~~ r_1^2 - \Delta_0^2</math>

<math>~=</math>

<math>~\varpi_W R_c \biggl[- e^2 - \frac{1}{2^2} e^4 - \frac{1}{2^3}e^6 - \frac{5}{2^6} e^8 - \mathcal{O}(e^{10}) \biggr] -e^2 R_c^2 </math>

<math>~\Rightarrow ~~~\frac{ r_1^2}{\Delta_0^2} </math>

<math>~=</math>

<math>~1

-e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{\Delta_0^2}\biggr]

- \frac{\varpi_W R_c}{\Delta_0^2} \biggl[\frac{1}{2^2} e^4 + \frac{1}{2^3}e^6 + \frac{5}{2^6} e^8 + \mathcal{O}(e^{10}) \biggr] </math>


Now Work on Elliptic Integral Expressions

From a separate discussion we can draw the series expansion of <math>~\boldsymbol{K}(k)</math>, specifically,

<math>~\frac{2K(k)}{\pi}</math>

<math>~=</math>

<math>~ 1 + \biggl( \frac{1}{2} \biggr)^2k^2 + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k^6 + \cdots </math>

where,

<math>~\frac{k^2}{4}</math>

<math>~\equiv</math>

<math>~ \frac{1}{4} \biggl[ \frac{r_1^2 - r_2^2}{r_1^2} \biggr] = \biggl[ \frac{a\varpi}{r_1^2} \biggr] = \biggl[ \frac{a\varpi}{(\varpi + a)^2 + (z - Z_0)^2} \biggr] </math>

 

<math>~=</math>

<math>~ \frac{\varpi_W R_c(1-e^2)^{1 / 2}}{[ \varpi_W + R_c(1-e^2)^{1 / 2} ]^2 + z_W^2} \, . </math>

Also,

<math>~\frac{2K(k_H)}{\pi}</math>

<math>~=</math>

<math>~ 1 + \biggl( \frac{1}{2} \biggr)^2k_H^2 + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6 + \cdots </math>

where,

<math>~\frac{k_H^2}{4}</math>

<math>~=</math>

<math>~ \frac{1}{\Delta^2}\biggl[ R (R_c + b\cos\theta_H) \biggr] </math>

 

<math>~=</math>

<math>~ \frac{\varpi_W (R_c + b\cos\theta_H)}{[\varpi_W + (R_c + b\cos\theta_H)]^2 + [z_W - b\sin\theta_H]^2} \, . </math>

What we want to do is write <math>~K(k)</math> in terms of <math>~K(k_H)</math>. Let's try …

<math>~\frac{2K(k)}{\pi}</math>

<math>~=</math>

<math>~\frac{2K(k_H)}{\pi} + \delta_K \, ,</math>


where,

<math>~\delta_K</math>

<math>~\equiv</math>

<math>~\frac{2K(k)}{\pi} - \frac{2K(k_H)}{\pi} </math>

 

<math>~=</math>

<math>~\biggl\{1 + \frac{k^2}{4} + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k^6 + \cdots \biggr\} - \biggl\{1 + \frac{k_H^2}{4} + \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6 + \cdots \biggr\} </math>

 

<math>~\approx</math>

<math>~\biggl\{1 + \frac{k^2}{4} \biggr\} - \biggl\{1 + \frac{k_H^2}{4} \biggr\} = \frac{k^2}{4} - \frac{k_H^2}{4} </math>

 

<math>~=</math>

<math>~ \frac{\varpi_W R_c(1-e^2)^{1 / 2}}{[ \varpi_W + R_c(1-e^2)^{1 / 2} ]^2 + z_W^2} - \frac{\varpi_W (R_c + b\cos\theta_H)}{[\varpi_W + (R_c + b\cos\theta_H)]^2 + [z_W - b\sin\theta_H]^2} </math>

 

<math>~=</math>

<math>~ \biggl\{ \varpi_W R_c(1-e^2)^{1 / 2} \biggr\} \biggl\{\varpi_W^2 +R_c^2 + z_W^2 + 2\varpi_W R_c(1-e^2)^{1 / 2} - R_c^2 e^2 \biggr\}^{-1} </math>

 

 

<math>~ - \biggl\{ \varpi_W R_c (1 + e\cos\theta_H) \biggr\} \biggl\{[\varpi_W + R_c(1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2 \biggr\}^{-1} </math>

 

<math>~\approx</math>

<math>~ \biggl\{ \varpi_W R_c \biggl[ 1-\frac{1}{2} e^2 + \mathcal{O}(e^4)\biggr] \biggr\} \biggl\{\varpi_W^2 +R_c^2 + z_W^2 + 2\varpi_W R_c\biggl[ 1-\frac{1}{2} e^2 + \mathcal{O}(e^4)\biggr] - R_c^2 e^2 \biggr\}^{-1} </math>

 

 

<math>~ - \biggl\{ \varpi_W R_c \biggl[ 1 + e\cos\theta_H \biggr] \biggr\} \biggl\{\varpi_W^2 + 2\varpi_W R_c(1+e\cos\theta_H) + R_c^2(1 + 2e\cos\theta_H + e^2\cos^2\theta_H) + z_W^2 - 2 z_W R_c e\sin\theta_H + R_c^2 e^2 \sin\theta^2_H \biggr\}^{-1} </math>

 

<math>~\approx</math>

<math>~ \biggl\{\varpi_W R_c - e^2 \biggl[ \frac{\varpi_W R_c}{2} \biggr] + \mathcal{O}(e^4) \biggr\} \biggl\{ [ (\varpi_W +R_c)^2 + z_W^2 ] - e^2 \biggl[ \varpi_W R_c + R_c^2 \biggr] + \mathcal{O}(e^4) \biggr\}^{-1} </math>

 

 

<math>~ - \biggl\{ \varpi_W R_c + e \biggl[ \varpi_W R_c \cos\theta_H \biggr]\biggr\} \biggl\{ [ (\varpi_W^2 + R_c)^2 + z_W^2 ] + 2R_c e(R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) + R_c^2 e^2 \biggr\}^{-1} </math>

 

<math>~\approx</math>

<math>~ \biggl\{ \frac{\varpi_W R_c}{ [ (\varpi_W +R_c)^2 + z_W^2 ] } \biggl[1 - \frac{1}{2}e^2 \biggr] \biggr\} \biggl\{ 1 - e^2 \biggl[ \frac{ \varpi_W R_c + R_c^2 }{ (\varpi_W +R_c)^2 + z_W^2 } \biggr] \biggr\}^{-1} </math>

 

 

<math>~ -~ \biggl\{ \frac{ \varpi_W R_c }{ [(\varpi_W^2 + R_c)^2 + z_W^2 ] } \biggl[ 1 + e\cos\theta_H \biggr] \biggr\} \biggl\{ 1 + e\biggl[ \frac{2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)}{ (\varpi_W^2 + R_c)^2 + z_W^2 }\biggr] + e^2 \biggl[ \frac{R_c^2 }{ (\varpi_W^2 + R_c)^2 + z_W^2 } \biggr] \biggr\}^{-1} </math>

 

<math>~\approx</math>

<math>~ \frac{\varpi_W R_c}{ [ (\varpi_W +R_c)^2 + z_W^2 ] } \biggl[1 - \frac{1}{2}e^2 \biggr] \biggl\{ 1 + e^2 \biggl[ \frac{ \varpi_W R_c + R_c^2 }{ (\varpi_W +R_c)^2 + z_W^2 } \biggr] \biggr\} </math>

 

 

<math>~ -~\frac{ \varpi_W R_c }{ [(\varpi_W^2 + R_c)^2 + z_W^2 ] } \biggl[ 1 + e\cos\theta_H \biggr] \biggl\{ 1 - e\biggl[ \frac{2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)}{ (\varpi_W^2 + R_c)^2 + z_W^2 }\biggr] - e^2 \biggl[ \frac{R_c^2 }{ (\varpi_W^2 + R_c)^2 + z_W^2 } \biggr] \biggr\} </math>

 

<math>~\approx</math>

<math>~ -~\frac{ e\cdot \varpi_W R_c }{ [(\varpi_W^2 + R_c)^2 + z_W^2 ] } \biggl[ \cos\theta_H - \frac{2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)}{ (\varpi_W^2 + R_c)^2 + z_W^2 }\biggr] </math>

 

 

<math>~ +~\frac{e^2 \cdot \varpi_W R_c}{ [ (\varpi_W +R_c)^2 + z_W^2 ] } \biggl\{ \biggl[ \frac{ \varpi_W R_c + R_c^2 }{ (\varpi_W +R_c)^2 + z_W^2 } - \frac{1}{2} \biggr] - \biggl[ \frac{R_c^2 }{ (\varpi_W^2 + R_c)^2 + z_W^2 } \biggr] - \cos\theta_H \biggl[ \frac{2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)}{ (\varpi_W^2 + R_c)^2 + z_W^2 }\biggr] \biggr\} </math>

 

<math>~\approx</math>

<math>~ -~\frac{ e\cdot \varpi_W R_c }{ [(\varpi_W^2 + R_c)^2 + z_W^2 ] [ (\varpi_W^2 + R_c)^2 + z_W^2 ] } \biggl[ \cos\theta_H [(\varpi_W^2 + R_c)^2 + z_W^2 ] -2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) \biggr] </math>

 

 

<math>~ +~\frac{\tfrac{1}{2}e^2 \cdot \varpi_W R_c}{ [ (\varpi_W +R_c)^2 + z_W^2 ][ (\varpi_W^2 + R_c)^2 + z_W^2 ] } \biggl\{ 2 (\varpi_W R_c + R_c^2 ) - [ (\varpi_W^2 + R_c)^2 + z_W^2 ] - 2R_c^2 - 4R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) \biggr\} </math>

 

<math>~\approx</math>

<math>~ -~\frac{ e\cdot \varpi_W R_c }{ \Delta_0^2 } \biggl[ \cos\theta_H - \frac{2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)}{\Delta_0^2} \biggr] </math>

 

 

<math>~ +~\frac{ e^2 \cdot \varpi_W R_c}{2 \Delta_0^4 } \biggl\{ 2 (\varpi_W R_c + R_c^2 ) - [ (\varpi_W^2 + R_c)^2 + z_W^2 ] - 2R_c^2 - 4R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) \biggr\} \, . </math>


Let's subtract <math>~K([k_H]_0)</math> from the potential expression. But first, let's adopt the shorthand notation …

Given that,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \biggl\{ \boldsymbol{K}(k) \biggr\} \frac{\Delta_0}{r_1}~\biggl( \frac{2^2}{3\pi^2} \biggr) \Upsilon_{W0}(\eta_0) </math>

 

<math>~=</math>

<math>~\biggl\{ \boldsymbol{K}(k) \biggr\} \biggl[\frac{r_1^2 }{ \Delta_0^2 } \biggr]^{-1 / 2} \biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} </math>

 

<math>~=</math>

<math>~\biggl\{ \boldsymbol{K}(k) \biggr\} \biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \mathcal{O}(e^4)\biggr\} \biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot \biggl[ 1 - \frac{1}{2}e^2 - \mathcal{O}(e^{4}) \biggr] </math>

let's define the variable, <math>~\mathcal{A}</math>, such that,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \biggl\{\boldsymbol{K}(k)\biggr\} \{1 + e^2\mathcal{A}\} </math>

<math>~\Rightarrow ~~~ \{ 1 + e^2 \cdot \mathcal{A} \}</math>

<math>~=</math>

<math>~\biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \mathcal{O}(e^4)\biggr\} \biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 + \mathcal{O}(e^{3}) \biggr]\cdot \biggl[ 1 - \frac{1}{2}e^2 - \mathcal{O}(e^{4}) \biggr]</math>

 

<math>~\approx</math>

<math>~\biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] \biggr\} \biggl[1 + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 \biggr] \biggl[ 1 - \frac{1}{2}e^2 \biggr]</math>

 

<math>~\approx</math>

<math>~\biggl\{1 + \frac{e^2}{2} \biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \biggl( \frac{5\cdot 13}{2^4\cdot 3}\biggr) e^2 - \frac{1}{2}e^2 \biggr\}</math>

<math>~\Rightarrow ~~~ 2\mathcal{A}</math>

<math>~\approx</math>

<math>~\biggl[ \frac{R_c(R_c + \varpi_W)}{\Delta_0^2}\biggr] + \biggl( \frac{41}{2^3\cdot 3}\biggr) \, . </math>


We can therefore write,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] - K([k_H]_0)</math>

<math>~\approx</math>

<math>~- K([k_H]_0) + \biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\} \{ 1 + e^2 \cdot \mathcal{A} \} </math>

 

<math>~\approx</math>

<math>~- K([k_H]_0) + K(k_H) \{ 1 + e^2 \cdot \mathcal{A} \} + \frac{\pi}{2} \cdot \delta_K \, , </math>

where we should keep in mind that <math>~\delta_k</math> is <math>~\mathcal{O}(e^1)</math>. So, let's examine the piece,

<math>~\frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]</math>

<math>~=</math>

<math>~

\biggl\{1 + \frac{k_H^2}{4} 

+ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6 + \cdots \biggr\} -

\biggl\{1 + \frac{k_H^2}{4} 

+ \biggl( \frac{1\cdot 3}{2\cdot 4}\biggr)^2 k_H^4 + \biggl( \frac{1\cdot 3\cdot 5}{2^4\cdot 3}\biggr)^2 k_H^6 + \cdots \biggr\}_{e\rightarrow 0} </math>

 

<math>~\approx</math>

<math>~ \frac{k_H^2}{4} - \biggl[ \frac{k_H^2}{4} \biggr]_{e\rightarrow 0} </math>

 

<math>~=</math>

<math>~ \biggl[ \frac{\varpi_W R_c (1 + e\cos\theta_H)}{[\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2} \biggr] - \biggl[ \frac{\varpi_W R_c (1 + e\cos\theta_H)}{[\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2} \biggr]_{e\rightarrow 0} </math>

 

<math>~=</math>

<math>~\varpi_W R_c (1 + e\cos\theta_H) \biggl\{ [\varpi_W + R_c (1 + e\cos\theta_H)]^2 + [z_W - R_c e\sin\theta_H]^2 \biggr\}^{-1} - \biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr] </math>

 

<math>~=</math>

<math>~\varpi_W R_c (1 + e\cos\theta_H) \biggl\{ \varpi_W^2 + 2\varpi_W R_c(1 + e\cos\theta_H) + R_c^2(1 + 2e\cos\theta_H + e^2\cos^2\theta_H) + z_W^2 -2z_W R_c e\sin\theta_H + R_c^2 e^2\sin^2\theta_H \biggr\}^{-1} </math>

 

 

<math>~ - \biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr] </math>

 

<math>~=</math>

<math>~ -\biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr] + \biggl[ \frac{ \varpi_W R_c (1 + e\cos\theta_H)}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr] \biggl\{1 + \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{(\varpi_W + R_c)^2 + z_W^2} + \frac{e^2 [R_c^2\cos^2\theta_H + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2} \biggr\}^{-1} </math>

 

<math>~\approx</math>

<math>~ -\biggl[ \frac{\varpi_W R_c }{(\varpi_W + R_c )^2 + z_W^2} \biggr] +\biggl[ \frac{ \varpi_W R_c (1 + e\cos\theta_H)}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr] \biggl\{1 - \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{(\varpi_W + R_c)^2 + z_W^2} </math>

 

 

<math>~ - \frac{e^2 [R_c^2\cos^2\theta_H + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2} + \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ [(\varpi_W + R_c)^2 + z_W^2]^2} \biggr\} </math>

 

<math>~\approx</math>

<math>~ \biggl[ \frac{ \varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr] \biggl\{ - \frac{ e [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{(\varpi_W + R_c)^2 + z_W^2} </math>

 

 

<math>~ - \frac{e^2 [R_c^2\cos^2\theta_H + R_c^2 \sin^2\theta_H ] }{(\varpi_W + R_c)^2 + z_W^2} + \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ [(\varpi_W + R_c)^2 + z_W^2]^2} \biggr\} </math>

 

 

<math>~ +\biggl[ \frac{ \varpi_W R_c}{ (\varpi_W + R_c)^2 + z_W^2 } \biggr] \biggl\{ \frac{e\cos\theta_H [(\varpi_W + R_c)^2 + z_W^2] -e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{(\varpi_W + R_c)^2 + z_W^2} \biggr\} </math>

 

<math>~\approx</math>

<math>~ \biggl[ \frac{ \varpi_W R_c}{ \Delta_0^2 } \biggr] \biggl\{ e\cos\theta_H - \frac{ eR_c\cos\theta_H [2\varpi_W + 2 R_c - 2z_W \tan\theta_H] }{ \Delta_0^2} - \frac{e^2 R_c^2 }{ \Delta_0^2} </math>

 

 

<math>~ - \frac{e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{ \Delta_0^2} + \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ \Delta_0^4} \biggr\} \, . </math>

Now we have,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] - K([k_H]_0)</math>

<math>~\approx</math>

<math>~- K([k_H]_0) + K(k_H) \{ 1 + e^2 \cdot \mathcal{A} \} + \frac{\pi}{2} \cdot \delta_K </math>

<math>~\Rightarrow ~~~ - \Delta_0 \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~\approx</math>

<math>~ \frac{2}{\pi} K([k_H]_0) + \frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr] + \delta_K + \frac{2}{\pi} K(k_H) e^2 \cdot \mathcal{A} \, . </math>

But, as we have just demonstrated,

<math>~\frac{2}{\pi} \biggl[ K(k_H) - K([k_H]_0) \biggr]+ \delta_K </math>

<math>~\approx</math>

<math>~ \biggl[ \frac{ \varpi_W R_c}{ \Delta_0^2 } \biggr] \biggl\{ e\cos\theta_H - \frac{ eR_c\cos\theta_H [2\varpi_W + 2 R_c - 2z_W \tan\theta_H] }{ \Delta_0^2} - \frac{e^2 R_c^2 }{ \Delta_0^2} </math>

 

 

<math>~ - \frac{e^2\cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] }{ \Delta_0^2} + \frac{ e^2 [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ \Delta_0^4} \biggr\} </math>

 

 

<math>~ -~\frac{ e\cdot \varpi_W R_c }{ \Delta_0^2 } \biggl[ \cos\theta_H - \frac{2R_c (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H)}{\Delta_0^2} \biggr] </math>

 

 

<math>~ +~\frac{ e^2 \cdot \varpi_W R_c}{2 \Delta_0^4 } \biggl\{ 2 (\varpi_W R_c + R_c^2 ) - [ (\varpi_W^2 + R_c)^2 + z_W^2 ] - 2R_c^2 - 4R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) \biggr\} \, . </math>

 

<math>~\approx</math>

<math>~ \biggl[ \frac{e^2 \cdot \varpi_W R_c}{ \Delta_0^4 } \biggr] \biggl\{ - R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] </math>

 

 

<math>~ +~(\varpi_W R_c + R_c^2 ) - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ] - R_c^2 - 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) </math>

 

 

<math>~ + \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ \Delta_0^2} \biggr\} </math>

TEMPORARY BREAK HERE

Hence,

<math>~ - \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~\approx</math>

<math>~ K([k_H]_0) + K(k_H) e^2 \cdot \mathcal{A} +~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot \varpi_W R_c}{ \Delta_0^4 } \biggr] \biggl\{ - R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] </math>

 

 

<math>~ +~(\varpi_W R_c + R_c^2 ) - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ] - R_c^2 - 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) </math>

 

 

<math>~ + \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ \Delta_0^2} \biggr\} </math>

Include Second Wong Term

<math>~\biggl( \frac{a}{GM} \biggr) \Phi_\mathrm{W1}(\varpi,z)\biggr|_\mathrm{exterior}</math>

<math>~=</math>

<math>~ - \biggl( \frac{2^{3} }{3\pi^3} \biggr) \Upsilon_{W1}(\eta_0) \times \cos\theta \biggl\{ \frac{a}{r_2} \cdot \boldsymbol{E}(k) \biggr\} </math>

<math>~\Rightarrow ~~~ - \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W1}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W1}(\eta_0) \times \cos\theta \biggl\{ \frac{\Delta_0}{r_2} \cdot \boldsymbol{E}(k) \biggr\} \, ; </math>

Leading (Upsilon) Coefficient

<math>~\Upsilon_{W1}(\eta_0)</math>

<math>~\equiv</math>

<math>~\biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \biggl\{ K(k_0)\cdot K(k_0) [\cosh\eta_0(1 - \cosh\eta_0)] +~2K(k_0)\cdot E(k_0) [(3\cosh^2\eta_0 - 1)] -~5 E(k_0)\cdot E(k_0) [\cosh\eta_0(1+\cosh\eta_0)] \biggr\} </math>

<math>~\Rightarrow~~~ \biggl[ \frac{e^2}{ (1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>

<math>~=</math>

<math>~ - (1-e)K(k_0)\cdot K(k_0) +~2(3-e^2)K(k_0)\cdot E(k_0) -~5(1+e) E(k_0)\cdot E(k_0) \, . </math>

<math>~\Rightarrow ~~~ \frac{2^2}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + \frac{1}{2} k_0^2 + \frac{11}{2^5} ~k_0^4 + \frac{17}{2^6} ~ k_0^6 + \frac{1787}{2^{13}} ~k_0^8 + \mathcal{O}(k_0^{10})

\biggr]

</math>

 

 

<math>~ + 2 (3-e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~k_0^4 ~+~\frac{1}{2^5} ~ k_0^6 ~+~ \frac{231}{2^{13}}~k_0^8 + \mathcal{O}(k_0^{10})

\biggr]

</math>

 

 

<math>~ - 5(1+e) \biggl[ 1 - ~\frac{1}{2} ~k_0^2 ~ -~ \frac{1}{2^5} ~ k_0^4 ~ ~-~\frac{1}{2^6} ~ k_0^6 ~-~\frac{77}{2^{13}}~k_0^8 + \mathcal{O}(k_0^{10}) \biggr] </math>

 

<math>~=</math>

<math>~ - (1-e) \biggl[ 1 + \frac{1}{2} \cdot 2e( 1 - e +e^2 - e^3 ) + \frac{11}{2^5} ~\cdot 4e^2( 1 - 2e + 3e^2 ) + \frac{17}{2^6} ~ \cdot 2^3e^3( 1 - 3e ) + \frac{1787}{2^{13}} ~\cdot 2^4e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ + 2 (3-e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~\cdot 4e^2( 1 - 2e + 3e^2 ) ~+~\frac{1}{2^5} ~ \cdot 2^3e^3( 1 - 3e ) ~+~ \frac{231}{2^{13}}~\cdot 2^4e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ - 5(1+e) \biggl[ 1 - ~\frac{1}{2} ~\cdot 2e( 1 - e +e^2 - e^3 ) ~ -~ \frac{1}{2^5} ~ \cdot 4e^2( 1 - 2e + 3e^2 ) ~-~\frac{1}{2^6} ~ \cdot 2^3e^3( 1 - 3e ) ~-~\frac{77}{2^{13}}~\cdot 2^4e^4 + \mathcal{O}(e^{5}) \biggr] </math>

 

<math>~=</math>

<math>~ - 2^{-9}(1-e) \biggl[ 2^9 + 2^9e( 1 - e +e^2 - e^3 ) + 2^6 \cdot 11 ~\cdot e^2( 1 - 2e + 3e^2 ) + 2^6\cdot 17 ~ \cdot e^3( 1 - 3e ) + 1787 ~\cdot e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ + 2^{-9} (6- 2e^2) \biggl[ 2^9 ~+~2^6~\cdot e^2( 1 - 2e + 3e^2 ) ~+~2^7 \cdot e^3( 1 - 3e ) ~+~ 231~\cdot e^4 + \mathcal{O}(e^{5})

\biggr]

</math>

 

 

<math>~ - 2^{-9}(5+ 5e) \biggl[ 2^9 - ~2^9 \cdot e( 1 - e +e^2 - e^3 ) ~ -~ 2^6 \cdot e^2( 1 - 2e + 3e^2 ) ~-~2^6 \cdot e^3( 1 - 3e ) ~-~77~\cdot e^4 + \mathcal{O}(e^{5}) \biggr] </math>

<math>~\Rightarrow ~~~\frac{2^{11}}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>

<math>~=</math>

<math>~ - 2^9 - 2^9e( 1 - e +e^2 - e^3 ) - 2^6 \cdot 11 ~\cdot e^2( 1 - 2e + 3e^2 ) - 2^6\cdot 17 ~ \cdot e^3( 1 - 3e ) - 1787 ~\cdot e^4 </math>

 

 

<math>~ + 2^9e + 2^9e^2( 1 - e +e^2 ) + 2^6 \cdot 11 ~\cdot e^3( 1 - 2e ) + 2^6\cdot 17 ~ \cdot e^4 </math>

 

 

<math>~ + 6\biggl[ 2^9 ~+~2^6~\cdot e^2( 1 - 2e + 3e^2 ) ~+~2^7 \cdot e^3( 1 - 3e ) ~+~ 231~\cdot e^4

\biggr]

-2^{10}e^2 ~-~2^7~\cdot e^4 </math>

 

 

<math>~ + 5 \biggl[ -2^9 + ~2^9 \cdot e( 1 - e +e^2 - e^3 ) ~ +~ 2^6 \cdot e^2( 1 - 2e + 3e^2 ) ~+~2^6 \cdot e^3( 1 - 3e ) ~+~77~\cdot e^4 \biggr] </math>

 

 

<math>~ +~5 \biggl[ -2^9e + ~2^9 \cdot e^2( 1 - e +e^2 ) ~ +~ 2^6 \cdot e^3( 1 - 2e ) ~+~2^6 \cdot e^4 \biggr] + \mathcal{O}(e^{5}) </math>

 

<math>~=</math>

<math>~ 2^9( e^2 - e^3 + e^4 ) - 2^6 \cdot 11 ~( e^2 - 2e^3 + 3e^4 ) - 2^6\cdot 17 ~( e^3 - 3e^4 ) - 1787 ~e^4 </math>

 

 

<math>~ +2^9 ( e^2 - e^3 +e^4 ) + 2^6 \cdot 11 ( e^3 - 2e^4 ) + 2^6\cdot 17 ~ e^4 </math>

 

 

<math>~ +~ 3\cdot 2^7~( e^2 - 2e^3 + 3e^4 ) ~+~3\cdot 2^8 ( e^3 - 3e^4 ) ~+~ 2\cdot 3^2 \cdot 7\cdot 11~\cdot e^4 -2^{10}e^2 ~-~2^7~\cdot e^4 </math>

 

 

<math>~ + 5\cdot 2^9 ( - e^2 +e^3 - e^4 ) ~ +~ 5\cdot 2^6 ( e^2 - 2e^3 + 3e^4 ) ~+~5\cdot 2^6 ( e^3 - 3e^4 ) ~+~5\cdot 77~e^4 </math>

 

 

<math>~ +5\cdot 2^9 ( e^2 - e^3 +e^4 ) ~ +~ 5\cdot 2^6 ( e^3 - 2e^4 ) ~+~5\cdot 2^6 e^4 + \mathcal{O}(e^{5}) </math>

 

<math>~=</math>

<math>~ e^2 [ 2^9 - 2^6\cdot 11 + 2^9 + 3\cdot 2^7 -2^{10} -5\cdot 2^9 + 5\cdot 2^6 + 5\cdot 2^9 ] </math>

 

 

<math>~ + e^3 [ -2^9 - 2^7\cdot 11 - 2^6\cdot 17 - 2^9 +2^6\cdot 11 - 3\cdot 2^8+3\cdot 2^8 + 5\cdot 2^9-5\cdot 2^7 +5\cdot 2^6 -5\cdot 2^9 + 5\cdot 2^6] </math>

 

 

<math>~ + e^4 [ 2^9 - 3\cdot 11\cdot 2^6+3\cdot 17\cdot 2^6 - 1787 + 2^9 - 11\cdot 2^7 + 17\cdot 2^6 + 3^2\cdot 2^7 - 3^2\cdot 2^8+ 2\cdot 3^2\cdot 7\cdot 11 - 2^7 - 5\cdot 2^9 + 3\cdot 5\cdot 2^6 - 3\cdot 5\cdot 2^6 + 5\cdot 7\cdot 11 + 5\cdot 2^9 - 5\cdot 2^7 +5\cdot 2^6] + \mathcal{O}(e^{5}) </math>

 

<math>~=</math>

<math>~ e^2 [ - 2^6\cdot 11 + 3\cdot 2^7 + 5\cdot 2^6 ] + e^3 [ -2^{10} - 2^7\cdot 11 - 2^6\cdot 17 +2^6\cdot 11 ] </math>

 

 

<math>~ + e^4 [ 2^{10}~-~ 1787~+~ 2\cdot 3^2\cdot 7\cdot 11~+~ 5\cdot 7\cdot 11 ~+~ 2^6\cdot (3\cdot 17 - 3\cdot 11 - 22 + 17 + 18 - 36 - 2 - 10 + 5) ] + \mathcal{O}(e^{5}) </math>

 

<math>~=</math>

<math>~ 2^6 e^2 [ 0 ] ~- 2^8 \cdot 11 e^3 + e^4 [ 2^{10}~-~ 1787~+~ 7\cdot 11\cdot 23 ~-~ 2^8\cdot 3 ] + \mathcal{O}(e^{5}) </math>

 

<math>~=</math>

<math>~ - 2^8 \cdot 11 e^3 + 2^4\cdot 3\cdot 5e^4 + \mathcal{O}(e^{5}) </math>

<math>~\Rightarrow ~~~\frac{2^{2}}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math>

<math>~=</math>

<math>~ - \frac{11}{2} e^3 + \frac{3\cdot 5}{2^5} e^4 + \mathcal{O}(e^{5}) \, . </math>

Floating Comparison Summary

As shown above, the first three terms of the Huré, et al. (2020) series expression may be written as,

<math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{ \Psi_0 + \Psi_1 + \Psi_2 }{GM} \biggr] </math>

<math>~=</math>

<math>~ \boldsymbol{K}([k_H]_0) - \frac{e^2}{2^4} \cdot \boldsymbol{K}(k_H) + \frac{e^2}{2^4} \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \boldsymbol{E}(k_H) \, . </math>

Let's see how it compares to the first term of Wong's (1973) expression which, as shown separately above, can be written in the form,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \Delta_0 \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W0}(\eta_0) \biggl\{ \frac{\boldsymbol{K}(k) }{ r_1 } \biggr\}\, . </math>


First, as shown above,

<math>~\frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math>

<math>~=</math>

<math>~ \biggl[1 + \biggl(\frac{5\cdot 13}{2^4\cdot 3} \biggr)e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} \, . </math>

Note that, in order to determine the functional form of the <math>~\mathcal{O}(e^{2})</math> term in this expression, we will have to include <math>~k_0^8</math> terms in the various expressions for products of elliptic integrals. Second, we have shown that,

<math>~\frac{ r_1^2}{\Delta_0^2} </math>

<math>~=</math>

<math>~1

-e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{\Delta_0^2}\biggr]

- \frac{\varpi_W R_c}{\Delta_0^2} \biggl[\frac{1}{2^2} e^4 + \frac{1}{2^3}e^6 + \frac{5}{2^6} e^8 + \mathcal{O}(e^{10}) \biggr] </math>

<math>~\Rightarrow ~~~ \frac{\Delta_0}{r_1} </math>

<math>~\approx</math>

<math>~ 1 + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr]

\, ,</math>       and we are defining <math>~\delta_K</math> such that,

<math>~K(k)</math>

<math>~=</math>

<math>~K(k_H) + \frac{\pi}{2} \cdot \delta_K \, .</math>


Hence,

<math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math>

<math>~\approx</math>

<math>~ \biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\} \biggl\{ 1 + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr] \biggr\}\biggl[1 + \biggl(\frac{5\cdot 13}{2^4\cdot 3} \biggr)e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} </math>

 

<math>~\approx</math>

<math>~ \boldsymbol{K}([k_H]_0) + \boldsymbol{K}(k_H) e^2 \cdot \mathcal{A} +~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot \varpi_W R_c}{ \Delta_0^4 } \biggr] \biggl\{ - R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] </math>

 

 

<math>~ +~(\varpi_W R_c + R_c^2 ) - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ] - R_c^2 - 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) </math>

 

 

<math>~ + \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ \Delta_0^2} \biggr\} \, , </math>

and,

<math>~\mathcal{A}</math>

<math>~\approx</math>

<math>~\biggl[ \frac{R_c(R_c + \varpi_W)}{2\Delta_0^2}\biggr] + \biggl( \frac{41}{2^4\cdot 3}\biggr) \, . </math>


Second,

<math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W1}}{GM} \biggr] </math>

<math>~=</math>

<math>~ \boldsymbol{E}(k) \biggl\{ \frac{\Delta_0 \cdot \cos\theta}{r_2} \biggr\} \biggl[ \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W1}(\eta_0) \biggr] </math>

 

<math>~=</math>

<math>~ \biggl\{ \boldsymbol{E}(k_H) + \frac{\pi}{2}\cdot \delta_E \biggr\} \biggl\{ \frac{\Delta_0 \cdot \cos\theta}{r_2} \biggr\} \biggl[- \biggl(\frac{11}{2\cdot 3} \biggr) e + \biggl(\frac{5}{2^5}\biggr) e^2 + \mathcal{O}(e^{5}) \biggr]\cdot (1 - e^2)^{1 / 2} \, . </math>

Geometric Factor

By definition,

<math>~\Delta_0^2</math>

<math>~=</math>

<math>~ (\varpi_W + R_c)^2 + z_W^2 \, , </math>

<math>~r_1^2</math>

<math>~=</math>

<math>~\biggl[ \varpi_W + R_c (1 - e^2 )^{1 / 2}\biggr]^2 + z_W^2 \, ,</math>

<math>~r_2^2</math>

<math>~=</math>

<math>~\biggl[ \varpi_W - R_c (1 - e^2 )^{1 / 2}\biggr]^2 + z_W^2 \, ,</math>

<math>~\cos^2\theta</math>

<math>~=</math>

<math>~\biggl[ \frac{r_1^2 + r_2^2 - 4R_c^2(1-e^2)}{2r_1 r_2} \biggr]^2 \, .</math>

Hence,

<math>~r_2^2 - \Delta_0^2 \cdot \cos^2\theta</math>

<math>~=</math>

<math>~</math>


Whitworth's (1981) Isothermal Free-Energy Surface

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